【DataStructure】Some useful methods for arrays
Last night it took me about two hours to learn arrays. For the sake of less time, I did not put emphaises on the practice question, just now when reading the book, I found that some methods
referred to arrays are so beneficial to us. So in here make a simple summary.
Method 1: Check whether the array is sorted.
private static boolean isSorted(int[] a) {
if (a.length < 2) {
return true;
}
for (int i = 1; i < a.length; i++) {
if (a[i] < a[i-1]) {
return false;
}
}
return true;
}
}
Method 2: Use the start number and range to init the array
public static void load(int[] a, int start, int range) {
for (int i = 0; i < a.length; i++) {
a[i] = start + random.nextInt(range); // random 5-digit numbers
}
}
Method 3: Get the min number from the array
private static int minimum(int[] a) {
int min = a[0];
for (int i = 1; i < a.length; i++) {
if (a[i] < min) {
min = a[i];
}
}
return min;
}
Method 4: Remove the duplicate elements from object
private static int[] withoutDuplicates(int[] a) {
int n = a.length;
if (n < 2) {
return a;
}
for (int i = 0; i < n-1; i++) {
for (int j = i+1; j < n; j++) {
if (a[j] == a[i]) {
--n;
System.arraycopy(a, j+1, a, j, n-j);
--j;
}
}
}
int[] aa = new int[n];
System.arraycopy(a, 0, aa, 0, n);
return aa;
}
Method 5: Finds the prime number according to certain range
private static final int SIZE=1000;
private static boolean[] isPrime = new boolean[SIZE]; private static void initializeSieve() {
for (int i = 2; i < SIZE; i++) {
isPrime[i] = true;
}
for (int n = 2; 2*n < SIZE; n++) {
if (isPrime[n]) {
for (int m = n; m*n <SIZE; m++) {
isPrime[m*n] = false;
}
}
}
}
Another way of implement the function of finding the prime number(Vector)
private static final int SIZE=1000;
private static Vector<Boolean> isPrime = new Vector<Boolean>(SIZE); private static void initializeSieve() {
isPrime.add(false); // 0 is not prime
isPrime.add(false); // 1 is not prime
for (int i = 2; i < SIZE; i++) {
isPrime.add(true);
}
for (int n = 2; 2*n < SIZE; n++) {
if ((isPrime.get(n))) {
for (int m = n; m*n < SIZE; m++) {
isPrime.set(m*n, false);
}
}
}
}
Another way of implement the function of finding the prime number(BitSet)
private static final int SIZE=1000;
private static BitSet isPrime = new BitSet(SIZE); private static void initializeSieve() {
for (int i = 2; i < SIZE; i++) {
isPrime.set(i);
}
for (int n = 2; 2*n < SIZE; n++) {
if (isPrime.get(n)) {
for (int m = n; m*n <SIZE; m++) {
isPrime.clear(m*n);
}
}
}
}
Method 6: Print out the result according to the certain format:
public static void printSieve() {
int n=0;
for (int i = 0; i < SIZE; i++) {
if (isPrime[i]) {
System.out.printf("%5d%s", i, ++n%16==0?"\n":"");
}
}
System.out.printf("%n%d primes less than %d%n", n, SIZE);
}
Notes: There exists five spaces between each number, and it will change line when the length of char % 6 is zero.
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53
59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131
137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223
227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311
313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409
419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503
509 521 523 541 547 557 563 569 571 577 587 593 599 601 607 613
617 619 631 641 643 647 653 659 661 673 677 683 691 701 709 719
727 733 739 743 751 757 761 769 773 787 797 809 811 821 823 827
829 839 853 857 859 863 877 881 883 887 907 911 919 929 937 941
947 953 967 971 977 983 991 997
【DataStructure】Some useful methods for arrays的更多相关文章
- 【DataStructure】Some useful methods about linkedList(二)
Method 1: Add one list into the other list. For example, if list1is {22, 33, 44, 55} and list2 is { ...
- 【DataStructure】Some useful methods about linkedList(三)
Method 4: Gets the value of element number i For example, if list is {22, 33, 44, 55, 66, 77, 88, 99 ...
- 【DataStructure】Some useful methods about linkedList.
/** * Method 1: Delete the input element x * and meanwhile keep the length of array after deleted n ...
- 【DataStructure】Description and usage of queue
[Description] A queue is a collection that implements the first-in-first-out protocal. This means th ...
- 【DataStructure】Description and Introduction of Tree
[Description] At ree is a nonlinear data structure that models a hierarchical organization. The char ...
- 【DataStructure】One of queue usage: Simulation System
Statements: This blog was written by me, but most of content is quoted from book[Data Structure wit ...
- 【DataStructure】The difference among methods addAll(),retainAll() and removeAll()
In the Java collection framework, there are three similar methods, addAll(),retainAll() and removeAl ...
- 【DataStructure】Charming usage of Set in the java
In an attempt to remove duplicate elements from list, I go to the lengths to take advantage of meth ...
- 【leetcode】Median of Two Sorted Arrays
题目简述: There are two sorted arrays A and B of size m and n respectively. Find the median of the two s ...
随机推荐
- Android_declare-styleable_自己定义控件的属性
1.简单实例 (1).在res/values文件下定义一个attrs.xml文件 <? xml version="1.0" encoding="utf-8" ...
- 浏览器被劫持到http://hao.169x.cn/?v=108的解决办法
不管什么浏览器打开都是 http://hao.169x.cn/?v=108 1.下载wmi tool,(微软官网下载,我的下载地址是: http://120.52.73.52/download.mi ...
- java程序开发代写(QQ:928900200)
条件:手机1.2都是安卓智能机,手机1开热点,手机2链接手机1,功能:A手机2通过刷手机网页,登陆手机1设定的页面并下载其手机的指定文件,B手机1控制手机2的流量,当通过的流量多的时候,停止流量的供应
- ExternalInterface的简单使用方法
ExternalInterface的简单使用方法 使用ExternalInterface调用JavaScript方法-无返回值flex代码------------------<mx:Button ...
- Java Web整合开发(79) -- Struts 2
一. Struts 2.x 概述 不继承任何类的Action Struts 2的Action并不一定要实现Action接口或者继承ActionSupport,任何POJO都可以做Action,只要这个 ...
- java实现大数相加问题
闲来没事.写了个acm中常常遇到的大数加减问题的java 解决代码,我想说.用java的BigInteger 非常easy. 大爱java!! 比如: 实现多组输入的大数加减问题: import ja ...
- Memcahce(MC)系列(两)Linux下一个Memcache安装
Linux下一个memcache安装 memcache是高性能.分布式的内存对象缓存系统,用于在动态应用中降低数据库负载.提升訪问速度.眼下用memcache解决互联网上的大用户读取是很流行的一种使用 ...
- uml 9图不同的角度品种分类
只要阅读uml视频后为其9一些模糊样图或理解.话又说回来后来他们自己的系统看着笔记,统的了解.以下分别从两个不同的角度对uml中9种图进行理解以及当中某些图的区分,本人比較菜,有些不完好的地方欢迎提出 ...
- NET5 Web应用程序
ASP.NET5 Web应用程序结构 本文参考ASP.NET5 官方文档 Understanding ASP.NET 5 Web Apps,加入了一些个人理解,理解不对的地方希望大家能指出,互相学习. ...
- HPUX在oracle10g安装和卸载缩写
创作品,出自 "深蓝的blog" 博客,欢迎转载,转载时请务必注明出处.否则追究版权法律责任. 深蓝的blog:http://blog.csdn.net/huangyanlong/ ...