题目:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

 struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {} };
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
{
if (l2 == NULL)
return l1;
if (l1 == NULL)
return l2;
ListNode *r, *head;
head = NULL;
if (l1->val <= l2->val) //哪个链表的第一个节点小就把头指针指向哪个节点
{
head = l1;
l1 = l1->next;
}
else
{
head = l2;
l2 = l2->next;
}
r = head;
while (l1&&l2) //比较大小
{
if (l1->val <= l2->val)
{
r->next = l1;
l1 = l1->next;
}
else
{
r->next = l2;
l2 = l2->next;
}
r = r->next;
}
if (l1 == NULL) //l1为空,直接连接l2
{
r->next = l2;
}
if (l2 == NULL) //l2为空,直接连接l1
{
r->next = l1;
}
return head;
}

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