UVa 1584 Circular Sequence(环形串最小字典序)
题意 给你一个环形串 输出它以某一位为起点顺时针得到串的最小字典序
直接模拟 每次后移一位比較字典序就可以 注意不能用strcpy(s+1,s)这样后移 strcpy复制地址不能有重叠部分
#include<cstdio>
#include<cstring>
using namespace std;
const int N = 150;
char s[N], ans[N], c;
int t, l; int main()
{
scanf ("%d", &t);
while (t--)
{
scanf ("%s", s);
l = strlen (s);
strcpy (ans, s);
for (int i = 0; i < l; ++i)
{
c = s[l - 1];
for (int j = l - 1; j >= 1 ; --j)
s[j] = s[j - 1];
s[0] = c;
if (strcmp (s, ans) < 0)
strcpy (ans, s);
}
printf ("%s\n", ans);
}
}
Some DNA sequences exist in circular forms as in the following figure, which shows a circular sequence ``CGAGTCAGCT", that is, the last symbol ``T" in ``CGAGTCAGCT" is connected to the first symbol ``C". We always read a circular sequence in the
clockwise direction.

Since it is not easy to store a circular sequence in a computer as it is, we decided to store it as a linear sequence. However, there can be many linear sequences that are obtained from a circular sequence by cutting any place of the circular sequence.
Hence, we also decided to store the linear sequence that is lexicographically smallest among all linear sequences that can be obtained from a circular sequence.
Your task is to find the lexicographically smallest sequence from a given circular sequence. For the example in the figure, the lexicographically smallest sequence is ``AGCTCGAGTC". If there are two or more linear sequences that are lexicographically
smallest, you are to find any one of them (in fact, they are the same).
Input
The input consists of T test cases. The number of test cases T is given on the first line of the input file. Each test case takes one line containing a circular sequence that
is written as an arbitrary linear sequence. Since the circular sequences are DNA sequences, only four symbols, A,C, G and T, are allowed. Each sequence has length at least 2 and at most 100.
Output
Print exactly one line for each test case. The line is to contain the lexicographically smallest sequence for the test case.
The following shows sample input and output for two test cases.
Sample
Input
2
CGAGTCAGCT
CTCC
Sample
Output
AGCTCGAGTC
CCCT
UVa 1584 Circular Sequence(环形串最小字典序)的更多相关文章
- UVa 1584 Circular Sequence --- 水题
UVa 1584 题目大意:给定一个含有n个字母的环状字符串,可从任意位置开始按顺时针读取n个字母,输出其中字典序最小的结果 解题思路:先利用模运算实现一个判定给定一个环状的串以及两个首字母位置,比较 ...
- uva 1584.Circular Sequence
题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem ...
- 字典序UVa 1584 Circular Sequence
#include <iostream> #include <algorithm> #include <cmath> #include <cstdio> ...
- UVa -1584 Circular Sequence 解题报告 - C语言
1.题目大意 输入长度为n$(2\le n\le 100)$的环状DNA串,找出该DNA串字典序最小的最小表示. 2.思路 这题特别简单,一一对比不同位置开始的字符串的字典序,更新result. 3. ...
- Circular Sequence,ACM/ICPC Seoul 2004,UVa 1584
#include <stdio.h> #include <string.h> #define maxn 105 int lss(const char *s,int p,int ...
- Circular Sequence UVA - 1584
Some DNA sequences exist in circular forms as in the following figure, which shows a circular sequ ...
- UVA.1584 环状序列
UVA.1584 环状序列 点我看题面 题意分析 给出你一段换装DNA序列,然后让你输出这段环状序列的字典序最小的序列情况. 字典序字面意思上理解就是按照字典编排的序列,其实也可以理解为按照ASCII ...
- 环状序列(Circular Sequence, ACM/ICPC Seoul 2004, UVa1584)
长度为n的环状串有n种表示法,分别为从某 个位置开始顺时针得到.例如,图3-4的环状串 有10种表示: CGAGTCAGCT,GAGTCAGCTC,AGTCAGCTCG等. 在这些表示法中,字典序最小 ...
- [ACM_模拟] ZJUT 1155 爱乐大街的门牌号 (规律 长为n的含k个逆序数的最小字典序)
Description ycc 喜欢古典音乐是一个 ZJUTACM 集训队中大家都知道的事情.为了更方便地聆听音乐,最近 ycc 特意把他的家搬到了爱乐大街(德语Philharmoniker-Stra ...
随机推荐
- jdbc 使用谨记
jdbc是java操作数据库的杀手锏.所有java程序员,对jdbc应该都不陌生. 但是,应该你也曾经被其折磨的抓耳挠腮,咬牙切齿吧,也许正因为这样你才对其记忆犹新,刻骨铭心. 这里有一些使用jdbc ...
- 在CentOS6,CentOS7安装 Let'sEncrypt 免费SSL安全证书
相对来说,个人网站建立SSL是昂贵的,而且往往过程繁琐.一个标准的2048位证书费用至少150美元/年,网站除了要支付一笔昂贵的费用.重新配置Web服务器,并需要解决大量的配置错误.这让广大中小网站望 ...
- (转)OL2中设置鼠标的样式
http://blog.csdn.net/gisshixisheng/article/details/49496289 概述: 在OL2中,鼠标默认是箭头,地图移动时,鼠标样式是移动样式:很多时候,为 ...
- (转)Struts2快速入门
http://blog.csdn.net/yerenyuan_pku/article/details/66187307 Struts2框架的概述 Struts2是一种基于MVC模式的轻量级Web框架, ...
- registerDataSetObserver:浅析Andorid ListView和Adapte
最近由于遇到将内容分部绑定到ListView里的需求,追踪源码之后对ListView和Adapter有了点肤浅的认识,在此与大家分享. 这里用到了观察者模式,在ListView的setAdapter里 ...
- day13-迭代器、三元表达式、列表推导式、字典生成式、生成器与递归
目录 迭代器 可迭代对象 迭代器对象 for循环原理 三元表达式(三目表达式) 列表推导式 字典生成式 zip()方法 生成器 生成器表达式 递归 递归的两个阶段 迭代器 迭代器即迭代的工具,迭代是一 ...
- 所有对象的父类(java.lang.Object)
一.介绍 Object类是类层次结构的根源,每一个类都存在一个父类为Object类.所有的对象,包括数组,都实现了 Object 类的方法. 二.对象初始化 这里使用了静态代码块进行Object类的初 ...
- C/C++ 中野指针产生的问题
野指针产生的问题: 野指针的定义: > 野指针是指:指向一个已删除的对象或未申请访问受限内存区域的指针.与空指针不同,野指针无法通过简单地判断是否为NULL避免,而只能通过养成良好的编程习惯来尽 ...
- CentOS 7.2安装配置Vsftp服务器
一.配置防火墙,开启FTP服务器需要的端口 CentOS 7.2默认使用的是firewall作为防火墙,这里改为iptables防火墙. 1.关闭firewall: systemctl stop fi ...
- NFA到DFA实例
下面图使用NFA表示的状态转换图, 使用子集构造法,有如下过程, ε-closure(0) = {0, 1, 2, 3, 4, 6, 7}初始值,令为AA = {0, 1, 2, 3, 4, 6, 7 ...