Description

To stay woke and attentive(专注的) during classes, Karen needs some coffee!

Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading several recipe books, including the universally acclaimed "The Art of the Covfefe".

She knows n coffee recipes. The i-th recipe suggests that coffee should be brewed between li and ri degrees, inclusive, to achieve the optimal taste.

Karen thinks that a temperature is admissible if at least k recipes recommend it.

Karen has a rather fickle mind, and so she asks q questions. In each question, given that she only wants to prepare coffee with a temperature between a and b, inclusive, can you tell her how many admissible integer temperatures fall within the range?

Input

The first line of input contains three integers, nk (1 ≤ k ≤ n ≤ 200000), and q (1 ≤ q ≤ 200000), the number of recipes, the minimum number of recipes a certain temperature must be recommended by to be admissible, and the number of questions Karen has, respectively.

The next n lines describe the recipes. Specifically, the i-th line among these contains two integers li and ri (1 ≤ li ≤ ri ≤ 200000), describing that the i-th recipe suggests that the coffee be brewed between li and ri degrees, inclusive.

The next q lines describe the questions. Each of these lines contains a and b, (1 ≤ a ≤ b ≤ 200000), describing that she wants to know the number of admissible integer temperatures between a and b degrees, inclusive.

Output

For each question, output a single integer on a line by itself, the number of admissible(容许的) integer temperatures between a and b degrees, inclusive.

Sample Input

Input
3 2 4
91 94
92 97
97 99
92 94
93 97
95 96
90 100
Output
3
3
0
4
Input
2 1 1
1 1
200000 200000
90 100
Output
0

Hint

In the first test case, Karen knows 3 recipes.

  1. The first one recommends brewing the coffee between 91 and 94 degrees, inclusive.
  2. The second one recommends brewing the coffee between 92 and 97 degrees, inclusive.
  3. The third one recommends brewing the coffee between 97 and 99 degrees, inclusive.

A temperature is admissible if at least 2 recipes recommend it.

She asks 4 questions.

In her first question, she wants to know the number of admissible integer temperatures between 92 and 94 degrees, inclusive. There are 3: 92, 93 and 94 degrees are all admissible.

In her second question, she wants to know the number of admissible integer temperatures between 93 and 97 degrees, inclusive. There are 3: 93, 94 and 97 degrees are all admissible.

In her third question, she wants to know the number of admissible integer temperatures between 95 and 96 degrees, inclusive. There are none.

In her final question, she wants to know the number of admissible integer temperatures between 90 and 100 degrees, inclusive. There are 4: 92, 93, 94 and 97 degrees are all admissible.

In the second test case, Karen knows 2 recipes.

  1. The first one, "wikiHow to make Cold Brew Coffee", recommends brewing the coffee at exactly 1 degree.
  2. The second one, "What good is coffee that isn't brewed at at least 36.3306 times the temperature of the surface of the sun?", recommends brewing the coffee at exactly 200000 degrees.

A temperature is admissible if at least 1 recipe recommends it.

In her first and only question, she wants to know the number of admissible integer temperatures that are actually reasonable. There are none.

题目意思:女主为了得到最好的泡咖啡的温度,看了n本书,n本书推荐了n种的适合范围,她想要查询q次,a~b温度范围内有多少个温度是可以允许泡咖啡的时间(这个时间要求至少有k本数推荐过)。

解题思路:当时没有做到这一道题。。。。总的来说这一道题使用前缀和来做,这道题是不是有点像给气球刷颜色的那一类题。

N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到气球b依次给每个气球涂一次颜色。但是N次以后lele已经忘记了第I个气球已经涂过几次颜色了,你能帮他算出每个气球被涂过几次颜色吗?
 
当时数据在做这一类题的时候,限于数据量的因素,使用了树状数字或者线段树这样的数据结构,这里就可以不去使用了。
 
 #include<cstdio>
#include<cstring>
#include<algorithm>
#define maxs 200010
using namespace std;
int n,k,q;
int a[maxs];
int sum[maxs];
int main()
{
int i,r,l;
scanf("%d%d%d",&n,&k,&q);
for(i=;i<n;i++)
{
scanf("%d%d",&l,&r);
a[l]++;
a[r+]--;
}
for(i=;i<maxs;i++)
{
a[i]+=a[i-];
if(a[i]>=k)///满足至少有k本书推荐
{
sum[i]++;
}
}
for(i=;i<maxs;i++)
{
sum[i]+=sum[i-];
}
for(i=;i<q;i++)
{
scanf("%d%d",&l,&r);
printf("%d\n",sum[r]-sum[l-]);
}
return ;
}

Karen and Coffee CF 816B(前缀和)的更多相关文章

  1. Karen and Coffee CodeForces - 816B (差分数组+预处理前缀和)

    To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...

  2. Codeforces Round #419 (Div. 2) B. Karen and Coffee(经典前缀和)

    http://codeforces.com/contest/816/problem/B To stay woke and attentive during classes, Karen needs s ...

  3. CF 816B Karen and Coffee【前缀和/差分】

    To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...

  4. CodeForces 816B Karen and Coffee(前缀和,大量查询)

    CodeForces 816B Karen and Coffee(前缀和,大量查询) Description Karen, a coffee aficionado, wants to know the ...

  5. 816B. Karen and Coffee 前缀和思维 或 线段树

    LINK 题意:给出n个[l,r],q个询问a,b,问被包含于[a,b]且这样的区间数大于k个的方案数有多少 思路:预处理所有的区间,对于一个区间我们标记其(左边界)++,(右边界+1)--这样就能通 ...

  6. codeforces 816B Karen and Coffee (差分思想)

    题目链接 816B Karen and Coffee 题目分析 题意:有个人在学泡咖啡,因此看了很多关于泡咖啡温度的书,得到了n种推荐的泡咖啡温度范围[L1,R1] ,此人将有k种做法推荐的温度记为可 ...

  7. Codeforces Round #419 (Div. 2) B. Karen and Coffee

    To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...

  8. Codeforces816B Karen and Coffee 2017-06-27 15:18 39人阅读 评论(0) 收藏

    B. Karen and Coffee time limit per test 2.5 seconds memory limit per test 512 megabytes input standa ...

  9. CodeForces 816B 前缀和

    To stay woke and attentive during classes, Karen needs some coffee! Karen, a coffee aficionado, want ...

随机推荐

  1. 一次tomcat的调优记录

    项目本身需要上传模型,使用的是springboot1.5.3. 上传的模型比较大,下载的过程中就出现了问题(下载是su调用的java接口,其开发并非本人负责,不可更改) 问题在于,下载的时候tomca ...

  2. eclipse的git插件安装、配置与使用

    Git是一个分布式的版本控制工具,本篇文章从介绍Git开始,重点在于介绍Git的基本命令和使用技巧,让你尝试使用Git的同时,体验到原来一个版 本控制工具可以对开发产生如此之多的影响,文章分为两部分, ...

  3. 用JavaScript获取URL参数的方法之一

    若地址栏URL为:abc.html?m=tomms&c=allsearchlist&pageNo=1&pageNum=20&text=1 <script> ...

  4. java日常规范

    1.方法返回类型用int还是Integer 看需求,int是数据类型,不能包含null等. Integer是类,其中包含该类中属性和方法,包含null. 所以建议使用Integer,方便以后拓展. 2 ...

  5. 我的 Delphi 学习之路 —— Delphi 的安装

    标题:我的 Delphi 学习之路 -- Delphi 的安装 作者:断桥烟雨旧人伤 1. Delphi 版本的选择 Delphi 版本众多,我该选择哪一个,这确实是个问题,自从 Borland 公司 ...

  6. C++的一些关键字用法

    const 这个关键字真是太常用了, 所以干脆总结一下. int const a = 8; //定义一个int常量a, 不能再给a赋值了 const int a = 8; //和上面一样 int co ...

  7. BurpSuite—-Scanner模块(漏洞扫描)

    一.简介 Burp Scanner 是一个进行自动发现 web 应用程序的安全漏洞的工具.它是为渗透测试人员设计的,并且它和你现有的手动执行进行的 web 应用程序半自动渗透测试的技术方法很相似. 使 ...

  8. sublime install package没反应,以及安装后没有出现install package选项

    离线安装Package Control 一般出现这种问题的是网络原因,我们可以下载离线安装包 连接地址:https://github.com/wbond/package_control 安装完成后解压 ...

  9. 学习Emmet

    学习Emmet 在进行Web开发时,就免不了需要编写html文件,如何快速(偷懒^-^)的进行编写html,是个大问题,上网找了一下,发现了一个好东西 ,视频教程可以看下小马技术Emmet爆速开发, ...

  10. [POJ1741]Tree(点分治)

    树分治之点分治入门 所谓点分治,就是对于树针对点的分治处理 首先找出重心以保证时间复杂度 然后递归处理所有子树 对于这道题,对于点对(u,v)满足dis(u,v)<=k,分2种情况 路径过当前根 ...