[SHOI 2009] 会场预约

[题目链接]

https://www.lydsy.com/JudgeOnline/problem.php?id=2028

[算法]

直接用std :: set维护即可

时间复杂度 ： O(NlogN)

[代码]

#include<bits/stdc++.h>
using namespace std;

int n;

struct segment
{
        int l , r;
        friend bool operator < (segment a , segment b)
        {
                if (a.r == b.r) return a.l < b.l;
                else return a.r < b.r;
        }
} ;

template <typename T> inline void chkmax(T &x,T y) { x = max(x,y); }
template <typename T> inline void chkmin(T &x,T y) { x = min(x,y); }
template <typename T> inline void read(T &x)
{
    T f = ; x = ;
    char c = getchar();
    for (; !isdigit(c); c = getchar()) if (c == '-') f = -f;
    for (; isdigit(c); c = getchar()) x = (x << ) + (x << ) + c - '';
    x *= f;
}
int main()
{

        scanf("%d" , &n);
        set< segment > S;
        for (int i = ; i <= n; i++)
        {
                char type[];
                scanf("%s" , &type);
                if (type[] == 'B')
                {
                        printf("%d\n" , (int)S.size());
                        continue;
                } else
                {
                        int ans = ;
                        int l , r;
                        scanf("%d%d" , &l , &r);
                        while (true)
                        {
                                set< segment > :: iterator it = S.lower_bound((segment){ , l});
                                if (it == S.end()) break;
                                segment tmp = (*it);
                                if (tmp.l <= r)
                                {
                                        S.erase(it);
                                        ++ans;
                                } else break;
                        }
                        printf("%d\n" , ans);
                        S.insert((segment){l , r});
                }
        }

        return ;

}