Design a HashMap without using any built-in hash table libraries.

To be specific, your design should include these functions:

  • put(key, value) : Insert a (key, value) pair into the HashMap. If the value already exists in the HashMap, update the value.
  • get(key): Returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
  • remove(key) : Remove the mapping for the value key if this map contains the mapping for the key.

Example:

MyHashMap hashMap = new MyHashMap();
hashMap.put(1, 1);          
hashMap.put(2, 2);        
hashMap.get(1);            // returns 1
hashMap.get(3);            // returns -1 (not found)
hashMap.put(2, 1);          // update the existing value
hashMap.get(2);            // returns 1
hashMap.remove(2);          // remove the mapping for 2
hashMap.get(2);            // returns -1 (not found)
 class MyHashMap {
final ListNode[] nodes = new ListNode[]; public void put(int key, int value) {
int i = idx(key);
ListNode first = nodes[i];
ListNode newNode = new ListNode(key, value);
if (first == null) {
nodes[i] = newNode;
} else {
ListNode sameNode = find(nodes[i], key);
if (sameNode == null) {
newNode.next = first;
nodes[i] = newNode;
} else {
sameNode.val = value;
}
}
} public int get(int key) {
int i = idx(key);
if (nodes[i] == null) {
return -;
}
ListNode node = find(nodes[i], key);
return node == null ? - : node.val;
} public void remove(int key) {
int i = idx(key);
if (nodes[i] == null) {
return;
}
ListNode current = nodes[i];
ListNode previous = null;
while (current != null) {
if (current.key == key) {
if (previous != null) {
previous.next = current.next;
} else {
nodes[i] = current.next;
}
break;
} else {
previous = current;
current = current.next;
}
}
} int idx(int key) {
return Integer.hashCode(key) % nodes.length;
} ListNode find(ListNode node, int key) {
while (node != null) {
if (node.key == key) {
return node;
}
node = node.next;
}
return null;
} class ListNode {
int key, val;
ListNode next; ListNode(int key, int val) {
this.key = key;
this.val = val;
}
}
}
												

Design HashMap的更多相关文章

  1. 【Leetcode_easy】706. Design HashMap

    problem 706. Design HashMap solution1: class MyHashMap { public: /** Initialize your data structure ...

  2. Leetcode PHP题解--D75 706. Design HashMap

    2019独角兽企业重金招聘Python工程师标准>>> D75 706. Design HashMap 题目链接 706. Design HashMap 题目分析 自行设计一个has ...

  3. 706. Design HashMap - LeetCode

    Question 706. Design HashMap Solution 题目大意:构造一个hashmap 思路:讨个巧,只要求key是int,哈希函数选择f(x)=x,规定key最大为100000 ...

  4. [leetcode] 706. Design HashMap

    题目 Design a HashMap without using any built-in hash table libraries. Implement the MyHashMap class: ...

  5. [Swift]LeetCode706. 设计哈希映射 | Design HashMap

    Design a HashMap without using any built-in hash table libraries. To be specific, your design should ...

  6. [LeetCode] Design HashMap 设计HashMap

    Design a HashMap without using any built-in hash table libraries. To be specific, your design should ...

  7. LeetCode 706 Design HashMap 解题报告

    题目要求 Design a HashMap without using any built-in hash table libraries. To be specific, your design s ...

  8. [LeetCode&Python] Problem 706. Design HashMap

    Design a HashMap without using any built-in hash table libraries. To be specific, your design should ...

  9. LeetCode 706:设计哈希映射 Design HashMap

    题目: 不使用任何内建的哈希表库设计一个哈希映射 具体地说,你的设计应该包含以下的功能 put(key, value):向哈希映射中插入(键,值)的数值对.如果键对应的值已经存在,更新这个值. get ...

随机推荐

  1. kubernetes Configmap secret的使用

    kubernetes configmap 核心作用是让配置信息和镜像解耦,pod可以使用configmap的数据生成配置文件.如果后端的pod配置文件要改变时,只需要更改下configmap里面的数据 ...

  2. Prime Path (POJ - 3126 )(BFS)

    转载请注明出处:https://blog.csdn.net/Mercury_Lc/article/details/82697622     作者:Mercury_Lc 题目链接 题意:就是给你一个n, ...

  3. ie8中如何使用base64

    由于ie8中不能使用jQuery2.0以上版本所以无法使用 window.btoa()加密 window.atob()解密 所以只能使用最原生的base64加密方法如下: /** * Created ...

  4. 求两个排序数组的交集和并集----时间复杂度O(n+m)

    问题: 给你两个排序的数组,求两个数组的交集. 比如: A = 1 3 4 5 7, B = 2 3 5 8 9, 那么交集就是 3 5,n是a数组大小,m是b数组大小. 思路: (1)从b数组遍历取 ...

  5. Nginx之最简单的反向代理机制分析

    注:当前分析基于 Nginx之搭建反向代理实现tomcat分布式集群 的配置. 1. 用到的指令 下面介绍在上面的配置中用到的指令. upstream 指令 语法:upstream name { .. ...

  6. C# Read/Write another Process' Memory

    https://codingvision.net/security/c-read-write-another-process-memory Today’s tutorial is about…proc ...

  7. CentOS 上 Jenkins 的安装

    Jenkins 的前身是 Hudson. Jenkins 是一款开源 CI&CD 软件,用于自动化各种任务,包括构建.测试和部署软件. Jenkins 支持各种运行方式,可通过系统包.Dock ...

  8. 数据结构之链表(Linked list)

    1, 无序链表(Unordered linked list) 链表是有若干个数据节点依次链接成的数据结构,如下图所示,每一个数据节点包括包括数据和一个指向下一节点的指针.(python中的list就是 ...

  9. PCL已有点类型介绍和增加自定义的点类型

    博客转载自:http://www.pclcn.org/study/shownews.php?lang=cn&id=265 本小节不仅解释如何增加你自己的PointT点类型,也介绍了PCL中的模 ...

  10. RabbitMQ学习之:(五)Exchange Type (转贴+我的评论)

    From: http://lostechies.com/derekgreer/2012/03/28/rabbitmq-for-windows-exchange-types/ RabbitMQ for ...