PAT (Advanced Level) 1096. Consecutive Factors (20)
如果是素数直接输出1与素数,否则枚举长度和起始数即可。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std; long long n; bool prime(long long x)
{
if(x==) return ;
if(x==) return ;
for(long long i=; i*i<=x; i++)
{
if(x%i==) return ;
}
return ;
} int main()
{
scanf("%lld",&n);
int f=; if(prime(n))
{
printf("1\n");
printf("%lld\n",n);
}
else
{
for(int len=; len>=; len--)
{
long long num=;
for(long long i=;; i++)
{
if(i==)
{
for(long long j=i; j<=i+(long long)len-; j++)
{
num=num*j;
if(num>n) break;
}
}
else num=num/(i-)*(i+len-); if(num>n) break;
if(n%num==)
{
f=;
printf("%d\n",len);
for(long long j=i; j<=i+len-; j++)
{
printf("%lld",j);
if(j<i+len-) printf("*");
}
printf("\n");
break;
}
}
if(f==) break;
}
}
return ;
}
PAT (Advanced Level) 1096. Consecutive Factors (20)的更多相关文章
- 【PAT甲级】1096 Consecutive Factors (20 分)
题意: 输入一个int范围内的正整数,输出它最多可以被分解为多少个连续的因子并输出这些因子以*连接. trick: 测试点5包含N本身是一个素数的数据,此时应当输出1并把N输出. 测试点5包含一个2e ...
- PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642
PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge someti ...
- PAT (Advanced Level) Practice 1008 Elevator (20 分) 凌宸1642
PAT (Advanced Level) Practice 1008 Elevator (20 分) 凌宸1642 题目描述: The highest building in our city has ...
- PAT (Advanced Level) Practise - 1096. Consecutive Factors (20)
http://www.patest.cn/contests/pat-a-practise/1096 Among all the factors of a positive integer N, the ...
- PAT Advanced 1096 Consecutive Factors (20) [数学问题-因子分解 逻辑题]
题目 Among all the factors of a positive integer N, there may exist several consecutive numbers. For e ...
- 1096. Consecutive Factors (20)
Among all the factors of a positive integer N, there may exist several consecutive numbers. For exam ...
- PAT甲题题解-1096. Consecutive Factors(20)-(枚举)
题意:一个正整数n可以分解成一系列因子的乘积,其中会存在连续的因子相乘,如630=3*5*6*7,5*6*7即为连续的因子.给定n,让你求最大的连续因子个数,并且输出其中最小的连续序列. 比如一个数可 ...
- PAT (Advanced Level) Practice 1035 Password (20 分)
To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem ...
- 【PAT Advanced Level】1008. Elevator (20)
没什么难的,简单模拟题 #include <iostream> using namespace std; int main() { int num; cin>>num; int ...
随机推荐
- windows xp sp3 下载地址
windows xp service pack 3/ windows xp sp3 简体中文版下载地址: http://download.windowsupdate.com/msdownload/ ...
- sql注入绕过union select过滤
# # # #WAF Bypassing Strings: /*!%55NiOn*/ /*!%53eLEct*/ ,,)-- - +union+distinct+select+ +union+dist ...
- Python基础篇-day3
主要内容:字典 集合 文件处理 字符编码 1.字典dict简介dict就是key value值,索引有意义,数据无序 key定义规则:a:不可变--数字.字符串.元组(可变--列表.字典)b:不能重复 ...
- yaf for ubuntu安装
一.安装yaf需要的扩展 apt-get install perl-modules apt-get install libpcrecpp0 apt-get install libpcre3 libpc ...
- 创建简单动画(一) --- 常规hud
先说下当前我为处理动画的思路: (新手上路, 老司机轻喷,如果有更好的实现方法请大神指教 感恩戴德) #1. 分析动画构成 #2. 如果是位移动画则考虑使用BasicAnimation或者Keyfra ...
- 二〇一五年五月二十二日--bug--启动页面出现模糊的问题
启动页面出现模糊的问题: 原因是 :android:theme="@style/TranslucentTheme" <application android:name=&qu ...
- hdu_1115_Lifting the Stone(求多边形重心)
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1115 题意:给你N个点围成的一个多边形,让你求这个多边形的重心. 题解: 将多边形划分为若干个三角形. ...
- debian下安装repo
1.去google网站上下载repo脚本(用php语言写成的脚本) https://gerrit.googlesource.com/git-repo/+/stable/repo 可以将脚本复制下来并保 ...
- Lowest Bit
Lowest Bit Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Su ...
- WisKey的眼神
WisKey的眼神 Time Limit : 1000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Sub ...