ACfun




Time Limit: 2000/1000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others)

Problem Description

As a former ACMer, "AC" is a special abbreviated word which can bring much pleasure to me. Sometimes it means everything.

This problem is about "AC".

One day, I write a long string S on the paper which contains "A" and "C". Now I want to find a lexicographic minimum string T satisfied that T is distinct with all substring of S.

Input

The first line of input file contains an integer T indicating the number of case.

In each test case:

Input a string S consist of "A" and "C". The length of S is not large than 100.

Output

For each test case:

You should output the string T meet the condition.

Sample Input

1
ACAC

Sample Output

AA

题意是要输出最小的字典序。且不是原字符串的的子串。。找到最长连续A子串。

由于要不属于原字符串所以再在其后加一A就可以。

在给些数据吧。

5

A

C

AACAAA

ACACA

CCCAA

AA

A

AAAA

AA

AAA

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<vector>
#include<queue> using namespace std; int main()
{
char str[108];
int ans;
int t;
scanf("%d", &t);
while( t-- )
{
scanf("%s", str);
int num=0;
ans=0;
for(int i=0; i<strlen(str); i++)
{
if(str[i]=='A')
num++;
for(int j=i+1; j<strlen(str); j++)
{
if(str[j]=='A')
num++;
if(str[j]!='A')
break;
}
if(ans<num)
ans=num;
num=0;
}
for(int i=1; i<=ans+1; i++)
cout<<"A";
cout<<endl;
} return 0;
}

版权声明:本文博主原创文章,博客,未经同意不得转载。

ACdream: ACfun的更多相关文章

  1. ACdream 之ACfun 题解

    A - ACfun Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) SubmitSta ...

  2. ACdream 1214---矩阵连乘

    ACdream 1214---矩阵连乘 Problem Description You might have noticed that there is the new fashion among r ...

  3. acdream.LCM Challenge(数学推导)

     LCM Challenge Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit ...

  4. acdream.Triangles(数学推导)

    Triangles Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Stat ...

  5. acdream.A Very Easy Triangle Counting Game(数学推导)

    A - A Very Easy Triangle Counting Game Time Limit:1000MS     Memory Limit:64000KB     64bit IO Forma ...

  6. acdream.Bet(数学推导)

    Bet Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Pra ...

  7. acdream.郭式树(数学推导)

    郭式树 Time Limit:2000MS     Memory Limit:128000KB     64bit IO Format:%lld & %llu Submit Status Pr ...

  8. ACdream 1188 Read Phone Number (字符串大模拟)

    Read Phone Number Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Sub ...

  9. ACdream 1195 Sudoku Checker (数独)

    Sudoku Checker Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit ...

随机推荐

  1. poj 1659 Frogs&#39; Neighborhood (度序列)

    Frogs' Neighborhood Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 7295   Accepted: 31 ...

  2. 2-13. 平均两个有序序列(25)(ZJU_PAT 名单 | 排列 )

    主题链接:http://pat.zju.edu.cn/contests/ds/2-13 已知有两个等长的非降序序列S1, S2, 设计函数求S1与S2并集的中位数.有序序列A0, A1-AN-1的中位 ...

  3. struts2第一个程序的详解(配图)

    首先我们在struts2中要写上一个action <packagename="fish"namespace="/test"extends="st ...

  4. cisco san交换机配置

    1.配置交换机的管理地址switch(config)# interface mgmt 0 switch(config-if)# ip adress 192.168.100.108 255.255.25 ...

  5. Python的控制结构(转)

    首先我的工作第一语言是c/c++(面向对象子集).选择学习python一方面是因为看很多人都说python开发效率高,所以想验证一下:另一方面,Eric S. Raymond在文章:如何成为一名黑客 ...

  6. U14Linux的帐号与用户组

    1.在/etc/group和/etc/gshadow中查找mousegroup: grep mousegroup /etc/group /etc/gshadow (grep的使用) 2.其实Linux ...

  7. 也说Javascript对象拷贝及疑问

    一.浅拷贝 当我们需要将一个对象拷贝至另一个对象时,我们一般会这么实现 function shadowCopy(source,target){ var target=target||{}; for(v ...

  8. java 类 及其 执行过程

    java 类 命名 java类文件中  只能有一个公开类  且 公开类类名与当前类文件的文件名一致 方法如果使用了static修饰,那么此方法是类方法,可以 类名.方法名 使用. 你的main方法在同 ...

  9. 在TextView中加入图片

    TextView是一个非常强大的控件,有时须要在一个控件中同一时候显示图片和文字,使用TextView非常easy实现. 方法一: 聊天软件比方QQ一般都会有发送表情的功能,使用SpannableSt ...

  10. DLNA它 Error, can&#39;t findlibavformat ! 解

    DLNA库版本号为libdlna-0.2.4 运行./configure出错: ------------------------------ Error, can't findlibavformat ...