Food on the Plane
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

A new airplane SuperPuperJet has an infinite number of rows, numbered with positive integers starting with 1 from cockpit to tail. There are six seats in each row, denoted with letters from 'a' to 'f'. Seats 'a', 'b' and 'c' are located to the left of an aisle (if one looks in the direction of the cockpit), while seats 'd', 'e' and 'f' are located to the right. Seats 'a' and 'f' are located near the windows, while seats 'c' and 'd' are located near the aisle.

It's lunch time and two flight attendants have just started to serve food. They move from the first rows to the tail, always maintaining a distance of two rows from each other because of the food trolley. Thus, at the beginning the first attendant serves row 1 while the second attendant serves row 3. When both rows are done they move one row forward: the first attendant serves row 2 while the second attendant serves row 4. Then they move three rows forward and the first attendant serves row 5 while the second attendant serves row7. Then they move one row forward again and so on.

Flight attendants work with the same speed: it takes exactly 1 second to serve one passenger and 1 second to move one row forward. Each attendant first serves the passengers on the seats to the right of the aisle and then serves passengers on the seats to the left of the aisle (if one looks in the direction of the cockpit). Moreover, they always serve passengers in order from the window to the aisle. Thus, the first passenger to receive food in each row is located in seat 'f', and the last one — in seat 'c'. Assume that all seats are occupied.

Vasya has seat s in row n and wants to know how many seconds will pass before he gets his lunch.

Input

The only line of input contains a description of Vasya's seat in the format ns, where n (1 ≤ n ≤ 1018) is the index of the row and s is the seat in this row, denoted as letter from 'a' to 'f'. The index of the row and the seat are not separated by a space.

Output

Print one integer — the number of seconds Vasya has to wait until he gets his lunch.

Examples
input
1f
output
1
input
2d
output
10
input
4a
output
11
input
5e
output
18
Note

In the first sample, the first flight attendant serves Vasya first, so Vasya gets his lunch after 1 second.

In the second sample, the flight attendants will spend 6 seconds to serve everyone in the rows 1 and 3, then they will move one row forward in 1 second. As they first serve seats located to the right of the aisle in order from window to aisle, Vasya has to wait 3 more seconds. The total is 6 + 1 + 3 = 10.

分析:模拟即可;

代码:

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <unordered_map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define mod 1000000007
#define inf 0x3f3f3f3f
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
#define pii pair<int,int>
#define Lson L, mid, ls[rt]
#define Rson mid+1, R, rs[rt]
#define sys system("pause")
const int maxn=2e5+;
using namespace std;
ll gcd(ll p,ll q){return q==?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=;while(q){if(q&)f=f*p;p=p*p;q>>=;}return f;}
inline ll read()
{
ll x=;int f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
int n,m,k,t;
char a[],x;
ll num;
string node="fedabc";
int main()
{
int i,j;
scanf("%s",a);
for(i=;a[i]>=''&&a[i]<='';i++)num=num*+a[i]-'';
x=a[i];
ll b=(num-)/,c=num&^,ans=;
for(i=;node[i]!=x;i++);
ans+=i+;
ans+=b*;
if(c)ans+=;
cout<<ans<<endl;
//system("Pause");
return ;
}

Food on the Plane的更多相关文章

  1. 数据的平面拟合 Plane Fitting

    数据的平面拟合 Plane Fitting 看到了一些利用Matlab的平面拟合程序 http://www.ilovematlab.cn/thread-220252-1-1.html

  2. quad 和 plane 区别是什么?

    Quad就是两个三角形组成四边形,Plane会有很多三角形,哦也 貌似Quad拖上去后看不见,很薄的感觉

  3. u3d单词学习plane

    plane n.水平: 平面: 飞机: 木工刨

  4. 【转载】PMC/PEC Boundary Conditions and Plane Wave Simulation

    原文链接 PMC/PEC Boundary Conditions and Plane Wave Simulation (FDTD) OptiFDTD now has options to use Pe ...

  5. codeforces 577E E. Points on Plane(构造+分块)

    题目链接: E. Points on Plane time limit per test 2 seconds memory limit per test 256 megabytes input sta ...

  6. Data Plane Development Kit (DPDK): Getting Started

    参考:dpdk getting started 系统: Ubuntu 14.04 内核信息: 执行 uname -a Linux chen-VirtualBox 3.13.0-32-generic # ...

  7. Codeforces Round #115 B. Plane of Tanks: Pro 水题

    B. Plane of Tanks: Pro Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/17 ...

  8. B - Plane of Tanks: Pro

    Description Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to ...

  9. Codeforces Round #319 (Div. 1) C. Points on Plane 分块

    C. Points on Plane Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/576/pro ...

  10. yuv 图像里的stride和plane的解释

    stride可以翻译为:跨距 stride指在内存中每行像素所占的空间.如下图所示,为了实现内存对齐(或者其它的什么原因),每行像素在内存中所占的空间并不是图像的宽度. plane一般是以luma p ...

随机推荐

  1. 【LeetCode】456. 132 Pattern

    Given a sequence of n integers a1, a2, ..., an, a 132 pattern is a subsequence ai, aj, ak such that  ...

  2. ElasticSearch(5)-Mapping

    一.Mapping概述 映射 为了能够把日期字段处理成日期,把数字字段处理成数字,把字符串字段处理成全文本(Full-text)或精确的字符串值,Elasticsearch需要知道每个字段里面都包含了 ...

  3. LeetCode OJ 209. Minimum Size Subarray Sum

    Given an array of n positive integers and a positive integer s, find the minimal length of a subarra ...

  4. poj 1687 Buggy Sat 简单计算几何

    暑期集训出的第一道一血 感觉自己萌萌哒…… 这道题本身并没有坑点 仅仅是翻译巨坑…… 解大腿在做B 安学长在做E 我闲着也没事 就一个词一个词翻译F…… 最后感觉…… 题干大多数都看不懂…… 也都没啥 ...

  5. hdu 2546 饭卡 (01背包)

    Problem Description 电子科大本部食堂的饭卡有一种很诡异的设计,即在购买之前判断余额.如果购买一个商品之前,卡上的剩余金额大于或等于5元,就一定可以购买成功(即使购买后卡上余额为负) ...

  6. Digital Ocean VS. Linode对比评测

    美国攻城师Zach Schneider是linode vps资深用户,他最近却转向了Digital Ocean,原因是什么呢?来看这篇digitalocean linode对比评测的文章: 用了两年的 ...

  7. urllib2 之info 学习

    之前介绍了根据old_url获取真实url的geturl的方法,而根据urlopen返回的应答对象的info方法可以获取服务器发送头部headers的内容,并且通过字典形式反馈出来,同样测试代码如下: ...

  8. Openjudge-计算概论(A)-回文串判断

    描述: 任意给定一个非空的字符串,判断其是否是回文串.回文串是指正向看和反向看均相等的串,如AbcDcbA和cDDc.如果是回文串,则输出1,否则,输出0 输入长度不小于1不大于100的字符串输出如果 ...

  9. 【笔记】Loadrunner添加OS类型为Linux的服务器

    参考文章:http://www.51testing.com/?uid-145985-action-spacelist-type-blog-itemtypeid-11954 在给Loadrunner添加 ...

  10. protected-broadcast的作用

    protected-broadcast(暂时从网上搜到这么多,也不知对错,先留着) “保护性广播”,在一些AndroidManifest.xml中的一级标记<protected-broadcas ...