POJ 2121

http://poj.org/problem?id=2121

一道字符串的转换的题目。

题意：就是把那个英文数字翻译成中文。

思路：首先打表，然后把每一个单独的单词分离出来，在组合相加相乘。

 #include <stdio.h>
 #include <string.h>

 struct trans{
     char eng[];
     int num;
 }s[];

 int main(){
 //    freopen("in.txt","r",stdin);
     strcpy(s[].eng,"zero"),      s[].num = ;
     strcpy(s[].eng,"one"),       s[].num = ;
     strcpy(s[].eng,"two"),       s[].num = ;
     strcpy(s[].eng,"three"),     s[].num = ;
     strcpy(s[].eng,"four"),      s[].num = ;
     strcpy(s[].eng,"five"),      s[].num = ;
     strcpy(s[].eng,"six"),       s[].num = ;
     strcpy(s[].eng,"seven"),     s[].num = ;
     strcpy(s[].eng,"eight"),     s[].num = ;
     strcpy(s[].eng,"nine"),      s[].num = ;
     strcpy(s[].eng,"ten"),      s[].num= ;
     strcpy(s[].eng,"eleven"),   s[].num= ;
     strcpy(s[].eng,"twelve"),   s[].num= ;
     strcpy(s[].eng,"thirteen"), s[].num= ;
     strcpy(s[].eng,"fourteen"), s[].num= ;
     strcpy(s[].eng,"fifteen"),  s[].num= ;
     strcpy(s[].eng,"sixteen"),  s[].num= ;
     strcpy(s[].eng,"seventeen"),s[].num= ;
     strcpy(s[].eng,"eighteen"), s[].num= ;
     strcpy(s[].eng,"nineteen"), s[].num= ;
     strcpy(s[].eng,"twenty"),   s[].num= ;
     strcpy(s[].eng,"thirty"),   s[].num= ;
     strcpy(s[].eng,"forty"),    s[].num= ;
     strcpy(s[].eng,"fifty"),    s[].num= ;
     strcpy(s[].eng,"sixty"),    s[].num= ;
     strcpy(s[].eng,"seventy"),  s[].num= ;
     strcpy(s[].eng,"eighty"),    s[].num= ;
     strcpy(s[].eng,"ninety" ),   s[].num= ;
     strcpy(s[].eng,"hundred"),  s[].num= ;
     strcpy(s[].eng,"thousand"), s[].num= ;
     strcpy(s[].eng,"million"),  s[].num= ;
     strcpy(s[].eng,"negative"); s[].num= -;
     char a[];
     while(gets(a))
     {
         if(strlen(a)==) break;
         char tmp[]={};
         int ans=,flog=,sum=,x=;
         int len=strlen(a);
         for(int i=,k=;i<len;i++)
         {
             if(a[i]!=' ') tmp[k++]=a[i];
             if(a[i]==' '||i==len-){
                 k=;
                 flog=;
                 for(int m=;m<=;m++){
                     if(strcmp(s[m].eng,tmp)==){
                             if(m==) {
                                 x=-;
                                 continue;
                             }
                             if(m<=) sum+=s[m].num;
                             if(m==) sum*=s[m].num;
                             if(m>=) {
                                 ans+=sum*s[m].num;
                                 sum=;
                             }
                             break;
                     }
                 }
             }
             if(flog==){
                 memset(tmp,,sizeof(tmp));
                 flog=;
             }
         }
         printf("%d\n",(ans+sum)*x);
     }
     return ;
 }