A. Arrays(Codeforces Round #317 水题)

A. Arrays

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given two arrays A and B consisting
of integers, sorted in non-decreasing order. Check whether it is possible to choose knumbers
in array A and choose m numbers
in array B so that any number chosen in the first array is strictly less than any number chosen in the second array.

Input

The first line contains two integers nA, nB (1 ≤ nA, nB ≤ 105),
separated by a space — the sizes of arrays A and B,
correspondingly.

The second line contains two integers k and m (1 ≤ k ≤ nA, 1 ≤ m ≤ nB),
separated by a space.

The third line contains nA numbers a1, a2, ... anA ( - 109 ≤ a1 ≤ a2 ≤ ... ≤ anA ≤ 109),
separated by spaces — elements of array A.

The fourth line contains nB integers b1, b2, ... bnB ( - 109 ≤ b1 ≤ b2 ≤ ... ≤ bnB ≤ 109),
separated by spaces — elements of array B.

Output

Print "YES" (without the quotes), if you can choose k numbers
in array A and m numbers
in array B so that any number chosen in arrayA was
strictly less than any number chosen in array B. Otherwise, print "NO"
(without the quotes).

Sample test(s)

input

3 3
2 1
1 2 3
3 4 5

output

YES

input

3 3
3 3
1 2 3
3 4 5

output

NO

input

5 2
3 1
1 1 1 1 1
2 2

output

YES

Note

In the first sample test you can, for example, choose numbers 1 and 2 from array A and number 3 from array B (1
< 3 and 2 < 3).

In the second sample test the only way to choose k elements in the first array and m elements
in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in A will be less than all the numbers
chosen in B: .

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <algorithm>

using namespace std;
int a[100100],b[100010];
int n,m;
int k,t;

int main()
{
    while(scanf("%d%d",&n,&m)!=EOF)
    {
        scanf("%d%d",&k,&t);
        for(int i=0; i<n; i++)
        {
            scanf("%d",&a[i]);
        }
        for(int i=0; i<m; i++)
        {
            scanf("%d",&b[i]);
        }
        if(a[k-1] < b[m-t])
        {
            printf("YES\n");
        }
        else
        {
            printf("NO\n");
        }

    }
    return 0;
}