Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output:  321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

详见:https://leetcode.com/problems/reverse-integer/description/

实现语言:Java

class Solution {
public int reverse(int x) {
int res = 0;
while (x != 0) {
if (res > Integer.MAX_VALUE / 10 || res < Integer.MIN_VALUE / 10) {
return 0;
}
res = res * 10 + x % 10;
x /= 10;
}
return res;
}
}

实现语言:C++

class Solution {
public:
int reverse(int x) {
long res=0;
while(x)
{
res=res*10+x%10;
x/=10;
}
return (INT_MAX<res||INT_MIN>res)?0:res;
}
};

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