well-posed problem and ill-posed problem
well-posed problem must have the property that
- A solution exists
- The solution is unique
- The solution's behavior changes continuously with the initial conditions
简单来说就是有唯一解,并且是连续变化的。
Examples of archetypal well-posed problems include the Dirichlet problem for Laplace's equation, and the heat equation with specified initial conditions.
Problems that are not well-posed in the sense of Hadamard are termed ill-posed. Inverse problems are often ill-posed.
If the problem is well-posed, then it stands a good chance of solution on a computer using a stable algorithm. If it is not well-posed, it needs to be re-formulated for numerical treatment
well-posed problem and ill-posed problem的更多相关文章
- Problem : 1002 ( A + B Problem II )
经验总结:一定要注意输出的格式,字符的空格,空行,一定要观察清楚.如本题的最后一个输出结果后面没有空行.最后代码实现的时候需要判断一下,代码如下 !=n) cout<<endl; Prob ...
- 2013-2014 ACM-ICPC, NEERC, Southern Subregional Contest Problem B. Travelling Camera Problem set贪心
Problem B. Travelling Camera Problem 题目连接: http://www.codeforces.com/gym/100253 Description Programm ...
- Problem B The Blocks Problem(vector的使用)
题目链接:Problem B 题意:有n块木块,编号为0~n-1,要求模拟以下4种操作(下面的a和b都是木块编号) 1. move a onto b: 把a和b上方的木块全部归位,然后把a摞在b上面. ...
- 几何入门合集 gym101968 problem F. Mirror + gym102082 Problem F Fair Chocolate-Cutting + gym101915 problem B. Ali and Wi-Fi
abstract: V const & a 加速 F. Mirror 题意 链接 问题: 有n个人在y=0的平面上(及xoz平面).z=0平面上有一面镜子(边平行于坐标轴).z=a平面上有q个 ...
- A+B Problem Plus and A-B Problem Plus and A*B Problem Plus
//we have defined the necessary header files here for this problem. //If additional header files are ...
- Problem J. Joseph’s Problem 约瑟夫问题--余数之和
链接:https://vjudge.net/problem/UVA-1363 题意:给出n k,当 i 属于 1~n 时 ,求解 n% i 的和 n 和 k 的范围都是 1 到 10^9; 商相同 ...
- Holes in the text Add problem to Todo list Problem code: HOLES
import sys def count_holes(letter): hole_2 = ['A', 'D', 'O', 'P', 'Q', 'R'] if letter == 'B': return ...
- The Lead Game Add problem to Todo list Problem code: TLG
'''def count_lead(first, second): if first > second: return 1, first - second elif first == secon ...
- Turbo Sort Add problem to Todo list Problem code: TSORT
def heap_sort(ary): n = len(ary) first = int(n / 2 - 1) for start in range(first, -1, -1): # 3~0 rev ...
- POJ - Problem 2282 - The Counting Problem
整体思路:对于每一位,先将当前未达到$limit$部分的段 [如 $0$ ~ $10000$] 直接处理好,到下一位时再处理达到$limit$的部分. · $1 × 10 ^ n$以内每个数(包括$0 ...
随机推荐
- Qt出现警告 Unescaped backslashes are deprecated!解决办法
Fixing Qt Warning: Unescaped backslashes are deprecated! From: http://www.openguru.com/2011/10/fixin ...
- Nginx+Tomcat+Memcached负载均衡集群服务搭建
操作系统:CentOS6.5 本文档主要讲解,如何在CentOS6.5下搭建Nginx+Tomcat+Memcached负载均衡集群服务器,Nginx负责负载均衡,Tomcat负责实际服务,Memc ...
- OSCache 缓存技术
前言:OSCache标记库由OpenSymphony设计,它是一种开创性的JSP定制标记应用,提供了在现有JSP页面之内实现快速内存缓冲的功能.OSCache是个一个广泛采用的高性能的J2EE缓存框架 ...
- IOS代码
//// MJViewController.m// UITableView-编辑模式//// Created by mj on 13-4-11.// Copyright (c) 2013年 itcas ...
- C#编写媒体播放器--Microsoft的Directx提供的DirectShow组件,该组件的程序集QuartzTypeLib.dll.
使用C#编写媒体播放器时,需要用到Microsoft的Directx提供的DirectShow组件.用该组件前需要先注册程序集QuartzTypeLib.dll. 1.用QuartzTypeLib.d ...
- 8天学通MongoDB——第六天 分片技术
在mongodb里面存在另一种集群,就是分片技术,跟sql server的表分区类似,我们知道当数据量达到T级别的时候,我们的磁盘,内存 就吃不消了,针对这样的场景我们该如何应对. 一:分片 mong ...
- jenkins 状态管理
如何安装Jenkins as rpm: $ sudo service jenkins restart Usage: /etc/init.d/jenkins {start|stop|status|res ...
- [转载]Python模块学习 ---- subprocess 创建子进程
[转自]http://blog.sciencenet.cn/blog-600900-499638.html 最近,我们老大要我写一个守护者程序,对服务器进程进行守护.如果服务器不幸挂掉了,守护者能即时 ...
- bzoj4011
好题,首先有一个结论,有向无环图的树形图数目=根节点意外入度之积 现在相当于在原图上加一条边问树形图的数目 考虑多出来不合法的方案,一定是成环且包含新加入的边 对于一条路贡献就是∏d[i] [i∉pa ...
- Asp.Net IEnumerable,ICollection,IList,List区别
做C#的同学们,都知道,一类只能有一个继承类,但可以实现多个接口.这句话就告诉我们:IEnumerable,ICollection,IList,List区别了 首先我看看 IEnumerable: / ...