leetcode@ [274/275] H-Index & H-Index II (Binary Search & Array)

https://leetcode.com/problems/h-index/

Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.

According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the otherN − h papers have no more than h citations each."

For example, given citations = [3, 0, 6, 1, 5], which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3citations each, his h-index is 3.

Note: If there are several possible values for h, the maximum one is taken as the h-index.

Hint:

1. An easy approach is to sort the array first.
2. What are the possible values of h-index?
3. A faster approach is to use extra space.

class Solution {
public:
    int getIdx(vector<int>& vec, int val) {
        if(vec.size() <= ) return -;
        int low = , high = vec.size()-;
        while(low < high) {
            int mid = low + (high-low)/;
            if(vec[mid] < val) low = mid+;
            else high = mid;
        }
        return low;
    }
    int hIndex(vector<int>& citations) {
        if(citations.size() == ) return ;
        if(citations.size() == ) {
            if(citations[] == ) return ;
            return ;
        }
        sort(citations.begin(), citations.end());
        if(citations[citations.size()-] == ) return ;

        int res = INT_MIN;
        int low = , high = citations.size();
        while(low < high) {
            int mid = low + (high - low)/;
            if(mid <= citations.size()-getIdx(citations, mid)) {
                low = mid;
                res = max(res, mid);
            }
            else high = mid;
            if(high - low <= ) break;
        }

        if(low <= citations.size()-getIdx(citations, low)) {
            res = max(res, low);
        }
        if(high <= citations.size()-getIdx(citations, high)) {
            res = max(res, high);
        }
        return res;
    }
};

leetcode 263: H-Index

class Solution {
public:
    int getIdx(vector<int>& vec, int val) {
        if(vec.size() <= ) return -;
        int low = , high = vec.size()-;
        while(low < high) {
            int mid = low + (high-low)/;
            if(vec[mid] < val) low = mid+;
            else high = mid;
        }
        return low;
    }
    int hIndex(vector<int>& citations) {
        if(citations.size() == ) return ;
        if(citations.size() == ) {
            if(citations[] == ) return ;
            return ;
        }
        //sort(citations.begin(), citations.end());
        if(citations[citations.size()-] == ) return ;

        int res = INT_MIN;
        int low = , high = citations.size();
        while(low < high) {
            int mid = low + (high - low)/;
            if(mid <= citations.size()-getIdx(citations, mid)) {
                low = mid;
                res = max(res, mid);
            }
            else high = mid;
            if(high - low <= ) break;
        }

        if(low <= citations.size()-getIdx(citations, low)) {
            res = max(res, low);
        }
        if(high <= citations.size()-getIdx(citations, high)) {
            res = max(res, high);
        }
        return res;
    }
};

leetcode 264: H-Index II