JavaScript获取两个时间的时间差
<html>
<head>
<title>JavaScript计算两个时间差</title>
<meta http-equiv="content-Type" content="text/html;charset=gb2312">
</head>
<body>
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
function isValidDate(dateStr) {
var datePat = /^(\d{1,2})(\/|-)(\d{1,2})\2(\d{4})$/; // requires 4 digit year
var matchArray = dateStr.match(datePat); // is the format ok?
if (matchArray == null) {
alert(dateStr + " Date is not in a valid format.")
return false;
}
month = matchArray[1];
day = matchArray[3];
year = matchArray[4];
if (month < 1 || month > 12) {
alert("Month must be between 1 and 12.");
return false;
}
if (day < 1 || day > 31) {
alert("Day must be between 1 and 31.");
return false;
}
if ((month==4 || month==6 || month==9 || month==11) && day==31) {
alert("Month "+month+" doesn't have 31 days!")
return false;
}
if (month == 2) {
var isleap = (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0));
if (day>29 || (day==29 && !isleap)) {
alert("February " + year + " doesn't have " + day + " days!");
return false;
}
}
return true;
}
function isValidTime(timeStr) {
var timePat = /^(\d{1,2}):(\d{2})(:(\d{2}))?(\s?(AM|am|PM|pm))?$/;
var matchArray = timeStr.match(timePat);
if (matchArray == null) {
alert("Time is not in a valid format.");
return false;
}
hour = matchArray[1];
minute = matchArray[2];
second = matchArray[4];
ampm = matchArray[6];
if (second=="") { second = null; }
if (ampm=="") { ampm = null }
if (hour < 0 || hour > 23) {
alert("Hour must be between 1 and 12. (or 0 and 23 for military time)");
return false;
}
if (hour <= 12 && ampm == null) {
if (confirm("Please indicate which time format you are using. OK = Standard Time, CANCEL = Military Time")) {
alert("You must specify AM or PM.");
return false;
}
}
if (hour > 12 && ampm != null) {
alert("You can't specify AM or PM for military time.");
return false;
}
if (minute < 0 || minute > 59) {
alert ("Minute must be between 0 and 59.");
return false;
}
if (second != null && (second < 0 || second > 59)) {
alert ("Second must be between 0 and 59.");
return false;
}
return true;
}
function dateDiff(dateform) {
date1 = new Date();
date2 = new Date();
diff = new Date();
if (isValidDate(dateform.firstdate.value) && isValidTime(dateform.firsttime.value)) { // Validates first date
date1temp = new Date(dateform.firstdate.value + " " + dateform.firsttime.value);
date1.setTime(date1temp.getTime());
}
else return false;
if (isValidDate(dateform.seconddate.value) && isValidTime(dateform.secondtime.value)) { // Validates second date
date2temp = new Date(dateform.seconddate.value + " " + dateform.secondtime.value);
date2.setTime(date2temp.getTime());
}
else return false;
diff.setTime(Math.abs(date1.getTime() - date2.getTime()));
timediff = diff.getTime();
weeks = Math.floor(timediff / (1000 * 60 * 60 * 24 * 7));
timediff -= weeks * (1000 * 60 * 60 * 24 * 7);
days = Math.floor(timediff / (1000 * 60 * 60 * 24));
timediff -= days * (1000 * 60 * 60 * 24);
hours = Math.floor(timediff / (1000 * 60 * 60));
timediff -= hours * (1000 * 60 * 60);
mins = Math.floor(timediff / (1000 * 60));
timediff -= mins * (1000 * 60);
secs = Math.floor(timediff / 1000);
timediff -= secs * 1000;
dateform.difference.value = weeks + " weeks, " + days + " days, " + hours + " hours, " + mins + " minutes, and " + secs + " seconds";
return false;
}
// End -->
</script>
<form onSubmit="return dateDiff(this);">
<table>
<tr><td>
<pre>
起始时间:Date:<input type=text name=firstdate value="" size=10 maxlength=10>(MM/DD/YYYY format)
Time:<input type=text name=firsttime value="" size=10 maxlength=10>(HH:MM:SSam/pm format)
结束日期:Date:<input type=text name=seconddate value="" size=10 maxlength=10>(MM/DD/YYYY format)
Time:<input type=text name=secondtime value="" size=10 maxlength=10>(HH:MM:SSam/pm format)
<center>
<input type=submit value="计算日期之差"><br>
日期之差为:<input type=text name=difference value="" size=50>
</center>
</pre>
</td></tr>
</table>
</form>
</body>
</html>
JavaScript获取两个时间的时间差的更多相关文章
- C#两个时间的时间差的方法
今天遇到一问题,计算两个时间的时间差,看网上的写法较为复杂,找到个简单点的,记录下作为自己的总结. 关键函数: DateTime.Subtract 函数解释: 从此实例中减去指定的日期和时间,返回一个 ...
- java中获取两个时间中的每一天
引入下面方法即可: /** * 获取两个时间中的每一天 * @param bigtimeStr 开始时间 yyyy-MM-dd * @param endTimeStr 结束时间 yyyy-MM-dd ...
- PHP 获取两个时间之间的月份
## 获取两个时间之间的间距时间 $s = '2017-02-05'; $e = '2017-07-20'; $start = new \DateTime($s); $end = new \DateT ...
- JS比较两个时间的时间差
/** * 比较两个时间的时间差 * @param startTime 开始时间 * @param endTime 结束时间 * @demo compareTime(new Date('2019-12 ...
- C#计算两个时间的时间差,精确到年月日时分秒
喏,计算两个时间的时间差,精确到年月日时分秒 看起来比较笨的方法了,不知道有没有改进 DateTime d1 = new DateTime(2016, 4, 1, 0, 0, 0); DateTime ...
- 获取两个时间点间的随机时间&时间戳
获取两个时间点间的随机时间&时间戳 方案一 # python2 不兼容,python3正常 import datetime,random def randomtimes(start, end, ...
- JavaScript获取两个数之间的任意随机数
通过JavaScript的Math.random()方法可以获取0到1之间的任意随机数,那如何获取任意给定的两个数之间的随机数呢?如获取2和5之间的随机数,5和10之间的随机数等. 由于Math.ra ...
- 获取两个时间节点的月份列表&&每个月份的开始时间及结束时间
//Q:从今天起之前五个月的列表 date_default_timezone_set('PRC'); $time=strtotime('-5 month'); //包含本月 $begin = strt ...
- GoLang 获取两个时间相差多少小时
package main import ( "fmt" "time" ) func main() { fmt.Println(getHourDiffer(&qu ...
随机推荐
- phantomjs
PhantomJS是以WebKit为核心并提供JavaScript编程接口(API)的无界面浏览器. 它提供对web标准的 快速 并且 原生 的支持: DOM操作.CSS选择符.JSON.Canvas ...
- 分布式文件系统FastDFS设计原理
原文地址: http://blog.chinaunix.net/uid-20196318-id-4058561.html FastDFS是一个开源的轻量级分布式文件系统,由跟踪服务器(tracker ...
- jQuery Mobile和PhoneGap混合开发
其实二者并不影响,PhoneGap负责调用系统的接口,jQuery Mobile实现一些网页效果.PhoneGap开发请看上一篇文章,jQuery Mobile开发环境搭建如下:[请先阅读上一篇文章, ...
- POJ 2970 The lazy programmer(优先队列+贪心)
Language: Default The lazy programmer Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 1 ...
- Android Checkbox Example
1. Custom String 打开 “res/values/strings.xml” 文件, File : res/values/strings.xml <?xml version=&quo ...
- 虚拟机VMware 9安装苹果MAC OSX 10.8图文教程
前些天虚拟机VMware Workstation 9出来,相信大家都已经熟悉VM9了,至于MAC OSX 10.8系统,那也是出来一段时间了,本篇文章就是来讲解VMware Workstation 9 ...
- python类型转换、数值操作(转)
最近学习python语言,碰到数据类型间的转换问题.看到一篇文章总结的挺详细,收藏之备用. 类型转换 代码 Code highlighting produced by Actipro CodeHigh ...
- java中无符号类型的处理
在Java中,不存在Unsigned无符号数据类型,但可以轻而易举的完成Unsigned转换. 方案一:如果在Java中进行流(Stream)数据处理,可以用DataInputStream类对Stre ...
- 10905 - Children's Game
4th IIUC Inter-University Programming Contest, 2005 A Children’s Game Input: standard input Output: ...
- 永远不要在Linux 执行的 10 个最危险的命令
转: http://www.tecmint.com/10-most-dangerous-commands-you-should-never-execute-on-linux/ http://www.l ...