用户要求删除一个数据库的用户 GREENPASS,在删除的过程中,报错如下:

drop user GREENPASS * ERROR at line 1: ORA-04021: timeout occurred while waiting to lock object NEWDR.HNDR_SMS_LOG

处理过程

1. 首先查询NEWDR.HNDR_SMS_LOG,这是一个'PROCEDURE';

2. 现在报错,不能对此对象进行锁定。

3. 看看什么会话在访问此对象:

select B.SID, b.USERNAME, b.MACHINE   FROM V$ACCESS A, V$SESSION B WHERE A.SID = B.SID    and a.OBJECT = 'HNDR_SMS_LOG'    and a.TYPE = 'PROCEDURE';

SID USERNAME     MACHINE ---------- ------------ -------------------        520 NEWDR        WORKGROUP\BONC02

4. 根据sid获取操作系统的进程号

select spid os_sid   from v$process where addr = (select paddr from v$session where sid = &oracle_sid);

old 3: where addr = (select paddr from v$session where sid = &oracle_sid) new   3:  where addr = (select paddr from v$session where sid = 520)

OS_SID ------------ 29360

5. 询问业务人员,可以直接杀掉进程

ps -ef|grep 29360 kill -9 29360

6. 重新尝试 SQL> drop user GREENPASS; 用户已丢弃

-----------------------------------------------

sid 为 520 对应的语句 部分如下:

INSERT /*+ APPEND */                                                   INTO FACT_INFO_USER_BEFORE                                               (ACCT_MONTH,                                                            USER_NO,                                                               DEVICE_NUMBER,                                                         SERVICE_CODE,                                                          AREA_ID,                                                               CITY_ID,                                                               USER_DINNER,                                                           INNET_MONTH,                                                           AVG_ARPU,                                                              ACCT_ARPU,                                                             IS_ACCT,                                                               USER_TYPE,                                                             EXPIRE_MONTH)                                                         SELECT /*+ USE_HASH(A,B,C,D,E,F,G)*/                                    :B1,                                                                   C.USER_NO,                                                             C.DEVICE_NUMBER,                                                       C.TELE_TYPE,                                                           C.AREA_NO,                                                             C.CITY_NO,                                                             C.USER_DINNER,                                                         C.INNET_MONTH,                                                         A.AVG_FEE,                                                             B.ALL_FEE,                                                             NVL2(B.USER_NO, '1', '0'),                                             (CASE                                                                    WHEN F.CLUBMEM_LEVEL_SUB_CODE_LAST IN ('1', '2') AND                        F.CLUBMEM_LEVEL_SUB_CODE = '1' AND G.USER_NO IS NULL THEN          '1'                                                                   WHEN F.CLUBMEM_LEVEL_SUB_CODE_LAST IN ('1', '2') AND                        F.CLUBMEM_LEVEL_SUB_CODE = '2' AND G.USER_NO IS NULL THEN          '2'                                                                   WHEN F.CLUBMEM_LEVEL_SUB_CODE = '3' AND C.INNET_MONTH >= 4 AND              A.AVG_FEE >= D.HIGH_STANDARD AND G.USER_NO IS NULL THEN            '3'                                                                   WHEN C.INNET_MONTH >= 4 AND A.AVG_FEE >= D.HIGH_STANDARD AND                G.USER_NO IS NULL THEN                                             '4'                                                                   WHEN C.INNET_MONTH >= 4 AND A.AVG_FEE < D.HIGH_STANDARD AND                 A.AVG_FEE >= D.HIGH_STANDARD * 0.8 AND E.USER_TYPE <= '5' AND           G.USER_NO IS NULL THEN                                             '5'                                                                   WHEN C.INNET_MONTH >= 4 AND A.AVG_FEE < D.HIGH_STANDARD AND                 A.AVG_FEE >= D.HIGH_STANDARD * 0.8 AND E.USER_TYPE > '5' THEN       '6'                                                                   WHEN C.INNET_MONTH >= 4 AND A.AVG_FEE < D.HIGH_STANDARD * 0.8 AND           A.AVG_FEE >= 30 THEN                                               '6'

ORA-04021 timeout occurred while waiting to lock object的更多相关文章

  1. ORA-04021:timeout occurred while waiting to lock object

    编译某存储过程 ORA-04021 timeout occurred while waiting to lock object stringstringstringstringstring Cause ...

  2. 关于ORA-04021解决办法(timeout occurred while waiting to lock object)

    某个应用正在锁定该表或者包 表为 select b.SID,b.SERIAL#,c.SQL_TEXT from v$locked_object a, v$session b, v$sqlarea c ...

  3. org.eclipse.jdi.TimeoutException:Timeout occurred while waiting for packet 1983.occurred

    eclipse 增大junit内存配置 现象:eclipse在junit测试的时候出现如下错误 org.eclipse.jdi.TimeoutException:Timeout occurred wh ...

  4. Timeout occurred while waiting for latch: class 'ACCESS_METHODS_DATASET_PARENT'

    前些天某个SQL Server数据库的错误日志爆出如下错误: Timeout occurred while waiting for latch: class 'ACCESS_METHODS_DATAS ...

  5. Timeout occurred while waiting for latch: class 'COLUMNSTORE_ROWGROUP_COLLECTION'

    今天发现线上数据库主从延迟严重: SELECT ag.name AS ag_name, ar.replica_server_name AS ag_replica_server, dr_state.da ...

  6. org.eclipse.jdi.TimeoutException: Timeout occurred while waiting for packet 421. occured resuming VM.

    环境: 导入excel的时候,会根据路径,读取EXCEL的数据. 原因: 电脑上的防火墙关闭

  7. 【我的Android进阶之旅】解决AndroidStudio编译时报错:Timeout waiting to lock artifact cache .

    1. 错误描述 今天在Android Studio中,使用gradle命令的时候,出现了如下所示的错误: D:\GitLab Source\XTCLint>gradlew clean uploa ...

  8. Eclipse项目导入Android Stuio 配置出现 Timeout waiting to lock buildscript class cache for build file 'H:\studioproject\Generic_SN\build.gradle'

     Eclipse项目导入Android Stuio 配置出现 Error:Timeout waiting to lock buildscript class cache for build file  ...

  9. android studio :Timeout waiting to lock daemon addresses registry

    一.开发中 android studio 突然遇到下面的错误提示: Error:Timeout waiting to lock daemon addresses registry. It is cur ...

随机推荐

  1. 初步认知java的方法

    1.正确区分函数和方法: 面向对象的语言叫做方法,面向过程的语言叫做函数,两者的意义是一样的,只是叫法不同.java是面向对象的语言,所以用方法. 2.方法的定义: 就是有名字的代码段 3.方法的目的 ...

  2. Javascript.//DOM

    文档对象模型(Document Object Model,简称DOM),是W3C组织推荐的处理可扩展标志语言的标准编程接口.Document Object Model的历史可以追溯至1990年代后期微 ...

  3. 什么是html技术

    HTML(Hyper Text Mark-up Language )即超文本标记语言,是 WWW 的描述语言,由 Tim Berners-lee提出.设计 HTML 语言的目的是为了能把存放在一台电脑 ...

  4. WinZip Registry Optimizer 初体验

    WinZip Registry Optimizer是来自著名压缩软件WinZip开发团队的一种可以修复.组织和整理Windows注册表的应用程序,它可以删除无效的注册表条目,整理碎片从而提升系统性能, ...

  5. Eclipse动态web工程(Dynamic Web Project)添加jar文件的正确方法

    Eclipse中,创建了动态web工程之后,如果需要添加新的jar文件,有两种方法.第一种是配置工程的“build path”,第二种则是将jar文件放在工程目录下的“/WebContent/WEB- ...

  6. MIT JOS学习笔记02:kernel 01(2016.10.28)

    未经许可谢绝以任何形式对本文内容进行转载! 在文章开头不得不说的是,因为这部分的代码需要仔细理清的东西太多,所以导致这篇分析显得很啰嗦,还请谅解. 我们在上一篇文章已经分析了Boot Loader的功 ...

  7. ASP.NET Razor - C# 逻辑条件

    编程逻辑:根据条件执行代码. If 条件 C# 允许根据条件执行代码. 使用 if 语句来判断条件.根据判断结果,if 语句返回 true 或者 false: if 语句开始一个代码块 条件写在括号里 ...

  8. Dubbo框架

    1. Dubbo是什么? Dubbo是一个分布式服务框架,致力于提供高性能和透明化的RPC远程服务调用方案,以及SOA服务治理方案.简单的说,dubbo就是个服务框架,如果没有分布式的需求,其实是不需 ...

  9. unity行为树制作AI简单例子(2)

    继续昨天的工程,给Monster添加一个空物体命名为AI,在AI添加脚本BehaviorTree,然后就可以打开行为树编辑器进行编辑了 先写好自定义的节点脚本,下面是一个寻找漫游点的行为节点脚本 us ...

  10. 【OpenGL】第二篇 Hello OpenGL

    ---------------------------------------------------------------------------------------------------- ...