C. String Transformation
 
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given a string s consisting of |s| small english letters.

In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.

Your target is to make some number of moves (not necessary minimal) to get string abcdefghijklmnopqrstuvwxyz (english alphabet) as a subsequence. Subsequence of the string is the string that is obtained by deleting characters at some positions. You need to print the string that will be obtained from the given string and will be contain english alphabet as a subsequence or say that it is impossible.

Input

The only one line of the input consisting of the string s consisting of |s| (1 ≤ |s| ≤ 105) small english letters.

Output

If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes).

Examples
input

Copy
aacceeggiikkmmooqqssuuwwyy
output
abcdefghijklmnopqrstuvwxyz
input

Copy
thereisnoanswer
output
-1
代码:
 1 #include<iostream>
2 #include<cstring>
3 #include<cstdio>
4 #include<cmath>
5 #include<algorithm>
6 #include<cstdlib>
7 using namespace std;
8 typedef long long ll;
9 const int maxn=1e5+10;
10 #define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
11 int main(){
12 string s;
13 ios;
14 cin>>s;
15 int len=s.length();
16 int tmp=0;
17 for(int i=0;i<len;i++){
18 if(s[i]-'a'<=tmp){
19 tmp++;s[i]='a'+tmp-1;
20 }
21 if(tmp==26)break;
22 }
23 if(tmp==26)cout<<s<<endl;
24 else cout<<"-1"<<endl;
25 }

溜了,滚去写D的题解。

Codeforces 946 C.String Transformation的更多相关文章

  1. CCPC2018-湖南全国邀请赛 G String Transformation

    G.String Transformation 题目描述 Bobo has a string S = s1 s2...sn consists of letter a , b and c . He ca ...

  2. Codeforces 1383C - String Transformation 2(找性质+状压 dp)

    Codeforces 题面传送门 & 洛谷题面传送门 神奇的强迫症效应,一场只要 AC 了 A.B.D.E.F,就一定会把 C 补掉( 感觉这个 C 难度比 D 难度高啊-- 首先考虑对问题进 ...

  3. Codeforces 109D String Transformation 字符串 哈希 KMP

    原文链接https://www.cnblogs.com/zhouzhendong/p/CF109D.html 题目传送门 - CF109D 题意 给定两个字符串 $a,b$ ,求一组 $i,j$ 使得 ...

  4. C. String Transformation

    http://codeforces.com/problemset/problem/946/C You are given a string s consisting of |s| small engl ...

  5. CodeForces 797C Minimal string:贪心+模拟

    题目链接:http://codeforces.com/problemset/problem/797/C 题意: 给你一个非空字符串s,空字符串t和u.有两种操作:(1)把s的首字符取出并添加到t的末尾 ...

  6. Codeforces 827E Rusty String - 快速傅里叶变换 - 暴力

    Grigory loves strings. Recently he found a metal strip on a loft. The strip had length n and consist ...

  7. Codeforces 797C - Minimal string

    C. Minimal string 题目链接:http://codeforces.com/problemset/problem/797/C time limit per test 1 second m ...

  8. Codeforces Round 486C - Palindrome Transformation 贪心

    C. Palindrome Transformation time limit per test 1 second memory limit per test 256 megabytes input ...

  9. codeforces 825F F. String Compression dp+kmp找字符串的最小循环节

    /** 题目:F. String Compression 链接:http://codeforces.com/problemset/problem/825/F 题意:压缩字符串后求最小长度. 思路: d ...

随机推荐

  1. MyBatis的mapper.xml文件的参数问题:org.apache.ibatis.builder.IncompleteElementException: Could not find parameter map

    配置参数类型有两种选择,即:parameterType和parameterMap 不管参数是否是基本数据类型还是map类型,都是使用parameterType. 版权声明:本文为博主原创文章,未经博主 ...

  2. crond定时操作 crontab

    * * * * *  分别表示 分钟  小时  日  月  星期(0-6) 30 17,28,19 * * *  或 30 17-19 * * *  在每天的17-19小时半点时刻执行 30 8-18 ...

  3. 【windows】【md5】查看文件的md5值

    certutil -hashfile filename MD5 certutil -hashfile filename SHA1 certutil -hashfile filename SHA256 ...

  4. day22-python之模块

    1.os import os # print(os.getcwd()) # os.chdir("..") # print(os.getcwd()) # os.makedirs('d ...

  5. python模块之sys

    sys.argv 命令行参数List,第一个元素是程序本身路径 sys.exit(n) 退出程序,正常退出时exit(0) sys.version 获取Python解释程序的版本信息 sys.maxi ...

  6. 利用virt-manager,xmanager, xshell启动界面来管理虚拟机

    有时候我们需要搭建一套自己的简单环境来启动一个虚拟机,验证一些问题. 1.首先我利用vmware workstation来创建centos7虚拟机,然后开启虚拟化,如下图所示. 2.其次,启动虚拟机, ...

  7. 【12】Firefox 快捷键大全及更改和定制快捷键的方法

    [12]Firefox 快捷键大全及更改和定制快捷键的方法 答: Firefox 本身没有提供更改和定制快捷键的选项,若有需要,请安装扩展 Keyconfig 来解决.  安装地址如下: Keycon ...

  8. 24、AES RSA加密处理记录

    一.加密过程解释 前提:发送方为A,接受方为B牢记:RSA为非对称加密,AES为对称加密.对称加密,属于传统的加密技术,加密和解密的秘钥都是相同的,AES的秘钥长度有128.192.256三种.非对称 ...

  9. $.each 用break 好像不太灵啊

    for(var i=0;i<obj.length;i++) {                                       if (i < 5) {             ...

  10. DS博客作业06——图

    1.本周学习总结(0--2分) 1.思维导图 2.谈谈你对图结构的认识及学习体会. 这章学习了图,学习了图的两种存储结构:邻接矩阵和邻接表.这两种存储结构都用到了之前学c时学到的结构体,将结构体充分运 ...