https://pintia.cn/problem-sets/994805342720868352/problems/994805343979159552

A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the clique are adjacent. A maximal clique is a clique that cannot be extended by including one more adjacent vertex. (Quoted from https://en.wikipedia.org/wiki/Clique_(graph_theory))

Now it is your job to judge if a given subset of vertices can form a maximal clique.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers Nv (≤ 200), the number of vertices in the graph, and Ne, the number of undirected edges. Then Ne lines follow, each gives a pair of vertices of an edge. The vertices are numbered from 1 to Nv.

After the graph, there is another positive integer M (≤ 100). Then M lines of query follow, each first gives a positive number K (≤ Nv), then followed by a sequence of K distinct vertices. All the numbers in a line are separated by a space.

Output Specification:

For each of the M queries, print in a line Yes if the given subset of vertices can form a maximal clique; or if it is a clique but not a maximal clique, print Not Maximal; or if it is not a clique at all, print Not a Clique.

Sample Input:

8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
3 4 3 6
3 3 2 1

Sample Output:

Yes
Yes
Yes
Yes
Not Maximal
Not a Clique

代码:

#include <bits/stdc++.h>
using namespace std; int N, M, K;
int mp[220][220];
int vis[220]; int main() {
scanf("%d%d", &N, &M);
memset(mp, 0, sizeof(mp));
while(M --) {
int a, b;
scanf("%d%d", &a, &b);
mp[a][b] = mp[b][a] = 1;
}
scanf("%d", &K);
while(K --) {
int T;
vector<int> v;
memset(vis, 0, sizeof(vis));
scanf("%d", &T);
v.resize(T);
for(int i = 0; i < T; i ++) {
scanf("%d", &v[i]);
vis[v[i]] = 1;
} bool isclique = true;
for(int i = 0; i < T - 1; i ++) {
for(int j = i + 1; j < T; j ++) {
if(mp[v[i]][v[j]] == 0) {
isclique = false;
printf("Not a Clique\n");
break;
}
}
if(!isclique) break;
} if(!isclique) continue; bool ismax = true;
for(int i = 1; i <= N; i ++) {
if(vis[i] == 0) {
for(int j = 0; j < T; j ++) {
if(mp[v[j]][i] == 0) break;
if(j == T - 1) ismax = false;
}
}
if(!ismax) {
printf("Not Maximal\n");
break;
}
}
if(ismax) printf("Yes\n");
}
return 0;
}

  简单图论

FHFHFH

PAT 甲级 1142 Maximal Clique的更多相关文章

  1. PAT 1142 Maximal Clique[难]

    1142 Maximal Clique (25 分) A clique is a subset of vertices of an undirected graph such that every t ...

  2. [PAT] 1142 Maximal Clique(25 分)

    1142 Maximal Clique(25 分) A clique is a subset of vertices of an undirected graph such that every tw ...

  3. PAT 1142 Maximal Clique

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  4. 1142. Maximal Clique (25)

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  5. 1142 Maximal Clique

    题意:给出一个图,定义这样一个结点子集subset,若subset中的任意两结点不都相邻,则称之为Not a Clique:若subset中的任意两结点都相邻,则称之为Clique:若subset中的 ...

  6. PAT甲级目录

    树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 ...

  7. PAT甲级 图 相关题_C++题解

    图 PAT (Advanced Level) Practice 用到图的存储方式,但没有用到图的算法的题目 目录 1122 Hamiltonian Cycle (25) 1126 Eulerian P ...

  8. PAT A1142 Maximal Clique (25 分)——图

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  9. PAT甲级考前整理(2019年3月备考)之三,持续更新中.....

    PAT甲级考前整理一:https://www.cnblogs.com/jlyg/p/7525244.html,主要讲了131题的易错题及坑点 PAT甲级考前整理二:https://www.cnblog ...

随机推荐

  1. linux编译安装aria2

    一.安装aria2  [root@192-168-7-77 ~]# wget https://github.com/aria2/aria2/releases/download/release-1.33 ...

  2. Kubernetes学习之路(十五)之Ingress和Ingress Controller

    目录 一.什么是Ingress? 1.Pod 漂移问题 2.端口管理问题 3.域名分配及动态更新问题 二.如何创建Ingress资源 三.Ingress资源类型 1.单Service资源型Ingres ...

  3. Ubuntu环境下安装CUDA9.0

    前言: 本篇文章是基于安装CUDA 9.0的经验写,CUDA9.0目前支持Ubuntu16.04和Ubuntu17.04两个版本,如下图所示(最下面的安装方式我们选择第一个,即runfile方式): ...

  4. 新建一个Java Web程序

    依次选择 File——New——Web——Dynamic Web Project 输入项目名称“MyWebProject”,选择好Apache Tomcat V9.0服务器,其他采用默认配置. 单击N ...

  5. js中for循环的多种方式

    For/In 循环 JavaScript for/in 语句循环遍历对象的属性: 实例 var person={fname:"John",lname:"Doe" ...

  6. C#两个引用类的属性、方法 各位早安

    ***字符串.IndexOf("串"); - 返回字符串中第一个匹配项的索引,如果没有匹配项返回-1  intint b = s.IndexOf("天",s.I ...

  7. jvm系列 (一) ---jvm内存区域与溢出

    jvm内存区域与溢出 目录 jvm系列(一):jvm内存区域与溢出 jvm系列(二):垃圾收集器与内存分配策略 为什么学习jvm 木板原理,最短的一块板决定一个水的深度,当一个系统垃圾收集成为瓶颈的时 ...

  8. shell 本地接口自动化

    一.基于http/https的接口 一般情况下,当前大多公司在做接口自动化的时候都会使用一些工具:比如:postman/jmeter/python自研开发接口平台... 以上的情况,都是在源码与测试使 ...

  9. JUC——线程同步锁(ReentrantLock)

    ReentrantLock简介 ReentrantLock是一个可重复的互斥锁,又被称为独占锁,可重入的意思是:ReentrantLock锁可以被单个线程多次获取.但是在同一个时间点只能被一个线程锁持 ...

  10. linux下实现压测-html报表生成-控制台参数优化【jmeter】

    jmeter - 单机压测 - 命令行模式-html报表生成-控制台参数优化 一/ 准备工作 1.压力机安装并配置好 jdk 2.调试好程序脚本 再上传到 linux下 3.进入jmeter  bin ...