Android面HTTP协议发送get要求

/**
	 * 采纳get办法要求
	 *
	 * @param username
	 * @param password
	 * @return null表示求得的路径有问题,text返回请求得到的数据
	 */
	public static String getRequest(String username, String password) {
		try {
			String path = "http://172.22.64.156:8080/0001AndroidWebService/LoginServlet?username="
					+ URLEncoder.encode(username)
					+ "&password="
					+ URLEncoder.encode(password);
			URL url = new URL(path);
			HttpURLConnection conn = (HttpURLConnection) url.openConnection();

			conn.setReadTimeout(500);
			conn.setRequestMethod("GET");
			int code = conn.getResponseCode();
			if (code == 200) {
				// 请求成功
				InputStream is = conn.getInputStream();
				String text = StreamUtil.readStream(is);
				return text;
			} else {
				// 请求失败
				return null;
			}
		} catch (Exception e) {
			e.printStackTrace();
		}
		return null;
	}

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