javascript取url的参数的方法

<script type="text/javascript">
function request(paras)
{
    var url = location.href;
    var paraString = url.substring(url.indexOf("?")+1,url.length).split("&");
    var paraObj = {}
    for (i=0; j=paraString[i]; i++){
    paraObj[j.substring(0,j.indexOf("=")).toLowerCase()] = j.substring(j.indexOf("=")+1,j.length);
    }
    var returnValue = paraObj[paras.toLowerCase()];
    if(typeof(returnValue)=="undefined"){
    return "";
    }else{
    return returnValue;
    }
}
var title = request('title');
var dids = request('did');

show(dids,title);
function show(dids,title){
     $.ajax({
         url: "http://www.xxx.com/index.php?ac=article&at=read&isajax=1",
         type: "get",
         data:{did:dids},
         error: function(){
             alert('Error loading XML document');
         },
         success: function(data,status){
            // var obj = eval('(' + data + ')');
             $("#content").html(data);
             $("#content img").css("width","100%");
             $("#content img").css("height","auto");
            // alert(title);
            // $("#article_title").html(title);
         }
     });
}

</script>