Make Cents

Every year, an elephant qualifies to the Arab Collegiate Programming Competition. He graduated this year, but that’s irrelephant. What’s important is that the location of the competition might not have been the same every year. Therefore, after every trip, he always has leftover money in the currency of the country he visited.

Now he wants to see how much Jordanian Dinars he has after all those competitions. Can you help him convert the leftover money from all competitions to Jordanian Dinar, if that makes any cents?

Input

The first line of input is T – the number of test cases.

The first line of each test case contains C and N (1 ≤ C, N ≤ 100000), the number of currency types and the number of competitions, respectively.

The next C lines each contain the name of the currency C_i of maximum length 10 in lowercase and/or uppercase letters, and the value V_i of that currency in Jordanian Dinar (0 < V_i ≤ 1000). The names are case-sensitive.

The next N lines each contains an amount left over from each competition (0 ≤ N_i ≤ 1000), and the name of the currency of that amount (it is guaranteed that the name was either given in the input or is “JD”).

Output

For each test case, print on a single line the total amount of money he has in Jordanian Dinar(JD) rounded to 6 decimal digits.

Example

Input

Copy

1
3 5
dollar 0.71
euro 0.76
turkish 0.17
5.1 dollar
6 dollar
7 turkish
3 euro
1.1 JD

Output

Copy

12.4510006
题解：这题题意是汇率换算，看起来很简单（暴力），但数据量比较大很容易超时.这题需要用到STL中map（当容器中记录有1e6,查询次数也不过20次左右），时间复杂度就减小了。

 #include <iostream>
 #include <iostream>
 #include<string.h>
 #include<algorithm>
 #include<stdio.h>
 #include<stack>
 #include<queue>
 #include<vector>
 #include<math.h>
 #include<map>
 #define PI acos(-1.0)
 using namespace std;
 int main()
 {
     int i,j,m,n,t;
     char str[];
     double k;
     map<string,double>mp;
     scanf("%d",&t);
     while(t--)
     {
         scanf("%d%d",&m,&n);
         mp.clear();
         mp["JD"]=1.0;
         double sum=;
         for(i=;i<m; i++)
         {
             scanf("%s%lf",str,&k);
             mp[string(str)]=k;
         }
         for(i=; i<n; i++)
         {
             scanf("%lf %s",&k,str);
             sum+=mp[string(str)]*k;
         }
         printf("%.6lf\n",sum);
     }
     return ;
 }