背景

客户现场执行压测时候,发生周期性的TPS大幅下降,通过查看kwr报告发现DBcpu时间占DBtime时间很少,百分之90的DBtime花费在tuple锁等待上,等待事件类型是lock。

等待时间最多的语句是select fd_id,ctid,xmin from ... for update

含义

select for update语句目的在查询时,避免其他用户对该表进行dml等操作,造成表的不一致性。

select for update语句需要等待表锁,以及表对应行锁释放之后才能返回查询结果。

表级锁模式

常见锁模式以及应用场景:

ACCESS SHARE:select操作获取该模式锁资源,通常情况下所有只读取不修改表的查询都会获取该模式锁资源

ROW SHARE: select for update 和 select for share 命令获取该模式锁资源

ROW EXCLUSIVE: DML操作通过会获取该模式锁资源,通常情况下任何需要修改表数据的操作都会持有该模式锁资源

SHARE UPDATE EXCLUSIVE:对于 vacuum(非full)、create index concurrnetly、reindex concurrently、create statistics、alter index相关、alter table相关操作会持有该模式锁资源,该模式锁资源主要是为了范围并发对同一张表DDL变更以及vacuum操作

SHARE: create index (非concurrently)操作会持有该模式锁资源,该模式锁资源可阻止并发对表的创建索引操作

SHARE ROW EXCLUSIVE: cerate trigger、一些alter table操作会持有该模式锁资源

EXCLUSIVE: refresh materialized view concurrently操作会持有该模式锁资源

ACCESS EXCLUSIVE:lock table模式锁定模式,drop table、truncate、reindex、 cluster、vacuum full、refresh materialized view (without concurrently) 还有一些alter table、alter index操作需要获取该模式锁资源,该模式锁资源保证了持有者唯一访问表

测试

测试环境隔离级别是 read committed,数据库版本是KingbaseESV8R6C7

1.update语句阻塞select for update语句

开启一个会话,不提交
begin;
update t3 set name='qite' where id=1; 开启另一个会话执行,发现被阻塞
select id,name from t3 for update; 在另一个会话查看锁情况。
查看表t3有关的锁,这里表t3持有了tuple上的AccessExclusiveLock锁,这是最高级别的锁,阻塞一切sql语句。
pid4203持有的锁row share表示正在执行select for update语句,AccessExclusiveLock最高级别锁也是pid4203需要获取的。
pid4205持有的RowExclusiveLock锁表示执行dml语句需要获取的锁,这里可以看出pid4205会话很可能执行了update语句。
SELECT
pg_locks.pid,
a.datname,
locktype,
virtualtransaction,
transactionid,
nspname,
relname,
mode,
granted,
cast(date_trunc('second',query_start) AS timestamp) AS query_start
FROM
pg_locks
LEFT OUTER JOIN pg_class ON (pg_locks.relation = pg_class.oid)
LEFT OUTER JOIN pg_namespace ON (pg_namespace.oid = pg_class.relnamespace),
pg_stat_activity a
WHERE NOT pg_locks.pid = pg_backend_pid()
AND pg_locks.pid=a.pid
and pg_class.relname='t3';
pid | datname | locktype | virtualtransaction | transactionid | nspname | relname | mode | granted | query_start
------+---------+----------+--------------------+---------------+---------+---------+---------------------+---------+---------------------
4203 | test | tuple | 4/43 | | public | t3 | AccessExclusiveLock | t | 2023-05-16 15:39:11
4203 | test | relation | 4/43 | | public | t3 | RowShareLock | t | 2023-05-16 15:39:11
4205 | test | relation | 5/10 | | public | t3 | RowExclusiveLock | t | 2023-05-16 15:39:08
4205 | test | relation | 5/10 | | public | t3 | AccessShareLock | t | 2023-05-16 15:39:08
(4 rows) 执行另一个更直观的sql语句查看锁情况,开启第三个会话执行如下sql。
SELECT blocked_locks.pid AS blocked_pid,
blocked_activity.usename AS blocked_user,
blocking_locks.pid AS blocking_pid,
blocking_activity.usename AS blocking_user,
blocked_activity.query AS blocked_statement,
blocking_activity.query AS current_statement_in_blocking_process
FROM sys_catalog.sys_locks blocked_locks
JOIN sys_catalog.sys_stat_activity blocked_activity ON blocked_activity.pid = blocked_locks.pid
JOIN sys_catalog.sys_locks blocking_locks
ON blocking_locks.locktype = blocked_locks.locktype
AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
AND blocking_locks.pid != blocked_locks.pid
JOIN sys_catalog.sys_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
WHERE NOT blocked_locks.GRANTED;
blocked_pid | blocked_user | blocking_pid | blocking_user | blocked_statement | current_statement_in_blocking_process
-------------+--------------+--------------+---------------+------------------------------------+---------------------------------------
4203 | system | 4205 | system | select id,name from t3 for update; | update t3 set name='qite' where id=1;
(1 row) 在操作系统查看有关pid,4203pid中的select语句被阻塞,阻塞源头是第一个会话执行的update语句,pid是4205。
kingbas+ 4203 4154 0 15:27 ? 00:00:00 kingbase: system test [local] SELECT waiting
kingbas+ 4205 4154 0 15:27 ? 00:00:00 kingbase: system test [local] idle in transaction 第一个会话中的update语句commit或rollback后,事务结束后,第二个会话中的select for update语句可以执行成功,原因是blocking_pid被释放了。

2.select for update语句阻塞update语句

开启一个会话执行如下sql
begin;
select id,name from t3 for update; 开启另一个会话执行,发现被阻塞
update t3 set name='qitu' where id=1; 在另一个会话查看锁情况
pid4203对应RowExclusiveLock锁表示执行dml语句需要获取的锁,pid4205持有的RowShareLock锁说明此会话在执行select for update语句。
SELECT
pg_locks.pid,
a.datname,
locktype,
virtualtransaction,
transactionid,
nspname,
relname,
mode,
granted,
cast(date_trunc('second',query_start) AS timestamp) AS query_start
FROM
pg_locks
LEFT OUTER JOIN pg_class ON (pg_locks.relation = pg_class.oid)
LEFT OUTER JOIN pg_namespace ON (pg_namespace.oid = pg_class.relnamespace),
pg_stat_activity a
WHERE NOT pg_locks.pid = pg_backend_pid()
AND pg_locks.pid=a.pid
and pg_class.relname='t3';
pid | datname | locktype | virtualtransaction | transactionid | nspname | relname | mode | granted | query_start
------+---------+----------+--------------------+---------------+---------+---------+------------------+---------+---------------------
4203 | test | tuple | 4/44 | | public | t3 | ExclusiveLock | t | 2023-05-16 15:54:16
4203 | test | relation | 4/44 | | public | t3 | RowExclusiveLock | t | 2023-05-16 15:54:16
4203 | test | relation | 4/44 | | public | t3 | AccessShareLock | t | 2023-05-16 15:54:16
4205 | test | relation | 5/11 | | public | t3 | RowShareLock | t | 2023-05-16 15:54:00
(4 rows) 执行如下sql,果然阻塞源是pig4205执行的语句select for update。
SELECT blocked_locks.pid AS blocked_pid,
blocked_activity.usename AS blocked_user,
blocking_locks.pid AS blocking_pid,
blocking_activity.usename AS blocking_user,
blocked_activity.query AS blocked_statement,
blocking_activity.query AS current_statement_in_blocking_process
FROM sys_catalog.sys_locks blocked_locks
JOIN sys_catalog.sys_stat_activity blocked_activity ON blocked_activity.pid = blocked_locks.pid
JOIN sys_catalog.sys_locks blocking_locks
ON blocking_locks.locktype = blocked_locks.locktype
AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
AND blocking_locks.pid != blocked_locks.pid
JOIN sys_catalog.sys_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
WHERE NOT blocked_locks.GRANTED;
blocked_pid | blocked_user | blocking_pid | blocking_user | blocked_statement | current_statement_in_blocking_process
-------------+--------------+--------------+---------------+---------------------------------------+---------------------------------------
4203 | system | 4205 | system | update t3 set name='qitu' where id=1; | select id,name from t3 for update;
(1 row) 操作系统查看对应pid情况,pid4203执行update语句被阻塞,阻塞源是pid4205。
kingbas+ 4203 4154 0 15:27 ? 00:00:00 kingbase: system test [local] UPDATE waiting
kingbas+ 4205 4154 0 15:27 ? 00:00:00 kingbase: system test [local] idle in transaction 解决方法是持有锁会话结束事务(提交或回滚),随后被阻塞的update语句执行成功,或杀掉持有锁的进程。

总结

select for update几种其他用法:

select * from t for update nowait 不等待行锁释放,提示锁冲突,不返回结果。

select * from t for update wait 5 等待5秒,若行锁仍未释放,则提示锁冲突,不返回结果。

select * from t for update skip locked 查询返回查询结果,但忽略有行锁的记录。

使用FOR UPDATE WAIT”子句有几个优点:

1.防止无限期地等待被锁定的行。

2.允许应用程序中对锁的等待时间进行控制。

3.在不确定sql执行前表是否被锁,wait关键字起到关键作用。

4.若使用了skip locked,则可以越过锁定的行,而不会报错。

此案例提供了数据库中锁阻塞的排查方法,如生产环境中遇到其他类型lock重型锁阻塞,也可用以上方法分析。

KingbaseES 中select for update语句引起的锁问题的更多相关文章

  1. 数据库中Select For update语句的解析

    ----------- Oracle -----------------– Oracle 的for update行锁 键字: oracle 的for update行锁 SELECT-FOR UPDAT ...

  2. KingbaseES 中select distinct on 语句

    用法 SELECT DISTINCT ON ( expression [, ...] ) 把记录根据[, -]的值进行分组,分组之后仅返回每一组的第一行. 需要注意的是,如果不指定ORDER BY子句 ...

  3. mysql 多列唯一索引在事务中select for update是不是行锁?

    在表中有这么一索引 UNIQUE KEY `customer_id` (`customer_id`,`item_id`,`ref_id`) 问1. 这种多列唯一索引在事务中select for upd ...

  4. Select For update语句浅析 (转)

    Select … for update语句是我们经常使用手工加锁语句.通常情况下,select语句是不会对数据加锁,妨碍影响其他的DML和DDL操作.同时,在多版本一致读机制的支持下,select语句 ...

  5. MySQL中select * for update锁表的范围

    MySQL中select * for update锁表的问题 由于InnoDB预设是Row-Level Lock,所以只有「明确」的指定主键,MySQL才会执行Row lock (只锁住被选取的资料例 ...

  6. MySQL中select * for update锁表的问题

    MySQL中select * for update锁表的问题 由于InnoDB预设是Row-Level Lock,所以只有「明确」的指定主键,MySQL才会执行Row lock (只锁住被选取的资料例 ...

  7. sql server中同时执行select和update语句死锁问题

    原始出处 http://oecpby.blog.51cto.com/2203338/457054 最近在项目中使用SqlServer的时候发现在高并发情况下,频繁更新和频繁查询引发死锁.通常我们知道如 ...

  8. 数据库:Mysql中“select ... for update”排他锁分析

    Mysql InnoDB 排他锁 用法: select … for update; 例如:select * from goods where id = 1 for update; 排他锁的申请前提:没 ...

  9. Select For update语句浅析

    Select -forupdate语句是我们经常使用手工加锁语句.通常情况下,select语句是不会对数据加锁,妨碍影响其他的DML和DDL操作.同时,在多版本一致读机制的支持下,select语句也不 ...

  10. Mysql中“select ... for update”排他锁(转)

    原帖地址 https://blog.csdn.net/claram/article/details/54023216 Mysql InnoDB 排他锁 用法: select … for update; ...

随机推荐

  1. Rtmp 开发学习

    参考文章:视频传输协议详解(RTMP.RTSP.HLS) RTMP--Real Time Messaging Protocol(实时消息传输协议) RTMP 是由 Adobe 公司提出的,在互联网 T ...

  2. Go语言并发编程(2):channel 通道介绍和使用

    一.简介 channel 不仅可以用于 goroutine 间进行安全通信,还可以用于同步内存访问. 而且 Go 社区强烈推荐使用 channel 通道实现 goroutine 之间的通信, 不要通过 ...

  3. 【Azure Developer】AAD API如何获取用户“Block sign in”信息(accountEnabled)

    问题描述 使用API获取所有Azure AD中的用户列表,API所参考的文档:https://docs.microsoft.com/en-us/graph/api/user-list?view=gra ...

  4. 图数据库 Nebula Graph 的代码变更测试覆盖率实践

    对于一个持续开发的大型工程而言,足够的测试是保证软件行为符合预期的有效手段,而不是仅仅依靠 code review 或者开发者自己的技术素质.测试的编写理想情况下应该完全定义软件的行为,但是通常情况都 ...

  5. 论文《Attention is all you need》阅读笔记

    Attention is all you need Transformer模型 Model Architecture Transformer结构上和传统的翻译模型相同,拥有encoder-decode ...

  6. Java 常用类 String的常用方法(2)

    1 /** 2 * String 常用方法(2) 3 * boolean endsWith(String suffix):测试此字符串是否以指定的后缀结束 4 * boolean startsWith ...

  7. Java 小练习(3) 方法的修改+ 调用

    1 package com.bytezero.exer; 2 3 public class ExerTest 4 { 5 public static void main(String[] args) ...

  8. C++ //排序案列 //描述:将person自定义数据类型进行排序,Person中有属性 姓名,年龄,身高 //排序规则: 按照年龄进行的升序,如果年龄相同按照身高进行降序

    1 //排序案列 2 //描述:将person自定义数据类型进行排序,Person中有属性 姓名,年龄,身高 3 //排序规则: 按照年龄进行的升序,如果年龄相同按照身高进行降序 4 5 #inclu ...

  9. 使用Kubernetes搭建带有ik分词的Elasticsearch集群

    创建好带有Ik分词的es镜像,并上传到镜像仓库中,创建镜像可参考链接中的文档 https://www.cnblogs.com/hi-lijq/p/16895206.html 编写es_cluster- ...

  10. idea vue 格式化 并保存文件 宏 快捷键 ctrl+s

    idea 格式化是 reformat Code 存盘是 ctrl+s 所以创建一个宏,先点格式化,再点存盘,然后定义个ctrl+s的快捷键覆盖之前的保存就ok了. 资料: IDEA 配置宏定义 并为宏 ...