Buy the Ticket

      Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
        Total Submission(s): 7152    Accepted Submission(s): 2998

Problem Description
The "Harry Potter and the Goblet of Fire" will be on show in the next few days. As a crazy fan of Harry Potter, you will go to the cinema and have the first sight, won’t you?

Suppose the cinema only has one ticket-office and the price for per-ticket is 50 dollars. The queue for buying the tickets is consisted of m + n persons (m persons each only has the 50-dollar bill and n persons each only has the 100-dollar bill).

Now the problem for you is to calculate the number of different ways of the queue that the buying process won't be stopped from the first person till the last person. 
Note: initially the ticket-office has no money.

The buying process will be stopped on the occasion that the ticket-office has no 50-dollar bill but the first person of the queue only has the 100-dollar bill.

 
Input
The input file contains several test cases. Each test case is made up of two integer numbers: m and n. It is terminated by m = n = 0. Otherwise, m, n <=100.
 
Output
For each test case, first print the test number (counting from 1) in one line, then output the number of different ways in another line.
 
Sample Input
3 0
3 1
3 3
0 0
Sample Output
Test #1:
6
Test #2:
18
Test #3:
180
 
Author
HUANG, Ninghai
 
Recommend
Eddy   |   We have carefully selected several similar problems for you:  1267 1297 2067 1143 1715 
 

HDU——1133 Buy the Ticket的更多相关文章

  1. hdu 1133 Buy the Ticket(Catalan)

    Buy the Ticket Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) T ...

  2. hdu 1133 Buy the Ticket (大数+递推)

    Buy the Ticket Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)To ...

  3. HDU 1133 Buy the Ticket (数学、大数阶乘)

    Buy the Ticket Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)To ...

  4. hdu 1133 Buy the Ticket

    首先,记50的为0,100的为1. 当m=4,n=3时,其中的非法序列有0110010; 从不合法的1后面开始,0->1,1->0,得到序列式0111101 也就是说,非法序列变为了n-1 ...

  5. HDOJ/HDU 1133 Buy the Ticket(数论~卡特兰数~大数~)

    Problem Description The "Harry Potter and the Goblet of Fire" will be on show in the next ...

  6. HDU 1133 Buy the Ticket 卡特兰数

    设50元的人为+1 100元的人为-1 满足前随意k个人的和大于等于0 卡特兰数 C(n+m, m)-C(n+m, m+1)*n!*m! import java.math.*; import java ...

  7. 【HDU 1133】 Buy the Ticket (卡特兰数)

    Buy the Ticket Problem Description The "Harry Potter and the Goblet of Fire" will be on sh ...

  8. HDUOJ---1133(卡特兰数扩展)Buy the Ticket

    Buy the Ticket Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)To ...

  9. Buy the Ticket{HDU1133}

    Buy the TicketTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total ...

随机推荐

  1. AGC16E Poor Turkeys

    输入样例: 10 10 8 9 2 8 4 6 4 9 7 8 2 8 1 8 3 4 3 4 2 7 输出样例#6: 5 话说这题虽然不是很OI但是确实挺锻炼思维的 一开始以为是用并查集之类的东西维 ...

  2. [转]从数据到代码——基于T4的代码生成方式

    本文转自:http://www.cnblogs.com/artech/archive/2010/10/23/1859529.html 在之前写一篇文章<从数据到代码>(上篇.下篇)中,我通 ...

  3. VS2013使用单元测试

    一.开发环境 开发工具:VS2013 二.开发流程 1.添加一个控制台项目UnitDemo namespace UnitDemo { public class Program { static voi ...

  4. 专题七:UDP编程补充——UDP广播程序的实现

    一.程序实现 UDP广播程序的实现代码: using System; using System.Net; using System.Net.Sockets; using System.Text; us ...

  5. ios基础笔试题-集锦二

    前言 下文转载自:http://www.henishuo.com/objc-interview-two/ 1.即时聊天App不会采用的网络传输方式 A. UDP B. TCP C. HTTP D. F ...

  6. NoSQL与关系数据库

    关系型数据库:完全支持关系代数理论作为基础:有较大的数据规模:固定的数据库模式:查询效率快:强一致性:数据完整性较易实现:扩展性一般:可用性好. NoSQL:部分支持关系代数理论作为基础:有超大数据规 ...

  7. Microsoft SQL Server学习(三)

    1.表:表示一个实体(客观存在的事物或抽象时间),可实现对实体的数据描述和数据操作. 2.表结构:二位平面(行.列) 3.数据类型: 类型名称 类型 整形 bit(只存储0.1) samllint i ...

  8. DIV水平 垂直居中CSS

    /*实现一.原理:要让div等块级元素水平和垂直居中,必需知道该div等块级元素的宽度和高度,然后设置位置为绝对位置,距离页面窗口左边框和上边框的距离设置为50%,这个50%就是指页面窗口的宽度和高度 ...

  9. POJ_2255_Tree Recovery

    Tree Recovery Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12342   Accepted: 7712 De ...

  10. Crash reporter

    A crash reporter is a software application whose function is to identify report crash details and to ...