Given N integers, you are supposed to find the smallest positive integer that is NOT in the given list.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10​5​​). Then N integers are given in the next line, separated by spaces. All the numbers are in the range of int.

Output Specification:

Print in a line the smallest positive integer that is missing from the input list.

Sample Input:

10
5 -25 9 6 1 3 4 2 5 17

Sample Output:

7

#include <stdio.h>
#include <algorithm>
#include <limits.h>
#include <set>
using namespace std;
int main() {
int n;
scanf("%d", &n);
set<int> st;
for (int i = ; i < n; i++) {
int tmp;
scanf("%d", &tmp);
if (tmp > ) {
st.insert(tmp);
}
}
int j = ;
for (auto it = st.begin(); it != st.end(); it++) {
if (*it > j) {
printf("%d", j);
break;
}
else j++;
}
if(j==st.size()+)printf("%d",j);
}

注意点:这里只保证了输入数不超过int大小,用hash不好做,不如直接用set,自动升序排列,找到第一个不满足的数。

第二个坑是测试点2-5都是输入数据连续的,缺失的是输入数据后面那个数

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