A Magic Lamp -- hdu -- 3183
http://acm.hdu.edu.cn/showproblem.php?pid=3183
A Magic Lamp
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2515 Accepted Submission(s): 983
The question is: give you an integer, you are allowed to delete exactly m digits. The left digits will form a new integer. You should make it minimum.
You are not allowed to change the order of the digits. Now can you help Kiki to realize her dream?
Each test case will contain an integer you are given (which may at most contains 1000 digits.) and the integer m (if the integer contains n digits, m will not bigger then n). The given integer will not contain leading zero.
If the result contains leading zero, ignore it.
#include<iostream>
#include<string.h>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<algorithm>
#include<queue>
using namespace std; #define N 110000
#define MOD 100000007 char s[N];
int a[N], m; int Find(int k); void Print(); void Slove(int k); int main()
{
int n; while(scanf("%s%d", s, &n)!=EOF)
{
int i, j; m=n; memset(a, , sizeof(a));
for(i=; s[i]; i++)
a[i] = s[i]-''; i=;
while()
{
int next = Find(i);
if(next== || next-i>m)
break; for(j=i; j<next; j++)
{
a[j] = -;
m--;
} i = next;
while(a[i]==) i++;
} Slove(i); Print();
}
return ;
} void Slove(int k)
{
int i, j, index, len=strlen(s)-; while()
{
if(m==) break; index=-;
for(i=k; i<=len; i++)
{
if(a[i]==-) continue;
j = i+;
while(a[j]==-) j++; if(a[i]>a[j])
{
index = i;
break;
}
}
if(index==-)
break; a[index] = -;
m--;
}
} int Find(int k)
{
int i; for(i=k+; s[i]; i++)
{
if(a[i]==)
return i;
}
return ;
} void Print()
{
int i, j, flag=; for(i=; s[i]; i++)
{
if(a[i]!= && a[i]!=-)
break;
}
for(j=i; s[j]; j++)
{
if(a[j]!=-)
{
printf("%d", a[j]);
flag = ;
}
}
if(!flag) printf(""); printf("\n");
}
A Magic Lamp -- hdu -- 3183的更多相关文章
- A Magic Lamp HDU - 3183 (逆向贪心/RMQ)
Kiki likes traveling. One day she finds a magic lamp, unfortunately the genie in the lamp is not so ...
- A Magic Lamp HDU - 3183(RMQ返回下标)
原文地址:https://blog.csdn.net/acdreamers/article/details/8692384 题意: 对于一个序列A[1...N],一共N个数,除去M个数使剩下的数组成的 ...
- hdu 3183 A Magic Lamp(RMQ)
题目链接:hdu 3183 A Magic Lamp 题目大意:给定一个字符串,然后最多删除K个.使得剩下的组成的数值最小. 解题思路:问题等价与取N-M个数.每次取的时候保证后面能取的个数足够,而且 ...
- hdu 3183 A Magic Lamp RMQ ST 坐标最小值
hdu 3183 A Magic Lamp RMQ ST 坐标最小值 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3183 题目大意: 从给定的串中挑 ...
- HDU 3183 - A Magic Lamp - [RMQ][ST算法]
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3183 Problem DescriptionKiki likes traveling. One day ...
- hdu 3183 A Magic Lamp rmq或者暴力
A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Pro ...
- hdu 3183 A Magic Lamp(RMQ)
A Magic Lamp Time Limi ...
- HDU 3183 A Magic Lamp(RMQ问题, ST算法)
原题目 A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) ...
- hdu A Magic Lamp
http://acm.hdu.edu.cn/showproblem.php?pid=3183 A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) ...
随机推荐
- js函数定义和调用
由于JavaScript的函数也是一个对象,上述定义的abs()函数实际上是一个函数对象,而函数名abs可以视为指向该函数的变量. var abs = function (x) { if (x > ...
- tkinter模块
Python GUI编程(Tkinter) Python 提供了多个图形开发界面的库,几个常用 Python GUI 库如下: Tkinter: Tkinter 模块(Tk 接口)是 Python 的 ...
- Tech 2 doesn’t system for H2 above 2007
I purchased my Tech2 from obd2tool.com and it operates excellent. Can not definitely compare softwar ...
- git报“commiter email "root@localhost.localdomain"does not match your user account”
首先检查账户邮箱配置是否正确,检查方法: git config --list 发现邮箱及帐号配置正确,但是git push时仍然报如题错误: 原因:git执行add.commit 时已经记录下了做了该 ...
- ASC与HEX之间的转换
ASC与HEX之间的转换 有这么两个函数: 函数 原型 功能 返回值 参数 备注 hex2asc __int16 hex2asc(unsigned char *strhex,unsigned char ...
- 如何使用Log4j
如何使用Log4j? 1. Log4j是什么? Log4j可以帮助调试(有时候debug是发挥不了作 用的)和分析,要下载和了解更详细的内容,还是访问其官方网站吧: http://jakarta. ...
- js之function
function* function* 这种声明方式(function关键字后跟一个星号)会定义一个生成器函数 (generator function),它返回一个 Generator 对象. 你 ...
- spoj 7258 SUBLEX(求第k大字串
其实对sam的拓扑排序我似懂非懂但是会用一点了. /** @xigua */ #include <stdio.h> #include <cmath> #include < ...
- c#中的as,is和强转
as和强转之间的区别: as转换类型失败时不会抛出异常:强转类型失败时会抛出异常 引入is先对变量进行检验: if (foo is int) { i = (int)foo; } logger log ...
- php 超时设置笔记
php.ini default_socket_timeout=5 mysql.connect_timeout = 5 max_execution_time = 5 php-fpm pm = dynam ...