A Magic Lamp -- hdu -- 3183
http://acm.hdu.edu.cn/showproblem.php?pid=3183
A Magic Lamp
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2515 Accepted Submission(s): 983
The question is: give you an integer, you are allowed to delete exactly m digits. The left digits will form a new integer. You should make it minimum.
You are not allowed to change the order of the digits. Now can you help Kiki to realize her dream?
Each test case will contain an integer you are given (which may at most contains 1000 digits.) and the integer m (if the integer contains n digits, m will not bigger then n). The given integer will not contain leading zero.
If the result contains leading zero, ignore it.
#include<iostream>
#include<string.h>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<algorithm>
#include<queue>
using namespace std; #define N 110000
#define MOD 100000007 char s[N];
int a[N], m; int Find(int k); void Print(); void Slove(int k); int main()
{
int n; while(scanf("%s%d", s, &n)!=EOF)
{
int i, j; m=n; memset(a, , sizeof(a));
for(i=; s[i]; i++)
a[i] = s[i]-''; i=;
while()
{
int next = Find(i);
if(next== || next-i>m)
break; for(j=i; j<next; j++)
{
a[j] = -;
m--;
} i = next;
while(a[i]==) i++;
} Slove(i); Print();
}
return ;
} void Slove(int k)
{
int i, j, index, len=strlen(s)-; while()
{
if(m==) break; index=-;
for(i=k; i<=len; i++)
{
if(a[i]==-) continue;
j = i+;
while(a[j]==-) j++; if(a[i]>a[j])
{
index = i;
break;
}
}
if(index==-)
break; a[index] = -;
m--;
}
} int Find(int k)
{
int i; for(i=k+; s[i]; i++)
{
if(a[i]==)
return i;
}
return ;
} void Print()
{
int i, j, flag=; for(i=; s[i]; i++)
{
if(a[i]!= && a[i]!=-)
break;
}
for(j=i; s[j]; j++)
{
if(a[j]!=-)
{
printf("%d", a[j]);
flag = ;
}
}
if(!flag) printf(""); printf("\n");
}
A Magic Lamp -- hdu -- 3183的更多相关文章
- A Magic Lamp HDU - 3183 (逆向贪心/RMQ)
Kiki likes traveling. One day she finds a magic lamp, unfortunately the genie in the lamp is not so ...
- A Magic Lamp HDU - 3183(RMQ返回下标)
原文地址:https://blog.csdn.net/acdreamers/article/details/8692384 题意: 对于一个序列A[1...N],一共N个数,除去M个数使剩下的数组成的 ...
- hdu 3183 A Magic Lamp(RMQ)
题目链接:hdu 3183 A Magic Lamp 题目大意:给定一个字符串,然后最多删除K个.使得剩下的组成的数值最小. 解题思路:问题等价与取N-M个数.每次取的时候保证后面能取的个数足够,而且 ...
- hdu 3183 A Magic Lamp RMQ ST 坐标最小值
hdu 3183 A Magic Lamp RMQ ST 坐标最小值 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3183 题目大意: 从给定的串中挑 ...
- HDU 3183 - A Magic Lamp - [RMQ][ST算法]
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3183 Problem DescriptionKiki likes traveling. One day ...
- hdu 3183 A Magic Lamp rmq或者暴力
A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Pro ...
- hdu 3183 A Magic Lamp(RMQ)
A Magic Lamp Time Limi ...
- HDU 3183 A Magic Lamp(RMQ问题, ST算法)
原题目 A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) ...
- hdu A Magic Lamp
http://acm.hdu.edu.cn/showproblem.php?pid=3183 A Magic Lamp Time Limit: 2000/1000 MS (Java/Others) ...
随机推荐
- PAT 1039 到底买不买(20)(20 分)
1039 到底买不买(20)(20 分) 小红想买些珠子做一串自己喜欢的珠串.卖珠子的摊主有很多串五颜六色的珠串,但是不肯把任何一串拆散了卖.于是小红要你帮忙判断一下,某串珠子里是否包含了全部自己想要 ...
- zabbix监控系统_监控收集脚本使用分享
性能测试总是要监控服务器,做了zabbix监控之后,重要收集监控数据,这里分享下我是怎么做的. 准备文件 python2.7 pypa-setuptools.tar.gz -p -path /h ...
- 通过修改Delphi 的 RTL,加快Delphi开发的应用程序速度和稳定性
RT 具体见PDF 看了不后悔,只给高手准备的. 神呐,偶看看是虾米东东
- Android相关概念
2017-06-02 armeabi就是针对普通的或旧的arm v5 cpu,armeabi-v7a是针对有浮点运算或高级扩展功能的arm v7 cpu. armeabi-v7a(32位ARM设备), ...
- MySQLdb与sqlalchemy的简单封装
一:MySQLdb # !/usr/bin/python # -*- coding: UTF-8 -*- import MySQLdb import MySQLdb.cursors import co ...
- java Mather 的 group 含义
参考博文: http://blog.csdn.net/java2king/article/details/4395067 明白了group 的 含义 public class Test { pub ...
- spring boot 无法启动
spring boot 使用内置tomcat 报错 : Unable to start embedded Tomcat servlet container Tomcat connector in f ...
- SparkStreaming--reduceByKeyAndWindow
1.reduceByKeyAndWindow(_+_,Seconds(3), Seconds(2)) 可以看到我们定义的window窗口大小Seconds(3s) ,是指每2s滑动时,需要统计 ...
- syslog、日志服务器安装、卸载详解、如何安装和卸载EventLog Analyzer
- How to turn on syntax highlighting in osx
put follow code in ~/.vimrc set ai " auto indenting set history=100 " keep 100 lines of hi ...