题目

给定一个无向图的节点,克隆能克隆的一切

思路

1--2
|
3--5

以上图为例,

node    neighbor

1         2, 3

2         1

3         1, 5

5         3

首先从1开始,  将(node,newNode)put到HashMap中

node        newNode

1                1

然后遍历该node的所有neighbor

node    neighbor

1         2, 3

此时遍历到2

将(node,newNode)put到HashMap中

node        newNode

1                1 -- 2  // newNode.neighbors.add(clone)

2               2

代码

 public class Solution {

     Map<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<>();

     public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) {
return null;
} //DFS
if (map.containsKey(node)) {
return map.get(node);
} UndirectedGraphNode newNode = new UndirectedGraphNode(node.label);
map.put(node, newNode);
for (UndirectedGraphNode nei : node.neighbors) {
UndirectedGraphNode clone = cloneGraph(nei);
newNode.neighbors.add(clone);
}
return newNode;
}
}

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