题目:

Consider an array of sheep where some sheep may be missing from their place. We need a function that counts the number of sheep present in the array (true means present).

For example,

[True,  True,  True,  False,
True, True, True, True ,
True, False, True, False,
True, False, False, True ,
True, True, True, True ,
False, False, True, True]

The correct answer would be 17.

Hint: Don't forget to check for bad values like null/undefined

解题办法:

def count_sheeps(arrayOfSheeps):
sum = 0
for x in arrayOfSheeps:
if x:
sum += 1
return sum

其他解法:

def count_sheeps(arrayOfSheeps):
return arrayOfSheeps.count(True)

知识点:

1、计算s数量可以使用l.count(s)

【Kata Daily 190927】Counting sheep...(数绵羊)的更多相关文章

  1. Counting sheep...

    Counting sheep... Description: Consider an array of sheep where some sheep may be missing from their ...

  2. 【DFS深搜初步】HDOJ-2952 Counting Sheep、NYOJ-27 水池数目

    [题目链接:HDOJ-2952] Counting Sheep Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 ...

  3. HDU-2952 Counting Sheep (DFS)

    Counting Sheep Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Tota ...

  4. HDU 2952 Counting Sheep(DFS)

    题目链接 Problem Description A while ago I had trouble sleeping. I used to lie awake, staring at the cei ...

  5. HDU2952:Counting Sheep(DFS)

    Counting Sheep Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Tota ...

  6. Hdu2952 Counting Sheep 2017-01-18 14:56 44人阅读 评论(0) 收藏

    Counting Sheep Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Tota ...

  7. ACM HDU-2952 Counting Sheep

    Counting Sheep Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) T ...

  8. 洛谷 P3184 [USACO16DEC]Counting Haybales数草垛

    P3184 [USACO16DEC]Counting Haybales数草垛 题目描述 Farmer John has just arranged his NN haybales (1 \leq N ...

  9. Project Euler 85 :Counting rectangles 数长方形

    Counting rectangles By counting carefully it can be seen that a rectangular grid measuring 3 by 2 co ...

随机推荐

  1. Docker---初识到使用

    1.剖析虚拟化技术概念 1)虚拟化是一个主流的技术,虚拟的,看不见的,但是可以落地的,用于资源管理的一项技术: 2)虚拟化的技术诞生的目标就是为了解决资源管理和资源利用的解决方案: 3)虚拟化就是将物 ...

  2. 给Python IDLE添加行号显示

    转载:https://blog.csdn.net/howard2005/article/details/104112297 文章目录一.引出问题1.Spyder编辑Python程序能显示行号2.Pyt ...

  3. 【题解】[USACO12MAR]Cows in a Skyscraper G

    题目链接 题目大意:给定一个集合\(S\),给一个限制条件\(P\),要求划分集合,使得每一个子集\(A\in S\),\(A\)满足限制条件\(P\),且划分总数最小. 注意到数据范围\(n< ...

  4. 111 01 Android 零基础入门 02 Java面向对象 04 Java继承(上)02 继承的实现 01 继承的实现

    111 01 Android 零基础入门 02 Java面向对象 04 Java继承(上)02 继承的实现 01 继承的实现 本文知识点: 继承的实现 说明:因为时间紧张,本人写博客过程中只是对知识点 ...

  5. WGS-84 to Web mercator

    function mercator_encrypt (wgsLat, wgsLon) {   var x = wgsLon * 20037508.34 / 180.;   var y = Math.l ...

  6. 多测师讲解selenium__论坛验证码_处理方法_ 高级讲师肖sir

    1.登录我们搭建的论坛环境 2. 3. 4.

  7. Flask之WTF

    Flask-WTF是什么? 是一个关于表单的扩展库,可以自动生成表单的HTML代码和验证提交的表单数据,并且提供跨站请求伪造(Cross-Site Request Forgery)保护的功能,使用非常 ...

  8. Shell Scripting 笔记

    Shell Scripting Tutorial Variables in the Bourne shell do not have to be declared, as they do in lan ...

  9. 互不侵犯(洛谷P1896)

    题目:在N*N的棋盘里面放k个国王,使他们互不攻击,共有多少种摆放方案.国王能攻击到它上下左右,以及左上左下右上右下八个方向上附近的各一个格子,共8个格子. 输入输出:输入N,K,输出有几种放置方法. ...

  10. CentOS8 安装

    CentOS8 1911 下载 https://mirrors.aliyun.com/centos/8/isos/x86_64/CentOS-8.1.1911-x86_64-dvd1.iso Step ...