链接

题意求能够整除和包含13的数字。

这个比较简单,保留余数及1,然后标记前面是否出现过13就行。

 #include <iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<stdlib.h>
#include<vector>
#include<cmath>
#include<queue>
#include<set>
using namespace std;
#define N 100000
#define LL long long
#define INF 0xfffffff
const double eps = 1e-;
const double pi = acos(-1.0);
const double inf = ~0u>>;
LL n,dp[][][][];
int d[];
LL dfs(int i,bool e,int r,bool o,bool p)
{
if(i==-)
{
return r==&&p;
}
if(!e&&dp[i][r][o][p]!=-)
return dp[i][r][o][p];
int j;
int mk = e?d[i]:;
LL ans = ;
for(j = ; j <= mk ; j++)
{
if(p)
ans+=dfs(i-,e&&j==mk,(r*+j)%,,);
else
{
if(o&&j==)
ans+=dfs(i-,e&&j==mk,(r*+j)%,,);
else if(j==)
ans+=dfs(i-,e&&j==mk,(r*+j)%,,);
else
ans+=dfs(i-,e&&j==mk,(r*+j)%,,);
}
}
return e?ans:dp[i][r][o][p]=ans;
}
LL cal(LL x)
{
int g=;
while(x)
{
d[g++] = x%;
x/=;
}
return dfs(g-,,,,);
}
int main()
{
memset(dp,-,sizeof(dp));
while(cin>>n)
{
cout<<cal(n)<<endl;
}
return ;
}

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