Simple Vedio Intercom System
I. Deployment / Architecture Block Diagram

II. Resources Used
sip proxy server + sip user agent
1. flexisip / freeswitch + linphone / pjsip / libexosip2 + libosip2 + ortp + mediastream2
III. Each module concrete realization
Maybe you don't need to write a single line of code, because all modules are perfect.
1. flexisip
https://github.com/BelleDonneCommunications/flexisip
2. linphone
http://www.linphone.org/sites/default/files/solutions-intercomsystems.pdf
http://www.linphone.org/sites/default/files/solutions-securedcommunications.pdf
3. freeswitch
4. pjsip
Simple Vedio Intercom System的更多相关文章
- A Simple Actions Recognition System
1. Problem Definition There's no doubt that researches and applications on the foundation of videos ...
- a simple machine learning system demo, for ML study.
Machine Learning System introduction This project is a full stack Django/React/Redux app that uses t ...
- Simple Library Management System HDU - 1497(图书管理系统)
Problem Description After AC all the hardest problems in the world , the ACboy 8006 now has nothing ...
- 【HDOJ】1497 Simple Library Management System
链表. #include <cstdio> #include <cstring> #include <cstdlib> #define MAXM 1001 #def ...
- How to Make a Computer Operating System
How to Make a Computer Operating System 如何制作一个操作系统(翻译版) 原文地址:Github:How to Make a Computer Operating ...
- [java]Arrays.copyOf() VS System.arrayCopy()
If we want to copy an array, we can use either System.arraycopy() or Arrays.copyOf(). In this post, ...
- Flume NG Getting Started(Flume NG 新手入门指南)
Flume NG Getting Started(Flume NG 新手入门指南)翻译 新手入门 Flume NG是什么? 有什么改变? 获得Flume NG 从源码构建 配置 flume-ng全局选 ...
- [转]Design Pattern Interview Questions - Part 4
Bridge Pattern, Composite Pattern, Decorator Pattern, Facade Pattern, COR Pattern, Proxy Pattern, te ...
- reds Virtual Memory
Virtual Memory technical specification This document details the internals of the Redis Virtual Memo ...
随机推荐
- HDU 6206 Apple ( 高精度 && 计算几何 && 三点构圆求圆心半径 )
题意 : 给出四个点,问你第四个点是否在前三个点构成的圆内,若在圆外输出"Accepted",否则输出"Rejected",题目保证前三个点不在一条直线上. 分 ...
- k8s上的基础概念和术语
kubernetes基本概念和术语 kubeernetes中的大部分概念如Node,Pod,Replication Controller ,Serverce等都可以看作一种“资源对象”,几乎所有的 ...
- 《SQL Server 2012 T-SQL基础》读书笔记 - 3.联接查询
Chapter 3 Joins Cross Joins(交叉联接)就是返回两个表的笛卡尔积(m行的表cross join一个n行的表得到一个m * n行的结果),它有两种标准SQL语法,第一种: SE ...
- pepflashplayer32_25_0_0_127.dll: 0x59952C6D is not a valid instance ID.
pepflashplayer32_25_0_0_127.dll: 0x59952C6D is not a valid instance ID. . 点进去是提示doctype错误 暂时没有解决---- ...
- 嵌入式Linux之虚拟内存地址空间布局(Virtual Memory Space)
虚拟内存地址空间 Linux内核属于微内核的范畴,内核控制计算机的硬件资源,运行在特权模式:用户态应用程序运行在普通用户模式,无法直接访问硬件资源,必须依托于内核提供的资源,如CPU资源.Memory ...
- find查找特殊权限用法
find查找特殊权限的用法 find選項與參數: 3. 與檔案權限及名稱有關的參數: -name filename:搜尋檔案名稱為 filename 的檔案: -size [+-]SIZE:搜尋比 S ...
- postgresql_action
SELECT * FROM x123_area a LEFT JOIN x123_user_task_brief utb ON utb.ref_area_code = a.area_code WHER ...
- pom.xml文件设置
一个相对完整的maven配置文件 <?xml version="1.0" encoding="UTF-8"?> <project xmlns= ...
- 阶段1 语言基础+高级_1-3-Java语言高级_04-集合_08 Map集合_1_Map集合概述
map集合是双列集合 map有两个泛型.左边K也叫作键 右边V是value
- 小白学数据分析--聚类分析理论之K-means理论篇
小白学数据分析--聚类分析理论之K-means理论篇 聚类分析是一类广泛被应用的分析方法,其算法众多,目前像SAS.Splus.SPSS.SPSS Modeler等分析工具均以支持聚类分析,但是如何使 ...