Codeforces Round #312 (Div. 2) A.Lala Land and Apple Trees
Amr lives in Lala Land. Lala Land is a very beautiful country that is located on a coordinate line. Lala Land is famous with its apple trees growing everywhere.
Lala Land has exactly n apple trees. Tree number i is located in a position xi and has ai apples growing on it. Amr wants to collect apples from the apple trees. Amr currently stands in x = 0 position. At the beginning, he can choose whether to go right or left. He'll continue in his direction until he meets an apple tree he didn't visit before. He'll take all of its apples and then reverse his direction, continue walking in this direction until he meets another apple tree he didn't visit before and so on. In the other words, Amr reverses his direction when visiting each new apple tree. Amr will stop collecting apples when there are no more trees he didn't visit in the direction he is facing.
What is the maximum number of apples he can collect?
The first line contains one number n (1 ≤ n ≤ 100), the number of apple trees in Lala Land.
The following n lines contains two integers each xi, ai ( - 105 ≤ xi ≤ 105, xi ≠ 0, 1 ≤ ai ≤ 105), representing the position of the i-th tree and number of apples on it.
It's guaranteed that there is at most one apple tree at each coordinate. It's guaranteed that no tree grows in point 0.
Output the maximum number of apples Amr can collect.
2
-1 5
1 5
10
3
-2 2
1 4
-1 3
9
3
1 9
3 5
7 10
9
In the first sample test it doesn't matter if Amr chose at first to go left or right. In both cases he'll get all the apples.
In the second sample test the optimal solution is to go left to x = - 1, collect apples from there, then the direction will be reversed, Amr has to go to x = 1, collect apples from there, then the direction will be reversed and Amr goes to the final tree x = - 2.
In the third sample test the optimal solution is to go right to x = 1, collect apples from there, then the direction will be reversed and Amr will not be able to collect anymore apples because there are no apple trees to his left.
题解:正负贪心一下,注意两边相等的情况。
#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<queue>
#include<cstring>
#define PAU putchar(' ')
#define ENT putchar('\n')
using namespace std;
inline int read(){
int x=,sig=;char ch=getchar();
while(!isdigit(ch)){if(ch=='-')sig=-;ch=getchar();}
while(isdigit(ch))x=*x+ch-'',ch=getchar();
return x*=sig;
}
inline void write(int x){
if(x==){putchar('');return;}if(x<)putchar('-'),x=-x;
int len=,buf[];while(x)buf[len++]=x%,x/=;
for(int i=len-;i>=;i--)putchar(buf[i]+'');return;
}
void init(){
int n=read(),neg=;
pair<int,int>a[n];
for(int i=;i<n;i++){
a[i].first=read();a[i].second=read();
if(a[i].first<)neg++;
}sort(a,a+n);
int sol=;
if((neg<<)<n)for(int i=;i<min((neg<<)+,n);i++)sol+=a[i].second;
else for(int i=max((neg<<)-n-,);i<n;i++)sol+=a[i].second;
write(sol);
return;
}
void work(){
return;
}
void print(){
return;
}
int main(){init();work();print();return ;}
Codeforces Round #312 (Div. 2) A.Lala Land and Apple Trees的更多相关文章
- Codeforces Round #312 (Div. 2) A. Lala Land and Apple Trees 暴力
A. Lala Land and Apple Trees Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/cont ...
- 【打CF,学算法——二星级】Codeforces Round #312 (Div. 2) A Lala Land and Apple Trees
[CF简单介绍] 提交链接:A. Lala Land and Apple Trees 题面: A. Lala Land and Apple Trees time limit per test 1 se ...
- 【Codeforces #312 div2 A】Lala Land and Apple Trees
# [Codeforces #312 div2 A]Lala Land and Apple Trees 首先,此题的大意是在一条坐标轴上,有\(n\)个点,每个点的权值为\(a_{i}\),第一次从原 ...
- Codeforces Round #312 (Div. 2) ABC题解
[比赛链接]click here~~ A. Lala Land and Apple Trees: [题意]: AMR住在拉拉土地. 拉拉土地是一个很漂亮的国家,位于坐标线.拉拉土地是与著名的苹果树越来 ...
- Codeforces Round #312 (Div. 2)
好吧,再一次被水题虐了. A. Lala Land and Apple Trees 敲码小技巧:故意添加两个苹果树(-1000000000, 0)和(1000000000, 0)(前者是位置,后者是价 ...
- codeforces 558A A. Lala Land and Apple Trees(水题)
题目链接: A. Lala Land and Apple Trees time limit per test 1 second memory limit per test 256 megabytes ...
- 【42.07%】【codeforces 558A】Lala Land and Apple Trees
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...
- Codeforces Round #312 (Div. 2) C. Amr and Chemistry 暴力
C. Amr and Chemistry Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/558/ ...
- Codeforces Round #312 (Div. 2)B. Amr and The Large Array 暴力
B. Amr and The Large Array Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contes ...
随机推荐
- erlang怎样有效监听大量并发连接
看了erlang的一些开源网络框架RabbitMQ.Ranch.他们都使用多个进程同一时候accept一个socket. 这样的方式在使得socketport监听的工作分担了很多其它的调度机会.可是, ...
- 【足迹C++primer】表达式求值
表达式求值 /** * 功能:表达式求值(0到9) * 时间:2014年6月15日08:02:31 * 作者:cutter_point */ #include<stdlib.h> #inc ...
- Java之多线程断点下载的实现
RandomAccessFile类: 此类的实例支持对随机訪问文件的读取和写入.随机訪问文件的行为相似存储在文件系统中的一个大型 byte 数组. 存在指向该隐含数组.光标或索引,称为文件指针.输入操 ...
- mybatis3温故
MyBatis可以利用SQL映射文件来配置,也可以利用Annotation来设置.MyBatis提供的一些基本注解如下表所示. 注解 目标 相应的XML 描述 @CacheNamespace 类 &l ...
- sparkSQL1.1入门之二:sparkSQL执行架构
在介绍sparkSQL之前.我们首先来看看,传统的关系型数据库是怎么执行的.当我们提交了一个非常easy的查询: SELECT a1,a2,a3 FROM tableA Where con ...
- Codeforces Round #258 (Div. 2)[ABCD]
Codeforces Round #258 (Div. 2)[ABCD] ACM 题目地址:Codeforces Round #258 (Div. 2) A - Game With Sticks 题意 ...
- The builder launch configuration could not be found
Export Wizard Error Errors occurred during the build Problems occured when invoking code from p ...
- 那些年不错的Android开源项目(转)
第一部分 个性化控件(View) 主要介绍那些不错个性化的View,包括ListView.ActionBar.Menu.ViewPager.Gallery.GridView.ImageView.Pro ...
- Linux入门之——安装虚拟机软件
/** ****************************************************************************** * @author 暴走的小 ...
- .net之页面生面周期
# 事件或方法 功能 描述 1 Init 事件 页面初始化 页面生存周期中的第一个阶段是初始化.当 Init 事件发生时,在.aspx 源文件中静态声明的所有控件都已实例化并取其默认值.应该注意的是, ...