Oracle绝对秒数转换为时间戳

一般Oracle得到的时间格式为：

1970-01-05 01:23:56.297

为了计算两个时间的差值：

1970-01-05 01:23:56.297 与 1970-01-05 01:24:57.432

Python代码如下：

#!/usr/bin/python3.4
# -*- coding: utf-8 -*-

import time

def Caltime(date1, date2):
    # 格式化时间
    date1 = time.strptime(date1, "%Y-%m-%d %H:%M:%S.%f")
    date2 = time.strptime(date2, "%Y-%m-%d %H:%M:%S.%f")
    # 转化为时间戳
    date1 = time.mktime(date1)
    date2 = time.mktime(date2)

    date = date2 - date1
    return date

if __name__ == '__main__':
    date1 = "1970-01-05 01:23:56.297"
    date2 = "1970-01-05 01:24:57.432"
    result = Caltime(date1, date2)
    print(result)
    # 61.0