POJ 2350 Above Average

Description

It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.

Input

The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and 100) of a student in the class.

Output

For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.

Sample Input

5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91

Sample Output

40.000%
57.143%
33.333%
66.667%
55.556%

简单题 求分数超过平均分的学生的比例
来看一下WA和AC的代码
下面是WA的

 #include<stdio.h>
 int sco[+];
 int main()
 {
     int T,n,i;
     double ave;
     double res;
     scanf("%d",&T);
     while(T--)
     {
         scanf("%d",&n);
         ave=0.0;res=0.0;
         for(i=;i<n;i++)
         {
             scanf("%d",&sco[i]);
             ave+=double(sco[i]);
         }
         ave/=double(n);
         for( i=;i<n;i++)
         {
             if(sco[i]>ave)res+=1.0;
         }
         res/=n;res*=;
         printf("%.3lf%%\n",res);
     }
     return ;
 }

下面是AC的

 #include<stdio.h>
 int sco[+];
 int main()
 {
     int T,n,i;
     float ave;
     float res;
     scanf("%d",&T);
     while(T--)
     {
         scanf("%d",&n);
         ave=0.0;res=0.0;
         for(i=;i<n;i++)
         {
             scanf("%d",&sco[i]);
             ave+=float(sco[i]);
         }
         ave/=float(n);
         for( i=;i<n;i++)
         {
             if(sco[i]>ave)res+=1.0;
         }
         res/=n;res*=100.0;
         printf("%.3f%%\n",res);
     }
     return ;
 }

就是把double改成了float......