先给出递归版本的实现方法,有时间再弄个循环版的。代码如下:

 /**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> postorderTraversal(TreeNode *root) {
vector<int> nodeValues;
if (root == NULL) return nodeValues;
postorderTraversal_Rec(root,nodeValues); return nodeValues;
}
private: void postorderTraversal_Rec(TreeNode *root, vector<int>& nodeValues){
if (root == NULL) return;
if (root->left != NULL) postorderTraversal_Rec(root->left,nodeValues);
if (root->right != NULL) postorderTraversal_Rec(root->right,nodeValues); nodeValues.push_back(root->val);
} };

leetcode Binary Tree Postorder Traversal 二叉树后续遍历的更多相关文章

  1. [LeetCode] Binary Tree Postorder Traversal 二叉树的后序遍历

    Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary ...

  2. [Leetcode] Binary tree postorder traversal二叉树后序遍历

    Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary t ...

  3. C++版 - LeetCode 145: Binary Tree Postorder Traversal(二叉树的后序遍历,迭代法)

    145. Binary Tree Postorder Traversal Total Submissions: 271797 Difficulty: Hard 提交网址: https://leetco ...

  4. [LeetCode] Binary Tree Inorder Traversal 二叉树的中序遍历

    Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tre ...

  5. [LeetCode] Binary Tree Preorder Traversal 二叉树的先序遍历

    Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tr ...

  6. LeetCode: Binary Tree Postorder Traversal 解题报告

    Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' va ...

  7. [LeetCode] 145. Binary Tree Postorder Traversal 二叉树的后序遍历

    Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary ...

  8. LeetCode 145. Binary Tree Postorder Traversal二叉树的后序遍历 (C++)

    题目: Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,nul ...

  9. leetcode题解:Binary Tree Postorder Traversal (二叉树的后序遍历)

    题目: Given a binary tree, return the postorder traversal of its nodes' values. For example:Given bina ...

随机推荐

  1. 自己动手写CPU 笔记

    自己动手写CPU 跳转至: 导航. 搜索 文件夹 1 处理器与MIPS 2 可编程逻辑器件与Verilog HDL 3 教学版OpenMIPS处理器蓝图 4 第一条指令ori 5 逻辑.移位与nop ...

  2. NYOJ353 3D dungeon 【BFS】

    3D dungeon 时间限制:1000 ms  |  内存限制:65535 KB 难度:2 描写叙述 You are trapped in a 3D dungeon and need to find ...

  3. Codeforces Round #191 (Div. 2)---A. Flipping Game

    Flipping Game time limit per test 1 second memory limit per test 256 megabytes input standard input ...

  4. 1711 Number Sequence(kmp)

    Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], .... ...

  5. AMR音频文件格式分析

    AMR音频文件格式分析 1 概要 如今非常多智能手机都支持多媒体功能,特别是音频和视频播放功能,而AMR文件格式是手机端普遍支持的音频文件格式.AMR,全称是:Adaptive Multi-Rate, ...

  6. mysql只导出表结构或数据

    唯一的非导电结构指南数据 mysqldump -t 数据库名称 -uroot -p > xxx.sql 指南结构不仅指导数据 mysqldump    --opt -d  数据库名 -u -p ...

  7. React实践(一)

    该实践取自官方教程:https://github.com/reactjs/react-tutorial 主要是自实现的过程以及一些心得体会 该实践是实现一个评论框. 一个展示所有评论的视图 一个提交评 ...

  8. android之【本地通知Notification】

    public class NotificationTest extends Activity { static final int NOTIFICATION_ID = 0x1123; @Overrid ...

  9. Swift 语言概览 -自己在Xcode6 动手写1

    原文:Swift 语言概览 -自己在Xcode6 动手写1 Swift是什么? Swift是苹果于WWDC 2014发布的编程语言,这里引用The Swift Programming Language ...

  10. RPC和RMI的区别(Difference Between RPC and RMI)

    RPC和RMI的区别(Difference Between RPC and RMI) RPC vs RMI RPC (Remote Procedure Call) and RMI (Remote Me ...