Two Sum II – Input array is sorted

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Question:

Similar to Question [1. Two Sum], except that the input array is already sorted in

ascending order.

同上题:先排序,然后从开头和结尾同时向中间查找,原理也比较简单。O(nlogn) runtime, O(1) space

vector<int> twoSumSored(vector<int>& nums, int target){

vector<int> vecCopy(nums);

int i=0,n=2,l=0,r = nums.size()-1;

sort(vecCopy.begin(),vecCopy.end());

int j=nums.size()-1;

while(i<j)

{

int sum = nums[i]+nums[j];

if (sum <target)

{

i++;

}

else if (sum > target)

{

j--;

}

else

{

vector<int> index;

index.push_back(i+1);

index.push_back(j+1);

return index;

}

}

}

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