LeetCode Single Number (找不不重复元素)
题意:给一个序列,序列中只有1个是单个的,其他都是成对出现的。也就是序列中有奇数个元素。要求找出这个元素。
思路:成对出现用异或最好了。两个同样的数一异或就变零,剩下的,就是那个落单的。
class Solution {
public:
int singleNumber(vector<int>& nums) {
int res=;
for(int i=; i<nums.size(); i++)
res^=nums[i];
return res;
}
};
AC代码
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