LeetCode & list cycle

链表是否存在环检测

singly-linked list

单链表

"use strict";

/**
*
* @author xgqfrms
* @license MIT
* @copyright xgqfrms
* @created 2020-11-17
* @modified
*
* @description 链表
* @difficulty Easy Medium Hard
* @complexity O(n)
* @augments
* @example
* @link
* @solutions
*
* @best_solutions
*
*/ const log = console.log; // 节点
function ListNode(val, next) {
this.val = 0 || val;
this.next = null || next;
} // 链表
function LinkedList(value) {
const node = new ListNode(value, ``);
if(!head) {
head = node;
} else {
let current = head;
while(current.next) {
current = current.next;
}
current.next = node;
}
};

two-pointers

双指针 / 快慢指针

Object 循环引用错误

/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/ /**
* @param {ListNode} head
* @return {boolean}
*/
var hasCycle = function(head) {
let result = false;
try {
JSON.stringify(head);
// result = false;
} catch(err) {
result = true;
}
return result;
};

refs

https://leetcode.com/problemset/all/?topicSlugs=two-pointers

https://leetcode.com/problems/linked-list-cycle



xgqfrms 2012-2020

www.cnblogs.com 发布文章使用:只允许注册用户才可以访问!


LeetCode & list cycle的更多相关文章

  1. [LeetCode]LinkedList Cycle

    题目说明 Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without usi ...

  2. [LeetCode] Linked List Cycle II 单链表中的环之二

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  3. [LeetCode] Linked List Cycle 单链表中的环

    Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using ex ...

  4. Java for LeetCode 142 Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  5. [LeetCode]Linked List Cycle II解法学习

    问题描述如下: Given a linked list, return the node where the cycle begins. If there is no cycle, return nu ...

  6. LeetCode解题报告:Linked List Cycle && Linked List Cycle II

    LeetCode解题报告:Linked List Cycle && Linked List Cycle II 1题目 Linked List Cycle Given a linked ...

  7. LeetCode——Linked List Cycle

    Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using ex ...

  8. [LeetCode] 141&142 Linked List Cycle I & II

    Problem: Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without ...

  9. LeetCode——Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

随机推荐

  1. 干货 | 携程Redis治理演进之路(二)

    https://mp.weixin.qq.com/s/QTqcBZlAhp5cLRJGJVZRNw 干货 | 携程Redis治理演进之路(二) 原创 技术中心 携程技术 2020-12-24     ...

  2. 项目action:前台传多个dataWrap给后台

    业务描述:当前台需要向后台传递多个dataWrap时,需要给后台action加上一段方法,才可以获取到额外的dataWrap. @Override public List<String> ...

  3. DEDECMS:安装百度UEDITOR编辑器

    第一步:下载相对应编辑器的版本 首先,去百度搜索"百度ueditor编辑器",然后点击进入官网,找到下载页面.找到我们想要的编辑器的版本,看自己网站的编码是UTF-8还是GBK,下 ...

  4. UI自动化实战进阶PO设计模式

    前言 经过前面的实战我们已经编写了几个测试用例,下面我们要用PO设计模式来调整我们的代码,让页面元素和测试业务进行分离,这样看起来直观而且后期的维护也方便. python有一个第三方的PO设计的库,既 ...

  5. Flink-v1.12官方网站翻译-P013-Timely Stream Processing

    及时的流处理 介绍 及时流处理是有状态流处理的一种扩展,其中时间在计算中起着一定的作用.其中,当你做时间序列分析时,当做基于某些时间段(通常称为窗口)的聚合时,或者当你做事件处理时,事件发生的时间很重 ...

  6. linux(3) 处理目录的常用命令

    目录命令总览 ls(英文全拼:list files): 列出目录及文件名 cd(英文全拼:change directory):切换目录 pwd(英文全拼:print work directory):显 ...

  7. 2020牛客暑期多校训练营(第五场)B - Graph (异或 最小生成树 分治 Trie)

    B - Graph 题目链接 每次操作不会改变两点之间的路径异或和 以 1 号点为起点,算出任意一点到 1 号点的异或值 dis[i](把该值当做 i 号点权值), 那么任意两点的异或值为 \(dis ...

  8. [CERC2014]Virus synthesis【回文自动机+DP】

    [CERC2014]Virus synthesis 初始有一个空串,利用下面的操作构造给定串 SS . 1.串开头或末尾加一个字符 2.串开头或末尾加一个该串的逆串 求最小化操作数, \(|S| \l ...

  9. 【noi 2.6_2988】计算字符串距离(DP)

    题意: 给两个字符串,可以增.删.改,问使这两个串变为相同的最小操作数. 解法:(下面2种的代码主要区别在初始化和,而状态转移方程大家可挑自己更容易理解的方法打) 1.f[i][j]表示a串前i个和b ...

  10. Gym 100796K Profact

    Alice is bored out of her mind by her math classes. She craves for something much more exciting. Tha ...