Codeforces Round #360 (Div. 2) B. Lovely Palindromes 水题
B. Lovely Palindromes
题目连接:
http://www.codeforces.com/contest/688/problem/B
Description
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindrome numbers. Pari loves integers with even length (i.e. the numbers with even number of digits), so she tries to see a lot of big palindrome numbers with even length (like a 2-digit 11 or 6-digit 122221), so maybe she could see something in them.
Now Pari asks you to write a program that gets a huge integer n from the input and tells what is the n-th even-length positive palindrome number?
Input
The only line of the input contains a single integer n (1 ≤ n ≤ 10100 000).
Output
Print the n-th even-length palindrome number.
Sample Input
1
Sample Output
11
Hint
题意
给你n,问你第n个偶数长度的回文数是哪个
题解
一眼题……
正着输出一遍,再倒着输出一遍就好了。
代码
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
cout<<s;
for(int i=s.size()-1;i>=0;i--)
cout<<s[i];
cout<<endl;
}
Codeforces Round #360 (Div. 2) B. Lovely Palindromes 水题的更多相关文章
- Codeforces Round #360 (Div. 2) C. NP-Hard Problem 水题
C. NP-Hard Problem 题目连接: http://www.codeforces.com/contest/688/problem/C Description Recently, Pari ...
- Codeforces Round #367 (Div. 2) A. Beru-taxi (水题)
Beru-taxi 题目链接: http://codeforces.com/contest/706/problem/A Description Vasiliy lives at point (a, b ...
- Codeforces Round #334 (Div. 2) A. Uncowed Forces 水题
A. Uncowed Forces Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/604/pro ...
- Codeforces Round #353 (Div. 2) A. Infinite Sequence 水题
A. Infinite Sequence 题目连接: http://www.codeforces.com/contest/675/problem/A Description Vasya likes e ...
- Codeforces Round #327 (Div. 2) A. Wizards' Duel 水题
A. Wizards' Duel Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/prob ...
- Codeforces Round #146 (Div. 1) A. LCM Challenge 水题
A. LCM Challenge 题目连接: http://www.codeforces.com/contest/235/problem/A Description Some days ago, I ...
- Codeforces Round #335 (Div. 2) B. Testing Robots 水题
B. Testing Robots Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606 ...
- Codeforces Round #335 (Div. 2) A. Magic Spheres 水题
A. Magic Spheres Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606/ ...
- Codeforces Round #306 (Div. 2) A. Two Substrings 水题
A. Two Substrings Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/550/pro ...
随机推荐
- 【LinuxC】GCC编译C程序,关闭随机基址
1.编译.链接和运行程序 C代码示例: #include <stdio.h> #include <stdlib.h> int main() { printf("hel ...
- [转载]Windows服务编写原理及探讨(3)
(三)对服务的深入讨论之下 现在我们还剩下一个函数可以在细节上讨论,那就是服务的CtrlHandler函数. 当调用RegisterServiceCtrlHandler函数时,SCM得到并保存这个回调 ...
- Nginx - Header详解
1. 前言 通过 HttpHeadersModule 模块可以设置HTTP头,但是不能重写已经存在的头,比如可能相对server头进行重写,可以添加其他的头,例如:Cache-Control,设置生存 ...
- Jdk 和 Tomcat的 安装。
1.再分发服务器上下载JDK,然后利用xftp上传到聚石塔等 2. 解压: tar -zxvf jdk-8u121-linux-x64.tar.gz 3.配置环境变量: export JAVA_HOM ...
- LeetCode403. Frog Jump
A frog is crossing a river. The river is divided into x units and at each unit there may or may not ...
- hdu 5078(2014鞍山现场赛 I题)
数据 表示每次到达某个位置的坐标和时间 计算出每对相邻点之间转移的速度(两点间距离距离/相隔时间) 输出最大值 Sample Input252 1 9//t x y3 7 25 9 06 6 37 6 ...
- 使用celery时要注意的任务调用形式
因为之前,一直用django和celery紧密集成,不分家. 所以使用时参考了网上的配置之后,没有变更过. 最近,和洪军想用k8s的pod重新规划系统构架时,这个问题才又浮了出来. 只是我们的task ...
- Hive(八)Hive的Shell操作与压缩存储
一.Hive的命令行 1.Hive支持的一些命令 Command Description quit Use quit or exit to leave the interactive shell. s ...
- USACO 4.3 Street Race
Street RaceIOI'95 Figure 1 gives an example of a course for a street race. You see some points, labe ...
- php中empty和isset函数
函数使用格式 empty bool empty ( mixed $var ) 判断变量是否为空. isset bool isset ( mixed $var [ , mixed $... ] ) 判断 ...