Codeforces Round #350 (Div. 2) B. Game of Robots 水题
B. Game of Robots
题目连接:
http://www.codeforces.com/contest/670/problem/B
Description
In late autumn evening n robots gathered in the cheerful company of friends. Each robot has a unique identifier — an integer from 1 to 109.
At some moment, robots decided to play the game "Snowball". Below there are the rules of this game. First, all robots stand in a row. Then the first robot says his identifier. After that the second robot says the identifier of the first robot and then says his own identifier. Then the third robot says the identifier of the first robot, then says the identifier of the second robot and after that says his own. This process continues from left to right until the n-th robot says his identifier.
Your task is to determine the k-th identifier to be pronounced.
Input
The first line contains two positive integers n and k (1 ≤ n ≤ 100 000, 1 ≤ k ≤ min(2·109, n·(n + 1) / 2).
The second line contains the sequence id1, id2, ..., idn (1 ≤ idi ≤ 109) — identifiers of roborts. It is guaranteed that all identifiers are different.
Output
Print the k-th pronounced identifier (assume that the numeration starts from 1).
Sample Input
2 2
1 2
Sample Output
1
题意
每个人都有自己的名字
现在在玩一个游戏,叫做叫名字
每个人都会叫前面人的名字和自己的名字
现在问你第k个叫的名字是啥
题解:
其实每个人叫了多少,就是一个前缀和
统计一下,然后直接输出就好了
代码
#include<bits/stdc++.h>
using namespace std;
const int maxn = 1e5+7;
int n,m,a[maxn],sum;
int main()
{
scanf("%d%d",&n,&m);
for(int i=1;i<=n;i++)scanf("%d",&a[i]);
for(int i=1;i<=n;i++)
{
sum+=i;
if(sum>=m)
{
sum=i-(sum-m);
cout<<a[sum]<<endl;
break;
}
}
return 0;
}
Codeforces Round #350 (Div. 2) B. Game of Robots 水题的更多相关文章
- Codeforces Round #297 (Div. 2)A. Vitaliy and Pie 水题
Codeforces Round #297 (Div. 2)A. Vitaliy and Pie Time Limit: 2 Sec Memory Limit: 256 MBSubmit: xxx ...
- Codeforces Round #290 (Div. 2) A. Fox And Snake 水题
A. Fox And Snake 题目连接: http://codeforces.com/contest/510/problem/A Description Fox Ciel starts to le ...
- Codeforces Round #322 (Div. 2) A. Vasya the Hipster 水题
A. Vasya the Hipster Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/581/p ...
- Codeforces Round #373 (Div. 2) B. Anatoly and Cockroaches 水题
B. Anatoly and Cockroaches 题目连接: http://codeforces.com/contest/719/problem/B Description Anatoly liv ...
- Codeforces Round #368 (Div. 2) A. Brain's Photos 水题
A. Brain's Photos 题目连接: http://www.codeforces.com/contest/707/problem/A Description Small, but very ...
- Codeforces Round #359 (Div. 2) A. Free Ice Cream 水题
A. Free Ice Cream 题目连接: http://www.codeforces.com/contest/686/problem/A Description After their adve ...
- Codeforces Round #355 (Div. 2) A. Vanya and Fence 水题
A. Vanya and Fence 题目连接: http://www.codeforces.com/contest/677/problem/A Description Vanya and his f ...
- Codeforces Round #384 (Div. 2) A. Vladik and flights 水题
A. Vladik and flights 题目链接 http://codeforces.com/contest/743/problem/A 题面 Vladik is a competitive pr ...
- Codeforces Round #379 (Div. 2) D. Anton and Chess 水题
D. Anton and Chess 题目连接: http://codeforces.com/contest/734/problem/D Description Anton likes to play ...
随机推荐
- SELinux 入门【转】
一.前言 安全增强型 Linux(Security-Enhanced Linux)简称 SELinux,它是一个 Linux 内核模块,也是 Linux 的一个安全子系统.SELinux 主要由美国国 ...
- PHP在引号前面添加反斜杠的原因及PHP去除反斜杠的办法
昨天用PHP做了个读写html文档的小程序,本地测试正常但是传到网站后发现,提交内容保存的时候会自动在双引号前面增加一个反斜杠“\”,而且每保存一次增加一个反斜杠,很是郁闷. 当然做这个只是为了参加电 ...
- 如何同步删除svn管理的package包目录
转:https://blog.csdn.net/shiwodecuo/article/details/51754598 eclipse在实际的开发中,当我们的项目由svn进行管理时,若想删除选中的整个 ...
- 数据库-mysql安装
MySQL 安装 所有平台的Mysql下载地址为: MySQL 下载. 挑选你需要的 MySQL Community Server 版本及对应的平台. Linux/UNIX上安装Mysql Linux ...
- IE手工导入证书
打开cer文件->欢迎使用证书导入向导->下一步->将所有的证书放入下列存储->受信任的根证书颁发机构->完成
- windows下redis服务操作
安装redis服务redis-server --service-install redis.windows.conf --service-name Redis26380 --loglevel verb ...
- 深度学习国外课程资料(Deep Learning for Self-Driving Cars)+(Deep Reinforcement Learning and Control )
MIT(Deep Learning for Self-Driving Cars) CMU(Deep Reinforcement Learning and Control ) 参考网址: 1 Deep ...
- 压力测试随笔之:JMeter,LoadRunner 相得益彰
做压力测试,我喜欢先写 JMeter 脚本,功能测通以后再翻译成 LoadRunner 脚本,最后用 LoadRunner 完成压测.也许我是 Java 出身吧,对 JMeter 总是有一种亲切感用着 ...
- hdu 5120(求两个圆环相交的面积 2014北京现场赛 I题)
两个圆环的内外径相同 给出内外径 和 两个圆心 求两个圆环相交的面积 画下图可以知道 就是两个大圆交-2*小圆与大圆交+2小圆交 Sample Input22 30 00 02 30 05 0 Sam ...
- 铁轨(UVa 514)
利用栈实现 C++11 代码如下: #include<iostream> #include<stack> using namespace std; #define maxn 1 ...