package com.lw.leet1;

 import java.util.Stack;

 /**
* @ClassName:Solution
* @Description:
* Reverse Words in a String
* Total Accepted: 26194 Total Submissions: 187094 My Submissions
* Given an input string, reverse the string word by word.
*
* For example
* Given s = "the sky is blue"
* return "blue is sky the".
*
* Clarification:
* What constitutes a word?
* A sequence of non-space characters constitutes a word.
* Could the input string contain leading or trailing spaces?
* Yes. However, your reversed string should not contain leading or trailing spaces.
* How about multiple spaces between two words?
* Reduce them to a single space in the reversed string.
*
* @Author LiuWei
* @Date 2014年8月15日下午7:48:48
* @Mail nashiyue1314@163.com
*/
public class Solution { public String reverseWords(String word){
Stack<String> sstack = new Stack<String>();
int flag = 0;
for(int i= 0; i<word.length(); i++){
while(i<word.length() && word.charAt(i)==' '){
i++;
}
flag = i;
while(i<word.length() && word.charAt(i)!=' '){
i++;
}
if(flag != i){
sstack.push(word.substring(flag, i));
}
}
String res = "";
while(!sstack.isEmpty()){
res += sstack.pop()+" ";
}
// The input string which is made up of space
if(res.length()==0){
return "";
}
return res.substring(0, res.length()-1);
} public String reverseWords2(String word){
String res ="";
int flag = 0;
for(int i= 0; i<word.length(); i++){
while(i<word.length() && word.charAt(i)==' '){
i++;
}
flag = i;
while(i<word.length() && word.charAt(i)!=' '){
i++;
}
if(flag != i){
res = word.substring(flag, i)+" "+res;
}
}
// The input string which is made up of space
if(res.length()==0){
return "";
}
return res.substring(0, res.length()-1);
} public static void main(String[] args){
Solution s = new Solution();
System.out.println(s.reverseWords2(" hello world "));
}
}

LeetCode-Reverse Words in a String[AC源码]的更多相关文章

  1. LeetCode: Reverse Words in a String:Evaluate Reverse Polish Notation

    LeetCode: Reverse Words in a String:Evaluate Reverse Polish Notation Evaluate the value of an arithm ...

  2. LeetCode Reverse Words in a String II

    原题链接在这里:https://leetcode.com/problems/reverse-words-in-a-string-ii/ 题目: Given an input string, rever ...

  3. [LeetCode] Reverse Vowels of a String 翻转字符串中的元音字母

    Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Giv ...

  4. [LeetCode] Reverse Words in a String II 翻转字符串中的单词之二

    Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...

  5. [LeetCode] Reverse Words in a String 翻转字符串中的单词

    Given an input string, reverse the string word by word. For example, Given s = "the sky is blue ...

  6. [LeetCode] Reverse Words in a String III 翻转字符串中的单词之三

    Given a string, you need to reverse the order of characters in each word within a sentence while sti ...

  7. LeetCode: Reverse Words in a String 解题报告

    Reverse Words in a String Given an input string, reverse the string word by word. For example,Given ...

  8. java.lang.String 类源码解读

    String类定义实现了java.io.Serializable, Comparable<String>, CharSequence 三个接口:并且为final修饰. public fin ...

  9. 翻String.Format源码发现的新东西:StringBuilderCache

    起因: 记不清楚今天是为毛点想F12看String.Format的实现源码了,反正就看到了下图的鸟东西: 瞬间石化有没有,StringBuilder还能这么获取? 研究StringBuilderCac ...

随机推荐

  1. 谈谈javascript中的变量提升还有函数提升

    在很多面试题中,经常会看到关于变量提升,还有函数提升的题目,所以我就写一篇自己理解之后的随笔,方便之后的查阅和复习. 首先举个例子 foo();//undefined function foo(){ ...

  2. 第六次作业psp

    psp 进度条 代码累积折线图 博文累积折线图 psp饼状图

  3. tensorflow之曲线拟合

    视频链接:https://morvanzhou.github.io/tutorials/machine-learning/ML-intro/ 1.定义层 定义 add_layer() from __f ...

  4. 博弈---ZOJ 2083 Win the Game(染绳子)

    原题:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2083 大意:两个人分别对n条绳子染 每次染m长 最后染不下的输,问先 ...

  5. lintcode-512-解码方法

    512-解码方法 有一个消息包含A-Z通过以下规则编码 'A' -> 1 'B' -> 2 ... 'Z' -> 26 现在给你一个加密过后的消息,问有几种解码的方式 样例 给你的消 ...

  6. 使用kdump内核调试工具遇到的问题及解决

    修改linux内核代码或者内核模块的时候,搞不好就会造成linux死机崩溃,crash死机后/var/log/kern.log里面不会有任何异常信息记录.这时候kdump就会派上用场了,网上kdump ...

  7. 在.net项目中使用Consul

    1.创建.net core web程序并运行 2.在Consul中注册该服务 Consul支持两种服务注册的方式,一种是通过Consul的服务注册HTTP API,由服务自身在启动后调用API注册自己 ...

  8. 定时器应用-点击按钮,div向右移动

    需求是点击button,div就一直往右移动,给个条件left=800px就停止移动,通过定时器来控制. 代码如下: <!DOCTYPE html> <html> <he ...

  9. 数学口袋精灵感受与BUG

    232朱杰 http://www.cnblogs.com/alfredzhu https://github.com/alfredzhu/ 组长,团队 230蔡京航 http://www.cnblogs ...

  10. Scrum冲刺博客汇总

    第一篇 Scrum冲刺博客 http://www.cnblogs.com/LZTZ/p/8886296.html 第二篇 Scrum冲刺博客 http://www.cnblogs.com/LZTZ/p ...