UVa-401 Palindromes回文词

虽然是水题，但是容易错。参照了紫书的代码可以写的很简洁。主要还是注意常量数组的使用，能让代码变得简单许多

 #include <iostream>
 #include <cstdio>
 #include <string.h>
 #include <algorithm>
 #include <stack>
 #include <math.h>
 #pragma warning ( disable : 4996 )

 using namespace std;

 int Max( int a, int b ) { return a>b?a:b; }
 int Min( int a, int b ) { return a>b?b:a; }

 const int inf = 0x3f3f3f3f;
 const int maxn =  + ;
 const char T[] = "A...3..HIL.JM.O...2TUVWXY51SE.Z..8.";
 char test[];

 char getM( char c )
 {
     if (isalpha(c)) return T[c-'A'];
     else return T[c-''+];
 }
 int main()
 {
     while ( ~scanf("%s", test) )
     {
         int len = strlen(test);
         bool isP = true, isM = true;
         for ( int i = ; i < (len+) / ; i++ )
         {
             if ( test[i] != test[len--i] ) isP = false;
             if ( getM(test[i]) != test[len--i] ) isM = false;
         }
         if ((!isP)&&(!isM)) printf( "%s -- is %s\n\n", test, "not a palindrome." );
         if (isP&&(!isM)) printf( "%s -- is %s\n\n", test, "a regular palindrome." );
         if ((!isP)&&isM) printf( "%s -- is %s\n\n", test, "a mirrored string." );
         if (isP&&isM) printf( "%s -- is %s\n\n", test, "a mirrored palindrome." );
     }
     return ;
 }