删除DOM节点应用

<!-- HTML结构 -->
<ul id="test-list">
    <li>JavaScript</li>
    <li>Swift</li>
    <li>HTML</li>
    <li>ANSI C</li>
    <li>CSS</li>
    <li>DirectX</li>
</ul>

删除与web开发无关的节点

方法一：

document.querySelectorAll("#test-list li").forEach(function(e){console.log(e.innerHTML);
if(['Swift','ANSI C','DirectX'].indexOf(e.innerHTML)>-1)e.remove();
});

方法二：

var li = document.getElementById("test-list")
Array.from(li.children).filter(x=>!['JavaScript', 'HTML', 'CSS'].includes(x.innerHTML)).forEach(x=>li.removeChild(x))

方法三：

var web = ["JavaScript", "HTML", "CSS"];
var ul = document.getElementById("test-list");
var arrLi = ul.children;

for (var item of arrLi) {
  if (web.indexOf(item.innerText) === -1) {
    ul.removeChild(item);
  }
}

方法一跟二都比较简练。

测试：

;(function () {
    var
        arr, i,
        t = document.getElementById('test-list');
    if (t && t.children && t.children.length === 3) {
        arr = [];
        for (i = 0; i < t.children.length; i ++) {
            arr.push(t.children[i].innerText);
        }
        if (arr.toString() === ['JavaScript', 'HTML', 'CSS'].toString()) {
            alert('测试通过!');
        }
        else {
            alert('测试失败: ' + arr.toString());
        }
    }
    else {
        alert('测试失败!');
    }
})();

内容摘自https://www.liaoxuefeng.com/wiki/001434446689867b27157e896e74d51a89c25cc8b43bdb3000/001435997163473d309006809fa43abbba322be3eb090a8000