python小练手题1

1.
"""
Write a program which can compute the factorial of a given numbers.
The results should be printed in a comma-separated sequence on a single line.
Suppose the following input is supplied to the program:
8
Then, the output should be:
40320
"""
num = int(input('请输入需要计算的数：'))
def fact(num):
    if num == 0:
        return 1
    return num * fact(num-1)

print(fact(num))

2.
"""
With a given integral number n, write a program to generate a dictionary that contains (i, i*i) such that is an integral number between 1 and n (both included). and then the program should print the dictionary.
Suppose the following input is supplied to the program:
8
Then, the output should be:
{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}
"""
num = int(input('请输入'))
d = {}
for i in range(1,num+1):
    d.update({i:i*i})

print(d)

3.
"""
Write a program which accepts a sequence of comma-separated numbers from console and generate a list and a tuple which contains every number.
Suppose the following input is supplied to the program:
34,67,55,33,12,98
Then, the output should be:
['34', '67', '55', '33', '12', '98']
('34', '67', '55', '33', '12', '98')
"""def spl(word):
    li = []
    for i in word.split(','):
        li.append(i)
    print()
    tup = '('+str(li)[1:-1]+')'
    return print(li,'\n',tup)
word = input("")
spl(word)

4.
"""
Write a program that calculates and prints the value according to the given formula:
Q = Square root of [(2 * C * D)/H]
Following are the fixed values of C and H:
C is 50. H is 30.
D is the variable whose values should be input to your program in a comma-separated sequence.
Example
Let us assume the following comma separated input sequence is given to the program:
100,150,180
The output of the program should be:
18,22,24
"""
import math
def fun(D):
    C = 50
    H = 30
    li = []
    for d in D.split(','):
        Q = int(math.sqrt((2 * C * int(d)) / H))
        li.append(Q)
    return print(str(li)[1:-1])

D = input()
fun(D)

5.
"""
Write a program which takes 2 digits, X,Y as input and generates a 2-dimensional array. The element value in the i-th row and j-th column of the array should be i*j.
Note: i=0,1.., X-1; j=0,1,¡­Y-1.
Example
Suppose the following inputs are given to the program:
3,5
Then, the output of the program should be:
[[0, 0, 0, 0, 0], [0, 1, 2, 3, 4], [0, 2, 4, 6, 8]]
"""
def array(x,y):
    li = []
    for i in range(x):
        li.append([])
        for j in range(y):
            li[i].append(0)

            li[i][j] = i*j

    return print(li)
array(3,5)

6.
"""
Write a program that accepts a comma separated sequence of words as input and prints the words in a comma-separated sequence after sorting them alphabetically.
Suppose the following input is supplied to the program:
without,hello,bag,world
Then, the output should be:
bag,hello,without,world
"""
def fun(word):
    li = [w for w in (word.split(','))]
    li.sort()
    # new = sorted(li,key=lambda i:i[0])
    return print(','.join(li))

fun('without,hello,bag,world')

7.
"""
Write a program that accepts sequence of lines as input and prints the lines after making all characters in the sentence capitalized.
Suppose the following input is supplied to the program:
Hello world
Practice makes perfect
Then, the output should be:
HELLO WORLD
PRACTICE MAKES PERFECT
"""
def fun():
    li = []
    while True:
        s = input()
        if s:
            li.append(s.upper())
            continue
        else:
            for i in li:
                print(i)
            break
fun()

8.
"""
Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a comma separated sequence.
Example:
0100,0011,1010,1001
Then the output should be:
1010
Notes: Assume the data is input by console.
"""
def fun(word):
    li = []
    for i in word.split(','):
        if int(i,base=2)%5==0:
            li.append(i)
    return print(','.join(li))

fun('0100,0011,1010,1001')

9.
"""
Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number.
The numbers obtained should be printed in a comma-separated sequence on a single line.
"""
def fun():
    li = []
    flag = 0
    for i in range(1000,3000):
        for j in list(str(i)):
            if int(j)%2 == 0:
                flag += 1
                if flag == 4:
                    li.append(i)
                    flag = 0
            else:
                flag = 0
    return print(li)
fun()

10.
"Write a program that accepts a sentence and calculate the number of letters and digits.
Suppose the following input is supplied to the program:
hello world! 123
Then, the output should be:
LETTERS 10
DIGITS 3""
"""
import re
def fun(word):
    alp = re.findall('[a-z,A-Z]',word)
    num = re.findall('[0-9]',word)
    return print('字母{}\n数字{}'.format(len(alp),len(num)))
fun('hello world! 123')