【leetcode】62.63 Unique Paths
62. Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?

Above is a 3 x 7 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
Tips:机器人从左上一直走到右下,(只能走右与下)直到走到FInish的位置。
package medium;
import java.util.Arrays;
public class L62UniquePaths {
public int uniquePaths(int m, int n) {
int[][] visited = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
visited[i][j] = -1;
System.out.println(i + "," + j + ">" + visited[i][j]);
}
}
int count = movingCount(m, n, 0, 0, visited);
return count;
}
public int movingCount(int m, int n, int row, int col, int[][] visited) {
int count = 0;
if (row < 0 || col < 0 || row >= m || col >= n)
return 0;
if (row == m - 1 && col == n - 1)
return 1;
if (visited[row][col] != -1)
return visited[row][col];
count = movingCount(m, n, row + 1, col, visited) + movingCount(m, n, row, col + 1, visited);
visited[row][col] = count;
return count;
}
//另外一种很快地方法。当前状态依赖于前一种状态
public int Solution2(int m, int n) {
int[] row = new int[n];
Arrays.fill(row,1);
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
row[j]+=row[j-1];
}
}
return row[n-1];
}
public static void main(String[] args) {
L62UniquePaths cc = new L62UniquePaths();
int count = cc.uniquePaths(3, 4);
System.out.println(count);
}
}
63. Unique Paths II
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
Note: m and n will be at most 100.
Tips:本题目是根据62题,稍作改变得来的,数组中1的位置不能走。
package medium;
public class L63UniquePaths2 {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
if (obstacleGrid == null)
return 0;
int m = obstacleGrid.length;
int n = obstacleGrid[0].length;
int[][] visited = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
visited[i][j] = -1;
System.out.println(i + "," + j + ">" + visited[i][j]);
}
}
int count = movingCount(m, n, 0, 0, visited, obstacleGrid);
return count;
}
public int movingCount(int m, int n, int row, int col, int[][] visited, int[][] obstacleGrid) {
int count = 0;
if (row < 0 || col < 0 || row >= m || col >= n)
return 0;
if (obstacleGrid[row][col] == 0) {
if (row == m - 1 && col == n - 1)
return 1;
if (visited[row][col] != -1)
return visited[row][col];
count = movingCount(m, n, row + 1, col, visited, obstacleGrid)
+ movingCount(m, n, row, col + 1, visited, obstacleGrid);
visited[row][col] = count;
}
return count;
}
public static void main(String[] args) {
L63UniquePaths2 l63 = new L63UniquePaths2();
int[][] obstacleGrid = { { 0, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 } };
int[][] aa = { { 1 } };
int count = l63.uniquePathsWithObstacles(aa);
System.out.println(count);
}
}
【leetcode】62.63 Unique Paths的更多相关文章
- <LeetCode OJ> 62. / 63. Unique Paths(I / II)
62. Unique Paths My Submissions Question Total Accepted: 75227 Total Submissions: 214539 Difficulty: ...
- 【LeetCode】62. Unique Paths 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/unique-pa ...
- 【LeetCode】62. Unique Paths
Unique Paths A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagra ...
- 【leetcode】62. Uniqe Paths
题目 https://oj.leetcode.com/problems/unique-paths/ A robot is located at the top-left corner of a m ...
- 【LeetCode】387. First Unique Character in a String
Difficulty:easy More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/first-unique-cha ...
- 62. 63. Unique Paths 64. Minimum Path Sum
1. A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- LeetCode(62)Unique Paths
题目 A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- leetcode@ [62/63] Unique Paths II
class Solution { public: int uniquePathsWithObstacles(vector<vector<int>>& obstacleG ...
- 【LeetCode】257. Binary Tree Paths 解题报告(java & python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 迭代 日期 题目地址:https://leet ...
随机推荐
- 二叉树 ADT接口 遍历算法 常规运算
BTree.h (结构定义, 基本操作, 遍历) #define MS 10 typedef struct BTreeNode{ char data; struct BTreeNode * lef ...
- 利用“海底捞算法”在MongoDB中优雅地存储一棵树
目前常见的树形结构数据库存储方案有以下四种,但是在处理无限深度.海量数据的树结构时,都存在一些问题: 1)Adjacency List(邻接表):每个节点仅记录父节点主键.优点是简单,缺点是访问子树需 ...
- 20155304 2016-2017-2 《Java程序设计》第八周学习总结
20155304 2016-2017-2 <Java程序设计>第八周学习总结 教材学习内容总结 NIO NIO使用频道来衔接数据节点,在处理数据时,NIO可以让你设定缓冲区容量,在缓冲区中 ...
- 20155336 《Java程序设计》实验二 (Java面向对象程序设计)实验报告
20155336 <Java程序设计>实验二 (Java面向对象程序设计)实验报告 实验内容 初步掌握单元测试和TDD 理解并掌握面向对象三要素:封装.继承.多态 初步掌握UML建模 熟悉 ...
- LOJ #2585. 「APIO2018」新家
#2585. 「APIO2018」新家 https://loj.ac/problem/2585 分析: 线段树+二分. 首先看怎样数颜色,正常的时候,离线扫一遍右端点,每次只记录最右边的点,然后查询左 ...
- 使用idea写ssm的时候提示源文件夹中的文件找不到
<context:property-placeholder location="classpath:db.properties"/>这一行idea提示找不到db.pro ...
- zepto 添加 animate组件
今天发现JQuery可以用 animate方法回到顶部,心想着zepto应该也可以 $('html,body').animate({ scrollTop: 0 }, 1000); 于是便用了一下,发现 ...
- phpcms v9如何给父级单页栏目添加内容
对于phpcms单页的调用相信大家都应该没问题,那么如果我们在后台添加的单页有二层甚至更多的时候,这样在管理内容上是没有给父级栏目添加内容这一功能的!那么我们该怎么实现这个功能并调用呢? 首先我们要修 ...
- windows下sublime text的node.js开发环境搭建
首先安装sublime text3,百度一堆,自己找吧.理论上sublime text2应该也可以.我只能说一句:这个软件实在是太强悍了. 跨平台,丰富的插件体系,加上插件基本上就是一个强悍的ide了 ...
- Action Required: Please provide your Tax Identity Information - Amazon Seller Tax Identity Collection
Hello ***, Your selling privileges have been suspended because we have not received required tax i ...