Alice thinks an integer x is a K-wolf number, if every K adjacent digits in decimal representation of x is pairwised different.
Given (L,R,K), please count how many K-wolf numbers in range of L,RL,R

.

Input

The input contains multiple test cases. There are about 10 test cases.

Each test case contains three integers L, R and K.

1≤L≤R≤1e18
2≤K≤52≤K≤5

Output

For each test case output a line contains an integer.

Sample Input

1 1 2
20 100 5

Sample Output

1
72

问有多少个数,任意连续k位都不相同

记一下前k-1位,有没有前导零

 #include<cstdio>
#include<iostream>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<cmath>
#include<queue>
#include<deque>
#include<set>
#include<map>
#include<ctime>
#define LL long long
#define inf 0x7ffffff
#define pa pair<int,int>
#define mkp(a,b) make_pair(a,b)
#define pi 3.1415926535897932384626433832795028841971
using namespace std;
inline LL read()
{
LL x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
LL n,len,l,r,k;
LL f[][][];
int zhan[];
int d[];
inline LL dfs(int now,int stat,int lead,int fp)
{
if (now==)return ;
if (!fp&&f[now][stat][lead]!=-)return f[now][stat][lead];
LL ans=,mx=fp?d[now-]:;
int lst=;
for(int i=now;i<=min(now+k-,len);i++)if (zhan[i]!=-)lst|=<<zhan[i];
for (int i=;i<=mx;i++)
{
if (lst&(<<i))continue;
if (i==&&lead&&now-!=)zhan[now-]=-;else zhan[now-]=i;
if (zhan[now-]!=-)lst|=(<<i);
ans+=dfs(now-,lst,lead&&i==&&now-!=,fp&&(i==d[now-]));
if (zhan[now-]!=-)lst-=(<<i);
}
if (!fp)f[now][stat][lead]=ans;
return ans;
}
inline LL calc(LL x)
{
if (!x)return ;
LL xxx=x;
len=;
while (xxx)
{
d[++len]=xxx%;
xxx/=;
}
LL sum=;
for (int i=;i<=d[len];i++)
{
if (i==&&len!=)zhan[len]=-;else zhan[len]=i;
if (zhan[len]!=-)sum+=dfs(len,<<zhan[len],zhan[len]==-,i==d[len]);
else sum+=dfs(len,,zhan[len]==-,i==d[len]);
zhan[len]=-;
}
return sum;
}
main()
{
while (~scanf("%lld%lld%lld",&l,&r,&k))
{
memset(f,-,sizeof(f));
printf("%lld\n",calc(r)-calc(l-));
}
}

hdu 5787

[暑假集训--数位dp]hdu5787 K-wolf Number的更多相关文章

  1. [暑假集训--数位dp]hdu3709 Balanced Number

    A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. ...

  2. [暑假集训--数位dp]LightOj1205 Palindromic Numbers

    A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the sam ...

  3. [暑假集训--数位dp]hdu3555 Bomb

    The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the ti ...

  4. [暑假集训--数位dp]hdu3652 B-number

    A wqb-number, or B-number for short, is a non-negative integer whose decimal form contains the sub- ...

  5. [暑假集训--数位dp]hdu2089 不要62

    杭州人称那些傻乎乎粘嗒嗒的人为62(音:laoer).杭州交通管理局经常会扩充一些的士车牌照,新近出来一个好消息,以后上牌照,不再含有不吉利的数字了,这样一来,就可以消除个别的士司机和乘客的心理障碍, ...

  6. [暑假集训--数位dp]hdu5898 odd-even number

    For a number,if the length of continuous odd digits is even and the length of continuous even digits ...

  7. [暑假集训--数位dp]LightOJ1140 How Many Zeroes?

    Jimmy writes down the decimal representations of all natural numbers between and including m and n, ...

  8. [暑假集训--数位dp]LightOj1032 Fast Bit Calculations

    A bit is a binary digit, taking a logical value of either 1 or 0 (also referred to as "true&quo ...

  9. [暑假集训--数位dp]cf55D Beautiful numbers

    Volodya is an odd boy and his taste is strange as well. It seems to him that a positive integer numb ...

随机推荐

  1. 如何将oracle查询的结果传输给变量

    如何将oracle查询的结果传输给变量 1. sqlplus查询时的变量设置 set echo off; #控制start命令不列出命令文件中的每一命令 set feedback off; #显示由查 ...

  2. 【Git版本控制】Git的merge合并分支命令

    1.实例 git checkout master git merge dev merge合并分支只对当前分支master产生影响,被合并的分支dev不受影响. 假设你有两个分支,“stable” 和 ...

  3. Linux常用文档操作命令--2

    4.文档压缩与解压操作 在Linux中常见的压缩文件有:*.tar.gz.*.tgz.*.gz.*.Z.*bz2等.其每种不同的压缩文件对印的压缩和解压命令也不同. *.tar.gz :tar程序打包 ...

  4. 16Shell脚本—计划任务服务程序

    计划任务服务程序 尽管我们现在已近有了功能彪悍的脚本程序来执行一些批处理工作,但是,如果仍然需要每天凌晨两点敲击键盘回车键来执行这个脚本程序,这简直太痛苦了.为此,我们需要学习如何设置服务器的计划任务 ...

  5. ccf 201712-4 行车路线(Python实现)

    一.原题 问题描述 试题编号: 201712-4 试题名称: 行车路线 时间限制: 1.0s 内存限制: 256.0MB 问题描述: 问题描述 小明和小芳出去乡村玩,小明负责开车,小芳来导航. 小芳将 ...

  6. paper:synthesizable finit state machine design techniques using the new systemverilog 3.0 enhancements之enhanced coding styles

    1.ANSI style 的代码比较紧凑. 下面规范推荐,比较好. 下面是带有parameter的module header的完整规范 一般1bit ,大家都是wire signal1 = gen_s ...

  7. python-闭包函数和装饰器

    目录 闭包函数 什么是闭包? 两种为函数传参的方式 使用参数的形式 包给函数 闭包函数的应用 闭包的意义: 装饰器 无参装饰器 什么是装饰器 为什么要用装饰器 怎么用装饰器 完善装饰器 闭包函数 什么 ...

  8. leetcode-14-basic-breadthFirstSearch

    BFS: breadth first search 107. Binary Tree Level Order Traversal II 解题思路: 本来我是用map<int,int>存所有 ...

  9. LeetCode(242)Valid Anagram

    题目 Given two strings s and t, write a function to determine if t is an anagram of s. For example, s ...

  10. poj3617 best cow line(贪心题)

    Best Cow Line Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32687   Accepted: 8660 De ...