[暑假集训--数位dp]hdu5787 K-wolf Number
Alice thinks an integer x is a K-wolf number, if every K adjacent digits in decimal representation of x is pairwised different.
Given (L,R,K), please count how many K-wolf numbers in range of L,RL,R
.
Input
The input contains multiple test cases. There are about 10 test cases.
Each test case contains three integers L, R and K.
1≤L≤R≤1e18
2≤K≤52≤K≤5
Output
For each test case output a line contains an integer.
Sample Input
1 1 2
20 100 5
Sample Output
1
72
问有多少个数,任意连续k位都不相同
记一下前k-1位,有没有前导零
#include<cstdio>
#include<iostream>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<cmath>
#include<queue>
#include<deque>
#include<set>
#include<map>
#include<ctime>
#define LL long long
#define inf 0x7ffffff
#define pa pair<int,int>
#define mkp(a,b) make_pair(a,b)
#define pi 3.1415926535897932384626433832795028841971
using namespace std;
inline LL read()
{
LL x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
LL n,len,l,r,k;
LL f[][][];
int zhan[];
int d[];
inline LL dfs(int now,int stat,int lead,int fp)
{
if (now==)return ;
if (!fp&&f[now][stat][lead]!=-)return f[now][stat][lead];
LL ans=,mx=fp?d[now-]:;
int lst=;
for(int i=now;i<=min(now+k-,len);i++)if (zhan[i]!=-)lst|=<<zhan[i];
for (int i=;i<=mx;i++)
{
if (lst&(<<i))continue;
if (i==&&lead&&now-!=)zhan[now-]=-;else zhan[now-]=i;
if (zhan[now-]!=-)lst|=(<<i);
ans+=dfs(now-,lst,lead&&i==&&now-!=,fp&&(i==d[now-]));
if (zhan[now-]!=-)lst-=(<<i);
}
if (!fp)f[now][stat][lead]=ans;
return ans;
}
inline LL calc(LL x)
{
if (!x)return ;
LL xxx=x;
len=;
while (xxx)
{
d[++len]=xxx%;
xxx/=;
}
LL sum=;
for (int i=;i<=d[len];i++)
{
if (i==&&len!=)zhan[len]=-;else zhan[len]=i;
if (zhan[len]!=-)sum+=dfs(len,<<zhan[len],zhan[len]==-,i==d[len]);
else sum+=dfs(len,,zhan[len]==-,i==d[len]);
zhan[len]=-;
}
return sum;
}
main()
{
while (~scanf("%lld%lld%lld",&l,&r,&k))
{
memset(f,-,sizeof(f));
printf("%lld\n",calc(r)-calc(l-));
}
}
hdu 5787
[暑假集训--数位dp]hdu5787 K-wolf Number的更多相关文章
- [暑假集训--数位dp]hdu3709 Balanced Number
A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. ...
- [暑假集训--数位dp]LightOj1205 Palindromic Numbers
A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the sam ...
- [暑假集训--数位dp]hdu3555 Bomb
The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the ti ...
- [暑假集训--数位dp]hdu3652 B-number
A wqb-number, or B-number for short, is a non-negative integer whose decimal form contains the sub- ...
- [暑假集训--数位dp]hdu2089 不要62
杭州人称那些傻乎乎粘嗒嗒的人为62(音:laoer).杭州交通管理局经常会扩充一些的士车牌照,新近出来一个好消息,以后上牌照,不再含有不吉利的数字了,这样一来,就可以消除个别的士司机和乘客的心理障碍, ...
- [暑假集训--数位dp]hdu5898 odd-even number
For a number,if the length of continuous odd digits is even and the length of continuous even digits ...
- [暑假集训--数位dp]LightOJ1140 How Many Zeroes?
Jimmy writes down the decimal representations of all natural numbers between and including m and n, ...
- [暑假集训--数位dp]LightOj1032 Fast Bit Calculations
A bit is a binary digit, taking a logical value of either 1 or 0 (also referred to as "true&quo ...
- [暑假集训--数位dp]cf55D Beautiful numbers
Volodya is an odd boy and his taste is strange as well. It seems to him that a positive integer numb ...
随机推荐
- SC || Chapter 8
栈:方法调用和局部变量的存储位置,保存基本类型 堆:在一块内存里分为多个小块,每块包含 一个对象,或者未被占用
- ASP.NET 验证控件报错:WebForms UnobtrusiveValidationMode 需要“jquery”ScriptResourceMapping。
在Visual Studio 2012中添加并使用验证控件时,可能会遇到如下的错误: WebForms UnobtrusiveValidationMode 需要“jquery”ScriptResour ...
- fei33423 工作 职场 格言
对老板: 1. 老板不知道你做的事情(目标设定) 2. 老板要的是规划(对上报告), 自己给自己设定 金字塔四位下的目标,各种维度.如何细化. 2.1 明确老板期望 2.2 与老板达成共识 2.3 ...
- Oracle 闪回 找回数据的实现方法
Oracle 闪回 找回数据的实现方法 闪回技术是Oracle强大数据库备份恢复机制的一部分,在数据库发生逻辑错误的时候,闪回技术能提供快速且最小损失的恢复.这篇文章主要介绍了Oracle 闪回 找回 ...
- C++ 学习笔记(三)string 类
在C语言中如果想要使用字符串那么有两种方法: 1.定义char型数组:char[10]; 然后将每个字符填充到对应的位置. 优点:这种方式将字符串放在内存所以每个位置都可以修改. 缺点:赋值比较麻烦, ...
- java解析多层嵌套json字符串
java分别解析下面两个json字符串 package jansonDemo; import com.alibaba.fastjson.JSON; import com.alibaba.fastjso ...
- NodeJS基础入门-Event
大多数Node.js核心API都采用惯用的异步事件驱动架构,其中某些类型的对象(触发器)会周期性地触发命名事件来调用函数对象(监听器). 例如,net.Server对象会在每次有新连接时触发事件;fs ...
- python入门:数字型和字符串换行要同类型 注意连接符
#!/usr/bin/env python # -*- coding: utf-8 -*- #数字型和字符串换行要同类型 注意连接符 a = 1 b = 2 print(str(a) + " ...
- usb hub 设备流程图
在此处负责而来:http://blog.csdn.net/xuelin273/article/details/38646851 下面的转载于:http://blog.csdn.net/qianguo ...
- HTTP认证之基本认证——Basic(一)
导航 HTTP认证之基本认证--Basic(一) HTTP认证之基本认证--Basic(二) HTTP认证之摘要认证--Digest(一) HTTP认证之摘要认证--Digest(二) 一.概述 Ba ...