Segment Tree Range Minimum Query.
int rangeMinQuery(int segTree[], int qlow, int qhigh, int low, int high, int pos) {
if (qlow <= low && qhigh >= high)
return segTree[pos];
if (qlow > high || qhigh < low)
return maxVal;
int mid = (low + high) / 2;
return min(rangeMinQuery(segTree, qlow, qhigh, low, mid, 2*pos+1),
rangeMinQuery(segTree, qlow, qhigh, mid+1, high, 2*pos+2));
}
void constructTree(int input[], int segTree[], int low, int high, int pos) {
if (low == high) {
segTree[pos] = input[low];
return;
}
int mid = (low + high) / 2;
constructTree(input, segTree, low, mid, 2*pos+1);
constructTree(input, segTree, mid+1, high, 2*pos+2);
segTree[pos] = min(segTree[2*pos+1], segTree[2*pos+2]);
}
Segment Tree Range Minimum Query.的更多相关文章
- Range Minimum Query and Lowest Common Ancestor
作者:danielp 出处:http://community.topcoder.com/tc?module=Static&d1=tutorials&d2=lowestCommonAnc ...
- AOJ DSL_2_A Range Minimum Query (RMQ)
Range Minimum Query (RMQ) Write a program which manipulates a sequence A = {a0,a1,...,an−1} with the ...
- Geeks - Range Minimum Query RMQ范围最小值查询
使用线段树预处理.能够使得查询RMQ时间效率在O(lgn). 线段树是记录某范围内的最小值. 标准的线段树应用. Geeks上仅仅有两道线段树的题目了.并且没有讲到pushUp和pushDown操作. ...
- RMQ(Range Minimum Query)问题(转)
问题描述 RMQ问题是求给定区间中的最值问题.对于长度为n的数列A,回答若干查询RMQ(A, i, j).返回数组A中下标在[i,j]里的最小值的下标. 比如数列 5,8,1,3,6,4,9,5,7 ...
- Leetcode: Range Sum Query - Mutable && Summary: Segment Tree
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive ...
- Leetcode: Range Sum Query 2D - Mutable && Summary: Binary Indexed Tree
Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper lef ...
- Segment Tree Query I & II
Segment Tree Query I For an integer array (index from 0 to n-1, where n is the size of this array), ...
- Lintcode: Segment Tree Query II
For an array, we can build a SegmentTree for it, each node stores an extra attribute count to denote ...
- Lintcode: Segment Tree Query
For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding ...
随机推荐
- 【题解】Painting Fence
[题解]Painting Fence 分治模板.贪心加分治.直接\(O(n^2logn)\)分治过去.考虑一块联通的柱形是子问题的,是递归的,贪心分治就可.记得对\(r-l+1\)取\(min\). ...
- 列举你了解的Python较其他语言的优势
1.简单易学 2.开发速度快 3.拥有最成熟的程序包资源库(第三方库)
- Unity中几种简单的相机跟随
#unity中相机追随 固定相机跟随,这种相机有一个参考对象,它会保持与该参考对象固定的位置,跟随改参考对象发生移动 using UnityEngine; using System.Collectio ...
- 【转】Unicode(UTF-8, UTF-16)令人混淆的概念
参考地址:http://www.cnblogs.com/kingcat/archive/2012/10/16/2726334.html Java中,char类型用UTF-16编码描述一个代码单元 为啥 ...
- Java多线程系列 基础篇07 synchronized底层优化
转载 http://www.cnblogs.com/paddix/ 作者:liuxiaopeng http://www.infoq.com/cn/articles/java-se-16-synchro ...
- SVG圆盘时钟动画
在线演示 本地下载
- Linux学习之路(二)文件处理命令之下
分区格式化: 一块分区想要使用的话,要格式化.格式化主要有两个工作,1,把分区分成等大小的数据块,每个数据块一般为4KB.2在分区之前建一个分区表,给第一个文件建一行相关数据,在分区表里保存了它的io ...
- python基础-大杂烩
random()随机函数 import random print(random.choice('abcdefghij')) #随机取这些字母 print(random.choice(['apple', ...
- HttpClient_02_实现https协议
二.参考文档 1.Java 和 HTTP 的那些事(四) HTTPS 和 证书 1. 轻松把玩HttpClient之配置ssl,采用设置信任自签名证书实现https 2.如何使用HttpClient来 ...
- 【坑坑坑坑坑】fwrite没有把数据写到文件中???
原文:https://blog.csdn.net/kuaidfkuai/article/details/45918025 <unix环境高级编程>中介绍标准IO: 标准IO流操作读写普通文 ...