HDU 1015.Safecracker【暴力枚举】【8月17】
Safecracker
"The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein's secrets and
wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters,
usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing
the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, ..., Z=26). The combination is then
vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary."
v - w^2 + x^3 - y^4 + z^5 = target
"For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode
the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn't exist then."
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
"Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then
at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or 'no solution'
if there is no correct combination. Use the exact format shown below."
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
LKEBA
YOXUZ
GHOST
no solution
A=1,B=2········Z=26.给定target。从已知字符中找出5个字符使v - w^2 + x^3 - y^4 + z^5 = target 成立。多组解输出字典序最大的。
暴力枚举,没想到能够过。5层循环:
#include<cstdio>
#include<cstring>
int f[30],target;
int main(){
char s[30];
while(scanf("%d%s",&target,s)!=EOF&&target){
memset(f,0,sizeof(f));
if(strlen(s)<5){
printf("no solution");
break;
}
bool key=false;
for(int i=0;i<strlen(s);i++)
f[s[i]-'@']=1;
for(int a=26;a>0&&!key;a--)
for(int b=26;b>0&&!key;b--){
if(b!=a)
for(int c=26;c>0&&!key;c--){
if(c!=b&&c!=a)
for(int d=26;d>0&&!key;d--){
if(d!=c&&d!=b&&d!=a)
for(int e=26;e>0&&!key;e--){
if(e!=d&&e!=c&&e!=b&&e!=a)
if(f[a]&&f[b]&&f[c]&&f[d]&&f[e])
if(a-b*b+c*c*c-d*d*d*d+e*e*e*e*e==target){
key=true;
printf("%c%c%c%c%c\n",(char)a+64,(char)b+64,(char)c+64,(char)d+64,(char)e+64);
}
}
}
}
}
if(!key) printf("no solution\n");
}
return 0;
}
HDU 1015.Safecracker【暴力枚举】【8月17】的更多相关文章
- HDOJ(HDU).1015 Safecracker (DFS)
HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1 ...
- hdu1015 Safecracker (暴力枚举)
http://acm.hdu.edu.cn/showproblem.php?pid=1015 Safecracker Time Limit: 2000/1000 MS (Java/Others) ...
- hdu 1015 Safecracker 水题一枚
题目链接:HDU - 1015 === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Klein s ...
- BestCoder Round #50 (div.1) 1002 Run (HDU OJ 5365) 暴力枚举+正多边形判定
题目:Click here 题意:给你n个点,有多少个正多边形(3,4,5,6). 分析:整点是不能构成正五边形和正三边形和正六边形的,所以只需暴力枚举四个点判断是否是正四边形即可. #include ...
- HDOJ/HDU 1015 Safecracker(枚举、暴力)
Problem Description === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Kle ...
- ZOJ 1403&&HDU 1015 Safecracker【暴力】
Safecracker Time Limit: 2 Seconds Memory Limit: 65536 KB === Op tech briefing, 2002/11/02 06:42 ...
- HDU 4462(暴力枚举)
因为题目当中的k比较小k <= 10,所以可以直接枚举,题目里面由两个trick, 一个是如果每个点都可以放稻草人的话,那么答案是0, 另外一个就是如果可以放稻草人的点不用被照到.知道了这两个基 ...
- HDOJ/HDU 1015 Safecracker(深搜)
Problem Description === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Kle ...
- HDU 1015 Safecracker 解决问题的方法
Problem Description === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Kl ...
随机推荐
- NSLayoutConstraint的使用
*一切皆代码*- -- #继承关系框架|类|类:-:|:-:|:-:UIKit|NSLayoutConstraint|--|-|- #应用场景UI界面的搭建一般会占用项目开发相当一部分的时间.涉及到控 ...
- 第4章 部署模式 Three-Tiered Distribution(三级分布)
影响因素 Tiered Distribution 中讨论的影响因素也适用于此模式.有关这些通用影响因素的讨论,请参阅"Tiered Distribution".下列影响因素仅适用于 ...
- Codeforces Round #448
Pizza Serparation #include<stdio.h> #include<string.h> #include<stdlib.h> #include ...
- for循环和数组的应用
<html> <head> <meta charset="utf-8"> <title>无标题文档</title> &l ...
- (转载) android studio library生成jar包和aar的方法总结
android studio library生成jar包和aar的方法总结 标签: android学习文档jar和aar的使用与生成gradle 2016-11-25 10:39 1782人阅读 评论 ...
- 【Oracle】审计
1.审计的功能:监控用户在database 的 action (操作) 2.审计分类: 1) session :在同一个session,相同的语句只产生一个审计结果(默认) 2) access : 在 ...
- RAP开发入门-布局管理
布局类继承关系 FillLayout new FillLayout(SWT.VERTICAL/HORIZONTAL)设置竖直/水平填充 RowLayout wrap折行显示.pack自适应布局(布局 ...
- ACM___数学___九的余数
九的余数 时间限制:3000 ms | 内存限制:65535 KB 难度:3 描述 现在给你一个自然数n,它的位数小于等于一百万,现在你要做的就是求出这个数整除九之后的余 ...
- 应用一:Vue之开发环境搭建
简单分享下vue项目的开发环境搭建流程~ 1.安装nodeJS vue的运行是要依赖于node的npm的管理工具来实现,下载地址:https://nodejs.org/en/.安装完成之后以管理员身份 ...
- Python中生成器,迭代器,以及一些常用的内置函数.
知识点总结 生成器 生成器的本质就是迭代器. 迭代器:Python中提供的已经写好的工具或者通过数据转化得来的. 生成器:需要我们自己用Python代码构建的 创建生成器的三种方法: 通过生成器函数 ...