http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.4.6927

The problems of finding a longest common subsequence of two sequences A and B and a shortest edit script for transforming A into B have long been known to be dual problems. In this paper, they are shown to be equivalent to finding a shortest/longest path in an edit graph. Using this perspective, a simple O(ND) time and space algorithm is developed where N is the sum of the lengths of A and B and D is the size of the minimum edit script for A and B. The algorithm performs well when differences are small (sequences are similar) and is consequently fast in typical applications. The algorithm is shown to have O(N +D expected-time performance under a basic stochastic model. A refinement of the algorithm requires only O(N) space, and the use of suffix trees leads to an O(NlgN +D ) time variation.

Myers1986AnONDDifferenceAlgorithm.pdf http://se-pubs.dbs.uni-leipzig.de/files/Myers1986AnONDDifferenceAlgorithm.pdf

An O(ND) Difference Algorithm and Its Variations∗ EUGENE W. MYERS Department of Computer Science, University of Arizona, Tucson, AZ 85721, U.S.A. ABSTRACT The problems of finding a longest common subsequence of two sequences A and B and a shortest edit script for transforming A into B have long been known to be dual problems. In this paper, they are shown to be equivalent to finding a shortest/longest path in an edit graph. Using this perspective, a simple O(ND) time and space algorithm is developed where N is the sum of the lengths of A and B and D is the size of the minimum edit script for A and B. The algorithm performs well when differences are small (sequences are similar) and is consequently fast in typical applications. The algorithm is shown to have O(N + D 2 ) expected-time performance under a basic stochastic model. A refinement of the algorithm requires only O(N) space, and the use of suffix trees leads to an O(NlgN + D 2 ) time variation.

An O(ND) Difference Algorithm and Its Variations (1986)的更多相关文章

  1. Falcon Genome Assembly Tool Kit Manual

    Falcon Falcon: a set of tools for fast aligning long reads for consensus and assembly The Falcon too ...

  2. 动态规划处理diff算法 Myers Diff (正向)

    Eugene W. Myers 在他1986年发表于"Algorithmica"的论文"An O(ND) Difference Algorithm and Its Var ...

  3. 【原创】Google的文本内容对比代码

    /* * Diff Match and Patch * * Copyright 2006 Google Inc. * http://code.google.com/p/google-diff-matc ...

  4. Myers差分算法的理解、实现、可视化

    作者:Oto_G QQ: 421739728 目录 简介 基础 差异的描述 好的差异比较 算法介绍 名词解释 两个定理 绘制编辑图 感谢 简介 本文章对Myers差分算法(Myers Diff Alg ...

  5. Android DiffUtil

    Android 的recyclerview-v7:24.2.0 发布后多了个DiffUtil工具类,这个工具类能够大大解放了Android开发者的一个苦恼:RecyclerView局部刷新和重新刷新时 ...

  6. linux timing profile

    double getUnixTime(void) { struct timespec tv; ) ; return (((double) tv.tv_sec) + (double) (tv.tv_ns ...

  7. 【翻译】理解 LSTM 及其图示

    目录 理解 LSTM 及其图示 本文翻译自 Shi Yan 的博文 Understanding LSTM and its diagrams,原文阐释了作者对 Christopher Olah 博文 U ...

  8. Leetcode 446.等差数列划分II 子序列

    等差数列划分II 子序列 如果一个数列至少有三个元素,并且任意两个相邻元素之差相同,则称该数列为等差数列. 例如,以下数列为等差数列: 1, 3, 5, 7, 9 7, 7, 7, 7 3, -1, ...

  9. Code Project精彩系列(转)

    Code Project精彩系列(转)   Code Project精彩系列(转)   Applications Crafting a C# forms Editor From scratch htt ...

随机推荐

  1. PTA 07-图6 旅游规划 (25分)

    题目地址 https://pta.patest.cn/pta/test/15/exam/4/question/717 5-9 旅游规划   (25分) 有了一张自驾旅游路线图,你会知道城市间的高速公路 ...

  2. iossharesdk微信登录出错

    只用下面的初始化就行了 //    //添加微信应用 注册网址 http://open.weixin.qq.com //    [ShareSDK connectWeChatWithAppId:mod ...

  3. P2389 电脑班的裁员 (动态规划)

    题目背景 隔壁的新初一电脑班刚考过一场试,又到了BlingBling的裁员时间,老师把这项工作交给了ZZY来进行.而ZZY最近忙着刷题,就把这重要的任务交(tui)给了你. 题目描述 ZZY有独特的裁 ...

  4. BS4(BeautifulSoup4)的使用--find_all()篇

    可以直接参考 BS4文档:https://www.crummy.com/software/BeautifulSoup/bs4/doc/index.zh.html#find-all 注意的是: 1.有些 ...

  5. css样式---隐藏元素

    1.通过设置width:0;或height:0 2.将元素的opacity设置成0 3.通过定位将元素移出屏幕范围 4.通过text-indent实现隐藏文字的效果 5.通过z-index隐藏一个元素 ...

  6. Java的常用对象

    PO:持久对象 (persistent object),po(persistent object)就是在Object/Relation Mapping框架中的Entity,po的每个属性基本上都对应数 ...

  7. 洛谷——P1290 欧几里德的游戏

    P1290 欧几里德的游戏 题目描述 欧几里德的两个后代Stan和Ollie正在玩一种数字游戏,这个游戏是他们的祖先欧几里德发明的.给定两个正整数M和N,从Stan开始,从其中较大的一个数,减去较小的 ...

  8. 局域网Cesium离线影像及瓦片影像地图加载

    1.Cesium简介 优点: cesium展示地图数据效果比较好,解析2D地图各种不同服务类型的数据源,比如百度地图.天地图.arcgis地图.BingMap.openStreetMap.MapBox ...

  9. 使用JavaScript进行进制转换将字符串转换为十进制

    JS 是一个很神奇的语言,内制的的很多函数可以帮我们进行数(进)制转换: JS中可以直接使用16进制: var a = 将任意进制字符串转换为十进制,如二进制,八进制,十六进制, 第二数数不写即为最常 ...

  10. Our happy ending

    题目链接 题意: 输入n.k.L,n个数,最大值不超过L,在序列中取若干个数和能达到k的序列个数 n,k<=20 , 0<=L<=10^9 分析: 题目关键在于和k比較小,所以能够考 ...