CodeForces - 43B Letter

字符串的处理

统计已有字符的个数 和需求字符比较

 #include <iostream>
 #include <stdio.h>
 #include <string.h>

 using namespace std;

 int head[];
 int text[];
 char input[];
 int main()
 {
     freopen("in.txt", "r", stdin);
     gets(input);
     for (int i = ; i < strlen(input); i++)
     {
         if (input[i] >= 'a' && input[i] <= 'z')
         {
             head[input[i] - 'a']++;
         }
         else if ( input[i] >= 'A' && input[i] <= 'Z' )
         {
             head[input[i] - 'A'+]++;
         }
     }
     gets(input);
     for (int i = ; i < strlen(input); i++)
     {
         if (input[i] >= 'a' && input[i] <= 'z')
         {
             text[input[i] - 'a']++;
         }
         else if ( input[i] >= 'A' && input[i] <= 'Z' )
         {
             text[input[i] - 'A'+]++;
         }
     }
     bool judge = true;
     for (int i = ; i < ; i++)
     {
         if (text[i] > head[i] )
         {
             judge = false;
             break;
         }
     }
     if (judge) printf("YES\n");
     else printf("NO\n");
 }