Scalaz（14）－ Monad：函数组合－Kleisli to Reader

Monad Reader就是一种函数的组合。在scalaz里函数（function）本身就是Monad，自然也就是Functor和applicative。我们可以用Monadic方法进行函数组合：

 import scalaz._
 import Scalaz._
 object decompose {
 //两个测试函数
 val f = (_: Int) +                               //> f  : Int => Int = <function1>
 val g = (_: Int) *                               //> g  : Int => Int = <function1>
 //functor
 val h = f map g  // f andThen g                   //> h  : Int => Int = <function1>
 val h1 = g map f  // f compose g                  //> h1  : Int => Int = <function1>
 h()  //g(f(2))                                   //> res0: Int = 25
 h1() //f(g(2))                                   //> res1: Int = 13
 //applicative
 val k = (f |@| g){_ + _}                          //> k  : Int => Int = <function1>
 k() // f(10)+g(10)                              //> res2: Int = 63
 //monad
 val m = g.flatMap{a => f.map(b => a+b)}           //> m  : Int => Int = <function1>
 val n = for {
   a <- f
   b <- g
 } yield a + b                                     //> n  : Int => Int = <function1>
 m()                                             //> res3: Int = 63
 n()                                             //> res4: Int = 63
 }

以上的函数f,g必须满足一定的条件才能实现组合。这个从f(g(2))或g(f(2))可以看出：必需固定有一个输入参数及输入参数类型和函数结果类型必需一致，因为一个函数的输出成为另一个函数的输入。在FP里这样的函数组合就是Monadic Reader。

但是FP里函数运算结果一般都是M[R]这样格式的，所以我们需要对f:A => M[B],g:B => M[C]这样的函数进行组合。这就是scalaz里的Kleisli了。Kleisli就是函数A=>M[B]的类封套，从Kleisli的类定义可以看出：scalaz/Kleisli.scala

 final case class Kleisli[M[_], A, B](run: A => M[B]) { self =>
 ...
 trait KleisliFunctions {
   /**Construct a Kleisli from a Function1 */
   def kleisli[M[_], A, B](f: A => M[B]): Kleisli[M, A, B] = Kleisli(f)
 ...

Kleisli的目的是把Monadic函数组合起来或者更形象说连接起来。Kleisli提供的操作方法如>=>可以这样理解：

(A=>M[B]) >=> (B=>M[C]) >=> (C=>M[D]) 最终运算结果M[D]

可以看出Kleisli函数组合有着固定的模式：

1、函数必需是 A => M[B]这种模式；只有一个输入，结果是一个Monad M[_]

2、上一个函数输出M[B]，他的运算值B就是下一个函数的输入。这就要求下一个函数的输入参数类型必需是B

3、M必须是个Monad；这个可以从Kleisli的操作函数实现中看出：scalaz/Kleisli.scala

   /** alias for `andThen` */
   def >=>[C](k: Kleisli[M, B, C])(implicit b: Bind[M]): Kleisli[M, A, C] =  kleisli((a: A) => b.bind(this(a))(k.run))

   def andThen[C](k: Kleisli[M, B, C])(implicit b: Bind[M]): Kleisli[M, A, C] = this >=> k

   def >==>[C](k: B => M[C])(implicit b: Bind[M]): Kleisli[M, A, C] = this >=> kleisli(k)

   def andThenK[C](k: B => M[C])(implicit b: Bind[M]): Kleisli[M, A, C] = this >==> k

   /** alias for `compose` */
   def <=<[C](k: Kleisli[M, C, A])(implicit b: Bind[M]): Kleisli[M, C, B] = k >=> this

   def compose[C](k: Kleisli[M, C, A])(implicit b: Bind[M]): Kleisli[M, C, B] = k >=> this

   def <==<[C](k: C => M[A])(implicit b: Bind[M]): Kleisli[M, C, B] = kleisli(k) >=> this

   def composeK[C](k: C => M[A])(implicit b: Bind[M]): Kleisli[M, C, B] = this <==< k

拿操作函数>=>（andThen）举例：implicit b: Bind[M]明确了M必须是个Monad。

kleisli((a: A) => b.bind(this(a))(k.run))的意思是先运算M[A]，接着再运算k，以M[A]运算结果值a作为下一个函数k.run的输入参数。整个实现过程并不复杂。

实际上Reader就是Kleisli的一个特殊案例：在这里kleisli的M[]变成了Id[]，因为Id[A]=A >>> A=>Id[B] = A=>B，就是我们上面提到的Reader，我们看看Reader在scalaz里是如何定义的：scalar/package.scala

   type ReaderT[F[_], E, A] = Kleisli[F, E, A]
   val ReaderT = Kleisli
   type =?>[E, A] = Kleisli[Option, E, A]
   type Reader[E, A] = ReaderT[Id, E, A]

   type Writer[W, A] = WriterT[Id, W, A]
   type Unwriter[W, A] = UnwriterT[Id, W, A]

   object Reader {
     def apply[E, A](f: E => A): Reader[E, A] = Kleisli[Id, E, A](f)
   }

   object Writer {
     def apply[W, A](w: W, a: A): WriterT[Id, W, A] = WriterT[Id, W, A]((w, a))
   }

   object Unwriter {
     def apply[U, A](u: U, a: A): UnwriterT[Id, U, A] = UnwriterT[Id, U, A]((u, a))
   }

type ReaderT[F[_], E, A] = Kleisli[F, E, A] >>> type Reader[E,A] = ReaderT[Id,E,A]

好了，说了半天还是回到如何使用Kleisli进行函数组合的吧：

 //Kleisli款式函数kf,kg
 val kf: Int => Option[String] = (i: Int) => Some((i + ).shows)
                                                   //> kf  : Int => Option[String] = <function1>
 val kg: String => Option[Boolean] = { case "" => true.some; case _ => false.some }
                                                   //> kg  : String => Option[Boolean] = <function1>
 //Kleisli函数组合操作
 import Kleisli._
 val kfg = kleisli(kf) >=> kleisli(kg)             //> kfg  : scalaz.Kleisli[Option,Int,Boolean] = Kleisli(<function1>)
 kfg()                                            //> res5: Option[Boolean] = Some(false)
 kfg()                                            //> res6: Option[Boolean] = Some(true)

例子虽然很简单，但它说明了很多重点：上一个函数输入的运算值是下一个函数的输入值 Int=>String=>Boolean。输出Monad一致统一，都是Option。

那么，Kleisli到底用来干什么呢？它恰恰显示了FP函数组合的真正意义：把功能尽量细分化，通过各种方式的函数组合实现灵活的函数重复利用。也就是在FP领域里，我们用Kleisli来组合FP函数。

下面我们就用scalaz自带的例子scalaz.example里的KleisliUsage.scala来说明一下Kleisli的具体使用方法吧：

下面是一组地理信息结构：

   // just some trivial data structure ,
   // Continents contain countries. Countries contain cities.
   case class Continent(name: String, countries: List[Country] = List.empty)
   case class Country(name: String, cities: List[City] = List.empty)
   case class City(name: String, isCapital: Boolean = false, inhabitants: Int = )

分别是：洲（Continent）、国家（Country）、城市（City）。它们之间的关系是层级的：Continent(Country(City))

下面是一组模拟数据：

  val data: List[Continent] = List(
     Continent("Europe"),
     Continent("America",
       List(
         Country("USA",
           List(
             City("Washington"), City("New York"))))),
     Continent("Asia",
       List(
         Country("India",
           List(City("New Dehli"), City("Calcutta"))))))

从上面的模拟数据也可以看出Continent,Country,City之间的隶属关系。我们下面设计三个函数分别对Continent,Country,City进行查找：

   def continents(name: String): List[Continent] =
     data.filter(k => k.name.contains(name))       //> continents: (name: String)List[Exercises.kli.Continent]
   //查找名字包含A的continent
   continents("A")                                 //> res7: List[Exercises.kli.Continent] = List(Continent(America,List(Country(U
                                                   //| SA,List(City(Washington,false,20), City(New York,false,20))))), Continent(A
                                                   //| sia,List(Country(India,List(City(New Dehli,false,20), City(Calcutta,false,2
                                                   //| 0))))))
   //找到两个：List(America,Asia)
   def countries(continent: Continent): List[Country] = continent.countries
                                                   //> countries: (continent: Exercises.kli.Continent)List[Exercises.kli.Country]
   //查找America下的国家
   val america =
       Continent("America",
       List(
         Country("USA",
           List(
             City("Washington"), City("New York")))))
                                                   //> america  : Exercises.kli.Continent = Continent(America,List(Country(USA,Lis
                                                   //| t(City(Washington,false,20), City(New York,false,20)))))
   countries(america)                              //> res8: List[Exercises.kli.Country] = List(Country(USA,List(City(Washington,f
                                                   //| alse,20), City(New York,false,20))))
   def cities(country: Country): List[City] = country.cities
                                                   //> cities: (country: Exercises.kli.Country)List[Exercises.kli.City]
   val usa = Country("USA",
             List(
               City("Washington"), City("New York")))
                                                   //> usa  : Exercises.kli.Country = Country(USA,List(City(Washington,false,20),
                                                   //| City(New York,false,20)))
   cities(usa)                                     //> res9: List[Exercises.kli.City] = List(City(Washington,false,20), City(New Y
                                                   //| ork,false,20))

从continents,countries,cities这三个函数运算结果可以看出它们都可以独立运算。这三个函数的款式如下：

String => List[Continent]

Continent => List[Country]

Country => List[City]

无论函数款式或者类封套（List本来就是Monad）都适合Kleisli。我们可以用Kleisli把这三个局部函数用各种方法组合起来实现更广泛功能：

   val allCountry = kleisli(continents) >==> countries
                                                   //> allCountry  : scalaz.Kleisli[List,String,Exercises.kli.Country] = Kleisli(<
                                                   //| function1>)
   val allCity = kleisli(continents) >==> countries >==> cities
                                                   //> allCity  : scalaz.Kleisli[List,String,Exercises.kli.City] = Kleisli(<functi
                                                   //| on1>)
   allCountry("Amer")                              //> res10: List[Exercises.kli.Country] = List(Country(USA,List(City(Washington,
                                                   //| false,20), City(New York,false,20))))
   allCity("Amer")                                 //> res11: List[Exercises.kli.City] = List(City(Washington,false,20), City(New
                                                   //| York,false,20))

还有个=<<符号挺有意思：

   def =<<(a: M[A])(implicit m: Bind[M]): M[B] = m.bind(a)(run)

意思是用包嵌的函数flatMap一下输入参数M[A]：

   allCity =<< List("Amer","Asia")                 //> res12: List[Exercises.kli.City] = List(City(Washington,false,20), City(New
                                                   //| York,false,20), City(New Dehli,false,20), City(Calcutta,false,20))

那么如果我想避免使用List()，用Option［List]作为函数输出可以吗？Option是个Monad，第一步可以通过。下一步是把函数款式对齐了：

List[String] => Option[List[Continent]]

List[Continent] => Option[List[Country]]

List[Country] => Option[List[City]]

下面是这三个函数的升级版：

   //查找Continent List[String] => Option[List[Continent]]
   def maybeContinents(names: List[String]): Option[List[Continent]] =
     names.flatMap(name => data.filter(k => k.name.contains(name))) match {
        case h :: t => (h :: t).some
        case _ => none
     }                                             //> maybeContinents: (names: List[String])Option[List[Exercises.kli.Continent]]
                                                   //|
   //测试运行
   maybeContinents(List("Amer","Asia"))            //> res13: Option[List[Exercises.kli.Continent]] = Some(List(Continent(America,
                                                   //| List(Country(USA,List(City(Washington,false,20), City(New York,false,20))))
                                                   //| ), Continent(Asia,List(Country(India,List(City(New Dehli,false,20), City(Ca
                                                   //| lcutta,false,20)))))))
   //查找Country  List[Continent] => Option[List[Country]]
   def maybeCountries(continents: List[Continent]): Option[List[Country]] =
     continents.flatMap(continent => continent.countries.map(c => c)) match {
        case h :: t => (h :: t).some
        case _ => none
     }                                             //> maybeCountries: (continents: List[Exercises.kli.Continent])Option[List[Exer
                                                   //| cises.kli.Country]]
    //查找City  List[Country] => Option[List[Country]]
   def maybeCities(countries: List[Country]): Option[List[City]] =
     countries.flatMap(country => country.cities.map(c => c)) match {
        case h :: t => (h :: t).some
        case _ => none
     }                                             //> maybeCities: (countries: List[Exercises.kli.Country])Option[List[Exercises.
                                                   //| kli.City]]

   val maybeAllCities = kleisli(maybeContinents) >==> maybeCountries >==> maybeCities
                                                   //> maybeAllCities  : scalaz.Kleisli[Option,List[String],List[Exercises.kli.Cit
                                                   //| y]] = Kleisli(<function1>)
   maybeAllCities(List("Amer","Asia"))             //> res14: Option[List[Exercises.kli.City]] = Some(List(City(Washington,false,2
                                                   //| 0), City(New York,false,20), City(New Dehli,false,20), City(Calcutta,false,
                                                   //| 20)))

我们看到，只要Monad一致，函数输入输出类型匹配，就能用Kleisli来实现函数组合。